Trigonometry, 2ADV T3 SM-Bank 8 MC The diagram below shows one cycle of a circular function. The amplitude and period of this function are respectively `3\ \ text(and)\ \ 2 ` `3\ \ text(and)\ \ (pi)/(2)` `4\ \ text(and)\ \ (pi)/(4)` `3\ \ text(and)\ \ 4` Show Answers Only `D` Show Worked Solution `text(Graph centres around)\ \ y = 1` `text(Amplitude) \ = 3` `text(Period:) = 4` `=> D`
Trigonometry, 2ADV T3 SM-Bank 7 MC The graph shown could have equation `y = 2cos(x + pi/6) + 1` `y = 2cos4(x - pi/6) + 1` `y = 4sin2(x - pi/12) - 1` `y = 3cos(2x + pi/6) - 1` Show Answers Only `=> B` Show Worked Solution `text{Amplitude = 2 (range from – 1 to 3)}` `text{Graph centre line (median):}\ \ y= 1` `:.\ text(Eliminate)\ \ C\ \ text(and)\ \ D.` `text(Period) = (2pi)/3 – pi/6 = pi/2\ \ text{(from graph)}` `text(Consider option)\ B,` `text(Period)= (2pi)/n= (2pi)/4 = pi/2` `=> B`