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Calculus, EXT1 EQ-Bank 28

\(P(x)\) is a polynomial where  \(P(\alpha)=0\)  and  \(P^{\prime}(\alpha)=0\).

  1. Show that \((x-\alpha)^2\) is a factor of \(P(x)\).   (2 marks)

    --- 7 WORK AREA LINES (style=lined) ---

  2. The curve  \(y=x^3+b x^2+c x+4\)  is tangent to the \(x\)-axis at  \(x=-1\). Find the values of \(b\) and \(c\).   (3 marks)

    --- 12 WORK AREA LINES (style=lined) ---

Show Answers Only

a.    \(P(\alpha)=0\ \ \Rightarrow\ \ (x-a)\ \text{is a factor of \(P(x)\)}\)

\(P(x)=(x-\alpha) \cdot Q(x)\)
 

\(P^{\prime}(x)=Q(x)+(x-a) \cdot Q(x)\)

\(\text{Since}\ \ P^{\prime}(\alpha)=0:\)

\(Q(\alpha)=0 \ \ \Rightarrow\ \ (x-\alpha) \ \text{is a factor of} \ \ Q(\alpha)\)
 

\(\text{Let} \ \ Q(x)=(x-\alpha) \cdot R(x)\)

\(P(x)=(x-\alpha)^2 \cdot R(x)\)

\(\therefore \ (x-\alpha)^2 \ \text{is a factor of} \ P(x).\)
 

b.    \(b=6, c=9\)

Show Worked Solution

a.    \(P(\alpha)=0\ \ \Rightarrow\ \ (x-a)\ \text{is a factor of \(P(x)\)}\)

\(P(x)=(x-\alpha) \cdot Q(x)\)
 

\(P^{\prime}(x)=Q(x)+(x-a) \cdot Q(x)\)

\(\text{Since}\ \ P^{\prime}(\alpha)=0:\)

\(Q(\alpha)=0 \ \ \Rightarrow\ \ (x-\alpha) \ \text{is a factor of} \ \ Q(\alpha)\)
 

\(\text{Let} \ \ Q(x)=(x-\alpha) \cdot R(x)\)

\(P(x)=(x-\alpha)^2 \cdot R(x)\)

\(\therefore \ (x-\alpha)^2 \ \text{is a factor of} \ P(x).\)
 

b.    \(\text{Since the curve is tangent at} \ \ x=-1\)

\(x=-1 \ \ \text{is a double root}\)

\(P(x)=x^3+b x^2+c x+4\)

\(P(-1)=-1+b-c+4=0 \ \ \Rightarrow\ \ b-c=-3\ \ldots\ (1)\)
 

\(P^{\prime}(x)=3 x^2+26 x+c\)

\(P^{\prime}(-1)=3-2 b+c=0 \ \ \Rightarrow\ \ -2 b+c=-3\ \ldots\ (2)\)
 

\(\text{Add} \ (1)+(2):\)

\(-b=-6 \ \ \Rightarrow\ \ b=6\)

\(\text{Substitute \(\ b=6\ \) into (1):}\)

\(-6-c=-3 \ \ \Rightarrow\ \ c=9\).

\(\therefore b=6, c=9\)

Filed Under: Multiplicity of Zeroes in Polynomials Tagged With: Band 4, smc-7292-40-Prove Multiplicity, syllabus-2027

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