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Probability, STD2 S2 2019 HSC 25

A bowl of fruit contains 17 apples of which 9 are red and 8 are green.

Dennis takes one apple at random and eats it. Margaret also takes an apple at random and eats it.

By drawing a probability tree diagram, or otherwise, find the probability that Dennis and Margaret eat apples of the same colour.  (3 marks)

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Show Answers Only

`8/17`

Show Worked Solution

`P(text(same colour))` `= P(R R) + P(GG)`
  `= 9/17 xx 8/16 + 8/17 xx 7/16`
  `= 72/272 + 56/272`
  `= 8/17`
♦♦ Mean mark 35%.

Filed Under: Multi-Stage Events, Multi-Stage Events (Std 2), Single and Multi-Stage Events (Std 1) Tagged With: Band 5, num-title-ct-corea, num-title-qs-hsc, smc-1135-10-Probability Trees, smc-1135-15-Draw Probability Tree, smc-4238-10-Dependent events, smc-4238-50-Probability trees, smc-829-10-Probability Trees, smc-829-15-Draw Probability Tree

Probability, STD2 S2 2018 HSC 30d

A game consists of two tokens being drawn at random from a barrel containing 20 tokens. There are 17 tokens labelled 10 cents and 3 tokens labelled $2. The player wins the total value of the two tokens drawn.

Complete the probability tree by writing the missing probabilities in the boxes.  (2 marks)

 


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Show Worked Solution

Filed Under: Single and Multi-Stage Events (Std 1) Tagged With: Band 4, smc-1135-10-Probability Trees

Probability, STD2 S2 SM-Bank 1

A game consists of two tokens being drawn at random from a barrel containing 20 tokens. There are 17 red tokens and 3 black tokens. The player keeps the two tokens drawn.

  1.  Complete the probability tree by writing the missing probabilities in the boxes.  (2 marks)
     
     
       
     
  2.  What is the probability that a player draws at least one red token. Give your answer in exact form.  (2 marks)

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  1.  
  2. `187/190`
Show Worked Solution
i.   

 

ii.   `P(text(at least one red))`

`= 1 – P(BB)`

`= 1 – 3/20 · 2/19`

`= 187/190`

Filed Under: Multi-Stage Events (Std 2), Single and Multi-Stage Events (Std 1) Tagged With: Band 4, Band 5, smc-1135-10-Probability Trees, smc-1135-30-P(E) = 1 - P(not E), smc-829-10-Probability Trees, smc-829-30-P(E) = 1 - P(not E)

Probability, STD2 S2 2016 HSC 28c

A cricket team is about to play two matches. The probability of the team having a win, a loss or a draw is 0.7, 0.1 and 0.2 respectively in each match. The possible results in the two matches are displayed in the probability tree diagram.
  

2ug-2016-hsc-q28_2

  1. What is the probability of the team having a win and a draw, in any order?  (2 marks)

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  2. Paul claims that 1.4 is the probability of the team winning both matches.

     

    Give one reason why this is NOT correct.  (1 mark)

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  1. `0.28`
  2. `text(Probabilities cannot exceed 1.)`
Show Worked Solution

i.   `P(W\ text(and)\ D)`

`= P(W,D) + P(D,W)`

`= 0.7 xx 0.2 + 0.2 xx 0.7`

`= 0.28`

♦ Mean mark (i) 45%.
♦ Mean mark (ii) 49%.

 
ii.
   `text(Probabilities cannot exceed 1.)`

Filed Under: Multi-stage Events, Multi-Stage Events (Std 2), Single and Multi-Stage Events (Std 1) Tagged With: Band 5, num-title-ct-corea, smc-1135-10-Probability Trees, smc-4238-10-Dependent events, smc-4238-50-Probability trees, smc-829-10-Probability Trees

Probability, STD2 S2 2005 HSC 23c

Moheb owns five red and seven blue ties. He chooses a tie at random for himself and puts it on. He then chooses another tie at random, from the remaining ties, and gives it to his brother.

  1. What is the probability that Moheb chooses a red tie for himself?  (1 mark)

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Copy the tree diagram into your writing booklet.
 

2UG-2005-23c
 

  1. Complete your tree diagram by writing the correct probability on each branch.  (2 marks)
  2. Calculate the probability that both of the ties are the same colour.  (2 marks)

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  1. `5/12`
  2.  
  3. `31/66`
Show Worked Solution
i. `P(R)` `= (#\ text(red ties))/(#\ text(total ties))`
    `= 5/12`

 

ii.  

 

iii. `Ptext((same colour))`

`= P(text(RR)) + P(text(BB))`

`= 5/12 × 4/11\ \ +\ \ 7/12 × 6/11`

`= 20/132 + 42/132`

`= 31/66`

Filed Under: Multi-stage Events, Multi-Stage Events (Std 2), Single and Multi-Stage Events (Std 1) Tagged With: Band 3, Band 4, Band 5, smc-1135-10-Probability Trees, smc-829-10-Probability Trees

Probability, STD2 S2 2007 HSC 25c

In a stack of 10 DVDs, there are 5 rated PG, 3 rated G and 2 rated M.

  1. A DVD is selected at random. What is the probability that it is rated M?   (1 mark)

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Grant chooses two DVDs at random from the stack. Copy or trace the tree diagram into your writing booklet.
 

  1. Complete the tree diagram by writing the correct probability on each branch.   (2 marks)

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  2. Calculate the probability that Grant chooses two DVDs with the same rating.   (2 marks)

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  1. `1/5`
  2.  
  3. `14/45`
Show Worked Solution

i.    `text(5 PG, 3 G, 2 M)`

`P text{(M)} = 2/10 = 1/5` 

 

ii.   

 

iii.  `P text{(same rating)}`

`= P text{(PG, PG)} + P text{(G, G)} + P text{(M, M)}`

`= (1/2 xx 4/9) + (3/10 xx 2/9) + (1/5 xx 1/9)`

`= 2/9 + 1/15 + 1/45`

`= 14/45`

Filed Under: Multi-stage Events, Multi-Stage Events, Multi-Stage Events (Std 2), Single and Multi-Stage Events (Std 1) Tagged With: Band 3, Band 5, num-title-ct-corea, num-title-qs-hsc, smc-1135-10-Probability Trees, smc-4238-10-Dependent events, smc-4238-50-Probability trees, smc-829-10-Probability Trees

Probability, STD2 S2 2008 HSC 25b

In a drawer there are 30 ribbons. Twelve are blue and eighteen are red.

Two ribbons are selected at random.

  1. Copy and complete the probability tree diagram.  (1 mark)
     

     
  2. What is the probability of selecting a pair of ribbons which are the same colour?  (2 marks)

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  1.  
  2. `73/145`
Show Worked Solution

i. 

ii.  `Ptext{(same colour)}`

`=\ text{P(BB) + P(RR)}`

`= 12/30 xx 11/29 + 18/30 xx 17/29`

`= 132/870 + 306/870`

`= 73/145` 

Filed Under: Multi-stage Events, Multi-Stage Events (Std 2), Single and Multi-Stage Events (Std 1) Tagged With: Band 4, Band 5, smc-1135-10-Probability Trees, smc-829-10-Probability Trees

Probability, STD2 S2 2014 HSC 28c

A fair coin is tossed three times. Using a tree diagram, or otherwise, calculate the probability of obtaining two heads and a tail in any order.   (2 marks)

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`3/8`

Show Worked Solution

 
`P text{(2 heads, 1 tail)}`

`= P(HHT) + P(HTH) + P(THH)`

`= (1/2 xx 1/2 xx 1/2) + (1/2 xx 1/2 xx 1/2) + (1/2 xx 1/2 xx 1/2)`

`= 1/8 + 1/8 + 1/8`

`= 3/8`

Filed Under: Multi-stage Events, Multi-Stage Events (Std 2), Single and Multi-Stage Events (Std 1) Tagged With: Band 4, smc-1135-10-Probability Trees, smc-1135-15-Draw Probability Tree, smc-829-10-Probability Trees, smc-829-15-Draw Probability Tree

Probability, STD2 S2 2014 HSC 19 MC

Jaz has 2 bags of apples.

Bag A contains 4 red apples and 3 green apples. 

Bag B contains 3 red apples and 1 green apple.

Jaz chooses an apple from one of the bags. 

Which tree diagram could be used to determine the probability that Jaz chooses a red apple?
 

2014 19 mc1

2014 19 mc2

Show Answers Only

`A`

Show Worked Solution

`text(The tree diagram needs to identify 2 separate events.)`

`text(1st event – which bag is chosen)`

`text(2nd event – choosing a red apple from a particular bag)`

`=>  A`

Filed Under: Multi-stage Events, Multi-Stage Events (Std 2), Single and Multi-Stage Events (Std 1) Tagged With: Band 4, smc-1135-10-Probability Trees, smc-829-10-Probability Trees

Probability, STD2 S2 2013 HSC 30b

In a class there are 15 girls (G) and 7 boys (B). Two students are chosen at random to be class representatives.

  1. Complete the tree diagram below.    (2 marks)
     

     

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  2. What is the probability that the two students chosen are of the same gender?    (2 marks)

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  1.  
  2. `6/11`
Show Worked Solution

i.  

ii.    `Ptext{(same gender)}` `=P(G,G) + P(B,B)`
    `=(15/22 xx 14/21) + (7/22 xx 6/21)`
    `=210/462 + 42/462`
    `=252/462`
    `=6/11`
♦ Mean mark (ii) 40%.

Filed Under: Multi-stage Events, Multi-Stage Events (Std 2), Single and Multi-Stage Events (Std 1) Tagged With: Band 4, Band 5, num-title-ct-corea, num-title-qs-hsc, smc-1135-10-Probability Trees, smc-4238-10-Dependent events, smc-4238-50-Probability trees, smc-829-10-Probability Trees

Probability, STD2 S2 2010 HSC 20 MC

Lou and Ali are on a fitness program for one month. The probability that Lou will finish the program successfully is 0.7 while the probability that Ali will finish successfully is 0.6. The probability tree shows this information

 

What is the probability that only one of them will be successful ?

  1. `0.18`
  2. `0.28`
  3. `0.42`
  4. `0.46`
Show Answers Only

`D`

Show Worked Solution

`text(Let)\ \ Ptext{(Lou successful)}=P(L) = 0.7, \ P(\text{not}\ L) = 0.3`

`text(Let)\ \ Ptext{(Ali successful)}=P(A) = 0.6, \ P(\text{not}\ A) = 0.4`

`P text{(only 1 successful)}` `=P(L)xxP(text(not)\ A)+P(text(not)\ L)xxP(A)`
  `=(0.7xx0.4)+(0.3xx0.6)`
  `=0.28+0.18`
  `=0.46`

 
`=>  D`

♦ Mean mark 48%.

Filed Under: Multi-stage Events, Multi-Stage Events, Multi-Stage Events (Std 2), Single and Multi-Stage Events (Std 1) Tagged With: Band 5, num-title-ct-corea, num-title-qs-hsc, smc-1135-10-Probability Trees, smc-4238-20-Independent events, smc-4238-50-Probability trees, smc-829-10-Probability Trees

Probability, STD2 S2 2012 HSC 27e

A box contains 33 scarves made from two different fabrics. There are 14 scarves made from silk (S) and 19 made from wool (W).
Two girls each select, at random, a scarf to wear from the box.

  1. Complete the probability tree diagram below.   (2 marks) 
      
       

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  2. Calculate the probability that the two scarves selected are made from silk.    (1 mark)

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  3. Calculate the probability that the two scarves selected are made from different fabrics.   (2 marks)

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  1.  
       
     
  2. `P\ text{(2 silk)}= 91/528`
  3. `P\ text{(different fabrics)}= 133/264`
Show Worked Solution

i. 

♦ Mean mark (i) 43%.
ii.  `P\ text{(2 silk)}` `= P(S_1) xx P(S_2)`
  `= 14/33 xx 13/32`
  `= 91/528`

 

iii.  `P\ text{(different)}` `= P (S_1,W_2) + P(W_1,S_2)`
  `= (14/33 xx 19/32) + (19/33 xx 14/32)`
  `= 532/1056`
  `= 133/264`
♦ Mean mark (iii) 41%.
MARKER’S COMMENT: In better responses, students multiplied along the branches and then added these two results together

Filed Under: Multi-stage Events, Multi-Stage Events, Multi-Stage Events (Std 2), Single and Multi-Stage Events (Std 1) Tagged With: Band 4, Band 5, num-title-ct-corea, num-title-qs-hsc, smc-1135-10-Probability Trees, smc-4238-10-Dependent events, smc-4238-50-Probability trees, smc-829-10-Probability Trees

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