If `d = 6t^2`, what is a possible value of `t` when `d = 2400`?
- `0.05`
- `20`
- `120`
- `400`
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If `d = 6t^2`, what is a possible value of `t` when `d = 2400`?
`B`
`d` | `= 6t^2` |
`t^2` | `= d/6` |
`t` | `= +- sqrt(d/6)` |
`text(When)\ \ d = 2400:`
`t` | `= +- sqrt(2400/6)` |
`= +- 20` |
`=> B`
The volume of a sphere is given by `V = 4/3 pi r^3` where `r` is the radius of the sphere.
If the volume of a sphere is `220\ text(cm)^3`, find the radius, to 1 decimal place. (3 marks)
--- 6 WORK AREA LINES (style=lined) ---
`3.7\ \ text{cm (to 1 d.p.)}`
`V` | `= 4/3 pi r^3` |
`3V` | `= 4 pi r^3` |
`r^3` | `= (3V)/(4 pi)` |
`text(When)\ \ V = 220`
`r^3` | `= (3 xx 220)/(4 pi)` |
`= 52.521…` | |
`:. r` | `=root3 (52.521…)` |
`= 3.744…\ \ \ text{(by calc)}` | |
`= 3.7\ \ text{cm (to 1 d.p.)}` |
Which of the following correctly expresses \(r\) as the subject of \(V=\pi r^2+x\) ?
\(C\)
\(V\) | \(=\pi r^2+x\) |
\(\pi r^2\) | \(=V-x\) |
\(r^2\) | \(=\dfrac{V-x}{\pi}\) |
\(\therefore\ r\) | \(=\pm\sqrt{\dfrac{V-x}{\pi}}\) |
\(\Rightarrow C\)
Make `r` the subject of the equation `V = 4/3 pir^3`. (3 marks)
--- 6 WORK AREA LINES (style=lined) ---
`r = root(3)((3V)/(4pi))`
`V` | `= 4/3 pir^3` |
`3V` | `=4pir^3` |
`(3V)/4` | `= pir^3` |
`r^3` | `= (3V)/(4pi)` |
`r` | `= root(3)((3V)/(4pi))` |
Make `y` the subject of the equation `x = sqrt(yp - 1)`. (2 marks)
`y = (x^2 + 1)/p`
`x` | `= sqrt(yp – 1)` |
`yp – 1` | `= x^2` |
`yp` | `= x^2 + 1` |
`:. y` | `= (x^2 + 1)/p` |
The volume of a sphere is given by `V = 4/3 pi r^3` where `r` is the radius of the sphere.
If the volume of a sphere is `220\ text(cm)^3`, find the radius, to 1 decimal place. (3 marks)
--- 6 WORK AREA LINES (style=lined) ---
`3.7\ \ text{cm (to 1 d.p.)}`
`V` | `= 4/3 pi r^3` |
`3V` | `= 4 pi r^3` |
`r^3` | `= (3V)/(4 pi)` |
`text(When)\ \ V = 220`
`r^3` | `= (3 xx 220)/(4 pi)` |
`= 52.521…` | |
`:. r` | `=root3 (52.521…)` |
`= 3.744…\ \ \ text{(by calc)}` | |
`= 3.7\ \ text{cm (to 1 d.p.)}` |
Make `L` the subject of the equation `T = 2piL^2`. (2 marks)
--- 4 WORK AREA LINES (style=lined) ---
`± sqrt(T/(2pi))`
`T` | `= 2piL^2` |
`L^2` | `= T/(2pi)` |
`:.L` | `= ±sqrt(T/(2pi))` |
What is the formula for `q` as the subject of `4p =5t + 2q^2`?
`D`
`4p` | `= 5t + 2q^2` |
`2q^2` | `= 4p – 5t` |
`q^2` | `= (4p – 5t)/2` |
`q` | `= +- sqrt{(4p – 5t)/2}` |
`=> D`
If `d = 6t^2`, what is a possible value of `t` when `d = 2400`?
`B`
`d` | `= 6t^2` |
`t^2` | `= d/6` |
`t` | `= +- sqrt(d/6)` |
`text(When)\ \ d = 2400:`
`t` | `= +- sqrt(2400/6)` |
`= +- 20` |
`=> B`
Which of the following correctly expresses `a` as the subject of `s= ut+1/2at^2 `?
`A`
`s` | `=ut+1/2at^2` |
`1/2at^2` | `=s-ut` |
`at^2` | `=2(s-ut)` |
`a` | `=(2(s-ut))/t^2` |
`=>A`
Which of the following correctly expresses `c` as the subject of `E = mc^2 + p` ?
`A`
`E` | `=\ mc^2 + p` |
`mc^2` | `=\ E\-p` |
`c^2` | `=(E-p)/m` |
`:.c` | `= +-sqrt((E-p)/m)` |
`=> A`