Make `r` the subject of the formula `P = 2r + 10`. (2 marks)
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Make `r` the subject of the formula `P = 2r + 10`. (2 marks)
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`r = (P – 10)/2`
`P` | `= 2r + 10` |
`2r` | `= P – 10` |
`r` | `= (P – 10)/2` |
Given the formula `C = (A(y + 1))/24`, calculate the value of `y` when `C = 120` and `A = 500`. (3 marks)
`4.76`
`text(Make)\ \ y\ \ text(the subject:)`
`C` | `= (A(y + 1))/24` |
`24C` | `= A(y + 1)` |
`y + 1` | `= (24C)/A` |
`y` | `= (24C)/A – 1` |
`= (24 xx 120)/500 – 1` | |
`= 4.76` |
Make `F` the subject of the equation `C = 5/9(F - 32)`. (2 marks)
`F = (9C)/5 + 32`
`C` | `= 5/9(F – 32)` |
`9C` | `= 5(F – 32)` |
`(9C)/5` | `= F – 32` |
`:.F` | `= (9C)/5 + 32` |
Which of the following correctly expresses `y` as the subject of the formula `3x-4y-1 = 0`?
`C`
`3x-4y-1` | `= 0` |
`4y` | `= 3x-1` |
`:. y` | `= (3x-1)/4` |
`=> C`
Make `p` the subject of the equation `c = 5/3p + 15`. (2 marks)
`p = 3/5 c – 9`
`c` | `= 5/3p + 15` |
`5/3p` | `= c – 15` |
`p` | `= 3/5 (c – 15)` |
`= 3/5 c – 9` |
Which of the following correctly expresses `Q` as the subject of `e = iR + Q/C`?
`=> B`
`e` | `= iR + Q/C` |
`Q/C` | `= e-iR` |
`:. Q` | `= C(e-iR)` |
`= Ce-CiR` |
`=> B`
The formula `C = 5/9 (F-32)` is used to convert temperatures between degrees Fahrenheit `(F)` and degrees Celsius `(C)`.
Convert 3°C to the equivalent temperature in Fahrenheit. (2 marks)
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`37.4\ text(degrees)\ F`
`C` | `= 5/9(F-32)` |
`F-32` | `= 9/5C` |
`F` | `= 9/5C + 32` |
`text(When)\ \ C = 3,`
`F` | `= (9/5 xx 3) + 32` |
`= 37.4\ text(degrees)\ F` |
Which of the following correctly expresses `T` as the subject of `B = 2pi (R + T/2)`?
`A`
`B` | `= 2pi (R + T/2)` |
`B/(2pi)` | `= R + T/2` |
`T/2` | `= B/(2pi)-R` |
`T` | `= B/pi-2R` |
`=> A`
Which of the following correctly express `x` as the subject of `a=(nx)/5` ?
`B`
`a` | `=(nx)/5` |
`nx` | `=5a` |
`x` | `=(5a)/n` |
`=> B`
Which equation correctly shows `r` as the subject of `S=800(1-r)`?
`A`
`S` | `=800(1-r)` |
`1-r` | `=S/800` |
`r` | `=1-S/800` |
`=(800-S)/800` |
`=>\ A`