In humans, blood groups are produced by combinations of three alleles
A mother has blood type
Which of the following includes all possible genotype(s) of the father?
or or or or or or
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In humans, blood groups are produced by combinations of three alleles
A mother has blood type
Which of the following includes all possible genotype(s) of the father?
→ To have blood type
→ As the mother has genotype
→ Option C includes every possible genotype with at least one
Experiments were conducted to obtain data on the traits 'seed shape' in plants and 'feather colour' in chickens. In each case, the original parents were pure breeding and produced the first generation (F1). The frequency data diagrams below relate to the second generation offspring (F2), produced when the F1 generations were bred together.
Explain the phenotypic ratios of the F2 generation in both the plant and chicken breeding experiments. Include Punnett squares and a key to support your answer. (5 marks)
→ Graph A shows a 3:1 phenotypic ratio. This is typical of a dominant/recessive allele phenotypic ratio of two heterozygous parents.
→ The Punnet square below supports this argument, where R refers to the dominant seed shape (e.g. round) and r is the recessive allele, producing another seed shape (e.g. wrinkled). The offspring have a 3:1 ratio of dominant : recessive seed shape.
Key: R = Round r = wrinkled
→ Graph B shows a 1:2:1 phenotypic ratio. Because both parents are heterozygous, this ratio is typical of a co-dominant or incomplete dominant trait.
→ If B is an allele referring to black colour feathers and W is the allele for white colour feathers then both parents will be BW, which is either grey colour feathers (co-dominance) or both black and white feathers (incomplete dominance). A cross between these genotypes will produce a phenotypic ratio of the same seen in the graph.
Key: B = Black Feathers W= White Feathers
→ Graph A shows a 3:1 phenotypic ratio. This is typical of a dominant/recessive allele phenotypic ratio of two heterozygous parents.
→ The Punnet square below supports this argument, where R refers to the dominant seed shape (e.g. round) and r is the recessive allele, producing another seed shape (e.g. wrinkled). The offspring have a 3:1 ratio of dominant : recessive seed shape.
Key: R = Round r = wrinkled
→ Graph B shows a 1:2:1 phenotypic ratio. Because both parents are heterozygous, this ratio is typical of a co-dominant or incomplete dominant trait.
→ If B is an allele referring to black colour feathers and W is the allele for white colour feathers then both parents will be BW, which is either grey colour feathers (co-dominance) or both black and white feathers (incomplete dominance). A cross between these genotypes will produce a phenotypic ratio of the same seen in the graph.
Key: B = Black Feathers W= White Feathers
Eggplant fruit comes in three colours: dark purple, white and violet. A genetic cross between the dark purple and white eggplants will always result in the violet phenotype.
What phenotypic ratio would you expect to see when two violet offspring are crossed? Show your working. (3 marks)
→ Violet is a mix between dark purple and white.
→ Thus proving this characteristic follows a co-dominance inheritance
→ Therefore, violet eggplants have a Pp genotype.
→
Genotype: PP – Pp – pp (1 – 2 – 1)
Phenotype: Dark Purple – Violet – White (1 – 2 – 1)
→ Violet is a mix between dark purple and white.
→ Thus proving this characteristic follows a co-dominance inheritance
→ Therefore, violet eggplants have a Pp genotype.
→
Genotype: PP – Pp – pp (1 – 2 – 1)
Phenotype: Dark Purple – Violet – White (1 – 2 – 1)
A normal allele results in liver cells with sufficient cholesterol receptors. A different allele results in liver cells without cholesterol receptors. Individuals who are heterozygous have liver cells with insufficient cholesterol receptors.
What type of inheritance is the most likely explanation for this?
→ A heterozygous individual exhibiting faulty cholesterol receptors suggests that neither allele is completely expressed.
→ There is also no evidence of the condition being sex-linked.