What is the name of the product formed when chlorine, \(\ce{Cl2}\), reacts with but-1-ene?
- 1,2-dichlorobutane
- 1,4-dichlorobutane
- 2,2-dichlorobutane
- 2,3-dichlorobutane
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What is the name of the product formed when chlorine, \(\ce{Cl2}\), reacts with but-1-ene?
\(A\)
\(\ce{CH3CH2CH=CH2 + Cl2 \rightarrow CH3CH2CHClCH2Cl }\)
→ Product is 1,2-dichlorobutane
\(\Rightarrow A\)
The table lists some properties of the straight-chained carbon compounds `W, X, Y` and `Z`.
Which row of the following table best identifies the compounds `W, X, Y` and `Z`?
\begin{align*}
\begin{array}{c|c}
\rule{0pt}{2.5ex}\text{ }\rule[-1ex]{0pt}{0pt} \\
\rule{0pt}{2.5ex}\text{A.}\ \ \ \ \ \rule[-1ex]{0pt}{0pt} \\
\rule{0pt}{2.5ex}\text{B.}\ \ \ \ \ \rule[-1ex]{0pt}{0pt} \\
\rule{0pt}{2.5ex}\text{C.}\ \ \ \ \ \rule[-1ex]{0pt}{0pt} \\
\rule{0pt}{2.5ex}\text{D.}\ \ \ \ \ \rule[-1ex]{0pt}{0pt} \\
\end{array}
\begin{array}{|c|c|}
\hline
\rule{0pt}{2.5ex}\textit{W}\rule[-1ex]{0pt}{0pt} & \rule{0pt}{2.5ex}\textit{X}\rule[-1ex]{0pt}{0pt} & \rule{0pt}{2.5ex}\textit{Y}\rule[-1ex]{0pt}{0pt}& \rule{0pt}{2.5ex}\textit{Z}\rule[-1ex]{0pt}{0pt}\\
\hline
\rule{0pt}{2.5ex}\ \ \ \ce{C3H6}\ \ \ \rule[-1ex]{0pt}{0pt} & \rule{0pt}{2.5ex}\ \ \ \ce{C3H8}\ \ \ \rule[-1ex]{0pt}{0pt} & \rule{0pt}{2.5ex}\ce{CH3OH}\rule[-1ex]{0pt}{0pt}& \rule{0pt}{2.5ex}\ce{C4H9OH}\rule[-1ex]{0pt}{0pt}\\
\hline
\rule{0pt}{2.5ex}\ce{C3H8}\rule[-1ex]{0pt}{0pt} & \rule{0pt}{2.5ex}\ce{C3H6}\rule[-1ex]{0pt}{0pt} & \rule{0pt}{2.5ex}\ce{CH3OH}\rule[-1ex]{0pt}{0pt}& \rule{0pt}{2.5ex}\ce{C4H9OH}\rule[-1ex]{0pt}{0pt}\\
\hline
\rule{0pt}{2.5ex}\ce{C3H6}\rule[-1ex]{0pt}{0pt} & \rule{0pt}{2.5ex}\ce{C3H8}\rule[-1ex]{0pt}{0pt} & \rule{0pt}{2.5ex}\ce{C4H9OH}\rule[-1ex]{0pt}{0pt}& \rule{0pt}{2.5ex}\ce{CH3OH}\rule[-1ex]{0pt}{0pt}\\
\hline
\rule{0pt}{2.5ex}\ce{C3H8}\rule[-1ex]{0pt}{0pt} & \rule{0pt}{2.5ex}\ce{C3H6}\rule[-1ex]{0pt}{0pt} & \rule{0pt}{2.5ex}\ce{C4H9OH}\rule[-1ex]{0pt}{0pt}& \rule{0pt}{2.5ex}\ce{CH3OH}\rule[-1ex]{0pt}{0pt}\\
\hline
\end{array}
\end{align*}
`A`
→ Compound W is unsaturated (C–C multiple bonds exist).
→ Compound X is saturated (all C–C bonds are single bonds).
→ Shorter alcohols, such as \(\ce{CH3OH}\) are more soluble.
`=>A`
Three test tubes were set up as shown.
Bromine water was added to `X` and `Y` in the absence of UV light.
Which of the following best represents the changes in test tubes `X` and `Y` ?
`C`
By Elimination:
→ Liquids are immiscible (eliminate A and D).
→ Bromine water does not decolourise with with alkanes, but does with alkenes (eliminate B).
`=>C`
Prop-1-ene reacts with `\text{Cl}_2` in an addition reaction. In the box given, draw the structural formula of the product of this reaction. (2 marks)
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Four organic liquids are used in an experiment. The four liquids are
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a. A safety concern is that the organic liquids are flammable.
To address this, keep substance away from open flames and keep away from ignition sources.
b. Flask 1: propanoic acid (carboxylic acids can’t be oxidised and are polar)
Flask 2: hex-1-ene (alkenes can be oxidised and are non-polar)
Flask 3: propan-1-ol (primary alcohols can be oxidised and are polar)
Flask 4: hexane (alkanes don’t react with acidified oxidants and are non-polar)
c. Hex-1-ene
→ Could be identified using the bromine water test.
→ The addition of brown bromine water to an alkene causes an addition reaction where the solution changes colours from brown to colourless.
Propanoic acid
→ Could be identified through a neutralisation reaction using `text{Na}_2text{CO}_3`.
→ Effervescent reaction will result.
Propan-1-ol
→ Could be identified through an oxidation reaction using acidified dichromate.
→ The reaction would cause the solution to change from green to orange.
a. A safety concern is that the organic liquids are flammable.
To address this, keep substance away from open flames and keep away from ignition sources.
b. Flask 1: propanoic acid (carboxylic acids can’t be oxidised and are polar)
Flask 2: hex-1-ene (alkenes can be oxidised and are non-polar)
Flask 3: propan-1-ol (primary alcohols can be oxidised and are polar)
Flask 4: hexane (alkanes don’t react with acidified oxidants and are non-polar)
c. Hex-1-ene
→ Could be identified using the bromine water test.
→ The addition of brown bromine water to an alkene causes an addition reaction where the solution changes colours from brown to colourless.
Propanoic acid
→ Could be identified through a neutralisation reaction using `text{Na}_2text{CO}_3`.
→ Effervescent reaction will result.
Propan-1-ol
→ Could be identified through an oxidation reaction using acidified dichromate.
→ The reaction would cause the solution to change from green to orange.
A chemist synthesises a substance using the following pathway.
\[\ce{ X ->[{hydration}] {Y} ->[{oxidation}] Z}\]
What are compounds `text{X, Y, Z}` ?
`C`
By elimination:
→ Hydration reaction is an addition reaction that can only occur on alkenes, thus `X` = prop-1-ene (eliminate A and B)
→ `Y` = propan-2-ol
→ The oxidation of secondary alcohol creates a ketone, thus `Z` = propanone
`=> C`