The landing gear on an aircraft uses a hydraulic braking system. A force of 60 N is applied at the master cylinder with a piston diameter of 12 mm.
What is the force at the brake calliper with a piston diameter of 42 mm ?
- 4.9 N
- 17.14 N
- 210 N
- 735 N
Aussie Maths & Science Teachers: Save your time with SmarterEd
The landing gear on an aircraft uses a hydraulic braking system. A force of 60 N is applied at the master cylinder with a piston diameter of 12 mm.
What is the force at the brake calliper with a piston diameter of 42 mm ?
\( D \)
→ Pressure is the same in both master cylinder and brake calliper \(\big(P = \frac{F}{A}\big) \)
→ Convert units: \(12\ \text{mm} = \dfrac{12}{1000} = 0.012\ \text{m, 42 mm}\ =\dfrac{42}{1000} = 0.042\ \text{m} \)
→ Using \(\dfrac{F_2}{A_2} = \dfrac{F_1}{A_1} \):
\(F_2 = \dfrac{F_1 \times A_2}{A_1} = \dfrac{60 \times \ \pi \times 0.021^2}{\pi \times 0.006^2} = 735\ \text{N} \)
\(\Rightarrow D \)
The diagram shows an aerofoil.
Which condition needs to be achieved for lift to occur?
`A`
→ For a net upwards force, the force from pressure below (pushing up) must exceed the force from pressure above (pushing down).
→ Therefore Pressure 1<Pressure 2.
`=A>`
The flaps of an executive jet are controlled using a hydraulic system. A force of 1 kN acts on the 40 mm diameter master piston.
What force would need to be developed to move the flap if the slave piston has a diameter of 100 mm? (3 marks)
--- 6 WORK AREA LINES (style=lined) ---
`6.25\ text{kN}`
`P=F/A`
`1000/(pi xx 20^2)` | `=F_S/(pi xx 50^2)` | |
`F_S` | `=(1000 xx pi xx 50^2)/(pi xx 20^2)` | |
`=6250\ text{N}` | ||
`=6.25\ text{kN}` |
The diagram shows the airflow in a venturi.
What does this diagram illustrate?
`D`
→ Bernoulli’s principle states that the higher the pressure is, the lower the velocity will be.
→ This is illustrated in the diagram as it shows that there is a decreased pressure in the thinner, higher velocity section.
`=>D`
An air gauge contains air at 750 kPa (gauge) while atmospheric pressure is at 100 kPa. The air at absolute pressure operates a piston of 15 mm diameter.
Calculate the force the compressed air exerts on the piston. (4 marks)
--- 8 WORK AREA LINES (style=lined) ---
`150.45\ text{N}`
`P_(ga)=750\ text{kPa}, \ P_(atm)=100\ text{kPa}, \ D=15\ text{mm}`
`P` | `=P_0+rhogh` | |
`P_(abs)` | `=P_(atm)+P_(ga)` | |
`= 750 + 100` | ||
`= 850\ text{kPa}` |
`P_(abs)` | `=F/A` | |
`F` | `=P_(abs)xxA` | |
`A` | `=(piD^2)/4` | |
`=(pixx0.015^2)/4` | ||
`=1.77xx10^(-4)\ text{m}^2` |
`:.\ F` | `=850xx10^3xx1.77xx10^(-4)` | |
`= 150.45\ text{N}` |
A pitot tube supplies two pressure readings, total pressure and static pressure.
These pressure readings are then used to determine the
`B`
Dynamic Pressure = Total − Static
`=>B`