Identify the compound in which chromium has an oxidation state of 6.
- \(\ce{CrCl3}\)
- \(\ce{Cr2O3}\)
- \(\ce{K2Cr2O7}\)
- \(\ce{Cr(OH)3}\)
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Identify the compound in which chromium has an oxidation state of 6.
\(C\)
Let \(x\) be the oxidation state of chromium in each of the following calculations.
\(\ce{CrCl3}\) → \(x+3(-1)=0\ \ \Rightarrow \ \ x=3\)
\(\ce{Cr2O3}\) → \(2x+3(-2)=0\ \ \Rightarrow \ \ x=3\)
\(\ce{K2Cr2O7}\) → \(2(1)+ 2x+7(-2)=0\ \ \Rightarrow \ \ x=6\)
\(\ce{Cr(OH)3}\) → \(x+3(-1)=0\ \ \Rightarrow \ \ x=3\)
\(\Rightarrow C\)
Which of the following species decreases in oxidation number?
\(\ce{Fe^{2+}(aq) + MnO4^-(aq) + 8H^+(aq) -> 5Fe^{3+} + Mn^{2+}(aq) + 4H2O(l)}\)
\(B\)
→ The oxidation number of \(\ce{Fe^{2+}(aq)}\) increases from +2 to +3.
→ The oxidation number of \(\ce{Mn}\) in \(\ce{MnO4^-}\)
\(\ce{Mn} +4(-2)\) | \(=-1\) | |
\(\ce{Mn}\) | \(=7\) |
→ \(\ce{Mn}\) decreases from an oxidation number of 7 to 2 during the reaction.
\(\Rightarrow B\)
What is the oxidation state of sulfur in the sulfate ion, \(\ce{SO4^{2-}}\)?
\(C\)
→ The oxidation number of a polyatomic ion is the charge of the ion.
→ Let \(x\) be the oxidation state of sulfur and the oxidation state of oxygen is \(-2\).
\(x +4(-2)\) | \(=-2\) | |
\(x-8\) | \(=-2\) | |
\(x\) | \(=6\) |
\(\Rightarrow C\)
The oxidation state of phosphorus in the pyrophosphate ion \(\ce{P2O7^{4-}}\) is
\(B\)
\(\text{Let}\ x =\ \text{oxidation state of phosphorus} \)
\(2x + (7 \times -2)\) | \(=-4\) | |
\(2x-14\) | \(=-4\) | |
\(x\) | \(=+5\) |
\(\Rightarrow B\)
In which one of the following compounds is sulfur in its lowest oxidation state?
\(D\)
Let \(x\) equal the oxidation of sulfur in each of the following calculations.
In \(\ce{SO3}\):
\(x+ 3 \times -2\) | \(=0\) | |
\(x\) | \(=6\) |
In \(\ce{HSO4–}\):
\(1 + x+ 4 \times -2\) | \(=-1\) | |
\(x\) | \(=6\) |
In \(\ce{SO2}\):
\(x+ 2 \times -2\) | \(=0\) | |
\(x\) | \(=4\) |
In \(\ce{Al2S3}\):
\(2 \times 3+ 3 \times x\) | \(=0\) |
\(3x\) | \(=-6\) |
\(x\) | \(=-2\) |
→ \(D\) has the lowest oxidation number showing it is in the lowest oxidation state.
\(\Rightarrow D\)
One test used for random breath testing in NSW involved crystals of potassium dichromate reacting with ethanol. In this reaction the orange dichromate ion, \(\ce{Cr2O7}^{2-}\), changes to the green chromium ion, \(\ce{Cr^3+}\).
Which statement is true for this reaction?
\(C\)
Let \(x\) equal the oxidation number of Cr in \(\ce{Cr2O7}^{2-}\).
\(2x+ 7 \times -2 = -2\)
\(2x= 12\)
\(x=6\)
The Chromium has been reduced as the oxidation number has decreased from 6 to 3, thus it gains electrons and the oxidation state is lower.
\(\Rightarrow C\)
Consider the following redox reaction.
\( \ce{2K2Cr2O7}(aq) + \ce{2H2O}(l) + \ce{3S}(s) \rightarrow \ce{2Cr2O3}(aq) + \ce{4KOH}(aq) + \ce{3SO2}(g) \)
Which species is being oxidised?
\(D\)
Sulfer has an oxidation number of 0 on the left hand side of the equation.
Let \(x\) equal the oxidation number of sulfur within \(\ce{3SO2}(g) \).
\(x+2 \times -2\) | \(=0\) | |
\(x-4\) | \(=0\) | |
\(x\) | \(=4\) |
→ The increase in oxidation number shows the species, \( \ce{S} \), has undergone oxidation.
\(\Rightarrow D\)