The enthalpies of reaction of a number of chemical reactions are as follows:
Reaction 1: \(\ce{CH3CH2OH(l) + 3O2(g) \rightarrow 2CO2(g) + 3H2O(l)}\) \(\Delta H_1=-1360\ \text{kJ mol}^{-1}\)
Reaction 2: \(\ce{CH3COOH(l) + 2O2(g) \rightarrow 2CO2(g) + 2H2O(l)}\) \(\Delta H_2=-876\ \text{kJ mol}^{-1}\)
Reaction 3: \(\ce{H2(g) + \frac{1}{2}O2(g) \rightarrow H2O(l)}\) \(\Delta H_3=-285.8\ \text{kJ mol}^{-1}\)
Calculate the enthalpy change for the reaction below using the enthalpies of reaction above.
\(\ce{CH3COOH(l) + H2(g) \rightarrow CH3CH2OH(l) + \frac{1}{2}O2(g)}\) \(\Delta H_4=?\) (3 marks)
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