Consider the following average bond energies (\(\text{KJ mol}^{-1}\)):
\begin{array} {cc}
\ce{N\equiv N} & 945 \\
\ce{H-H} & 436 \\
\ce{N=N} & 470 \\
\ce{N-H} & 391 \\
\ce{N-N} & 158 \\
\ce{C=N} & 615 \\
\end{array}
Using the values above, calculate the enthalpy change for the Haber Process:
\(\ce{N2(g) + 3H2(g) \rightarrow 2NH3(g)}\) (2 marks)
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