The enthalpies of formation for a number of chemical reactions are as follows:
\(\ce{C6H12O6(s)}\) \(\Delta H^{\circ}_f = -1271\ \text{kJmol}^{-1}\)
\(\ce{C2H5OH(aq)}\) \(\Delta H^{\circ}_f = -277.7\ \text{kJmol}^{-1}\)
\(\ce{CO2(g)}\) \(\Delta H^{\circ}_f = -393.5\ \text{kJmol}^{-1}\)
Calculate the enthalpy change for the fermentation of glucose (reaction below) using the enthalpies of formation above.
\(\ce{C6H12O6(s) \rightarrow 2C2H5OH(aq) + 2CO2(g)}\) (3 marks)
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