Given the formula `C = (A(y + 1))/24`, calculate the value of `y` when `C = 120` and `A = 500`. (3 marks)
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Given the formula `C = (A(y + 1))/24`, calculate the value of `y` when `C = 120` and `A = 500`. (3 marks)
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`4.76`
`text(Make)\ \ y\ \ text(the subject:)`
`C` | `= (A(y + 1))/24` |
`24C` | `= A(y + 1)` |
`y + 1` | `= (24C)/A` |
`y` | `= (24C)/A-1` |
`= (24 xx 120)/500-1` | |
`= 4.76` |
The daily energy requirement, `E` (kilojoules), for a person of mass `m` (kilograms) is calculated using the rule `E = 7m + 7300`.
For Elijah, `E = 7755`.
What is Elijah's mass? (2 marks)
`65\ text{kgs}`
`7755` | `= 7m + 7300` |
`7 m` | `= 455` |
`m` | `= 455/7` |
`= 65\ text(kilograms)` |
Given the formula `C = (A(y + 1))/24`, calculate the value of `y` when `C = 120` and `A = 500`. (3 marks)
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`4.76`
`text(Make)\ \ y\ \ text(the subject:)`
`C` | `= (A(y + 1))/24` |
`24C` | `= A(y + 1)` |
`y + 1` | `= (24C)/A` |
`y` | `= (24C)/A-1` |
`= (24 xx 120)/500-1` | |
`= 4.76` |
The formula `C = 5/9 (F-32)` is used to convert temperatures between degrees Fahrenheit `(F)` and degrees Celsius `(C)`.
Convert 3°C to the equivalent temperature in Fahrenheit. (2 marks)
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`37.4\ text(degrees)\ F`
`C` | `= 5/9(F-32)` |
`F-32` | `= 9/5C` |
`F` | `= 9/5C + 32` |
`text(When)\ \ C = 3,`
`F` | `= (9/5 xx 3) + 32` |
`= 37.4\ text(degrees)\ F` |
The distance in kilometres (`D`) of an observer from the centre of a thunderstorm can be estimated by counting the number of seconds (`t`) between seeing the lightning and first hearing the thunder.
Use the formula `D = t/3` to estimate the number of seconds between seeing the lightning and hearing the thunder if the storm is 1.2 km away. (1 mark)
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`3.6\ text(seconds)`
`D = t/3`
`text(When)\ \ D = 1.2,`
`t/3` | `= 1.2` |
`t` | `= 3.6\ text(seconds)` |