- What scale factor is used to convert Circle A into Circle B. (1 mark)
--- 2 WORK AREA LINES (style=lined) ---
- Complete this equation:
- Area of Circle A = _____ × Area of Circle B. (1 mark)
--- 0 WORK AREA LINES (style=lined) ---
Aussie Maths & Science Teachers: Save your time with SmarterEd
--- 2 WORK AREA LINES (style=lined) ---
--- 0 WORK AREA LINES (style=lined) ---
i. \(\text{Scale factor}\ = \dfrac{\text{Diameter B}}{\text{Diameter A}} = \dfrac{0.8}{2.4} = \dfrac{1}{3} \)
ii. \(\text{Scale factor (B to A)} = \dfrac{\text{Diameter A}}{\text{Diameter B}} = \dfrac{2.4}{0.8} = 3 \)
\(\text{Scale factor (Area)} = 3^2 = 9 \)
\(\therefore\ \text{Area of Circle A = 9 × Area of Circle B} \)
Kransky has a photo which is 25 cm wide and 10 cm high
He wants to enlarge it to make a poster with a width of 50 cm.
What will be the height of the poster? (2 marks)
--- 4 WORK AREA LINES (style=lined) ---
`text(20 cm)`
`text(Scale factor)` | `= text(new width)/text(old width)` |
`= 50/25` | |
`= 2` |
`:.\ text(New height)` | `= 2 xx 10` |
`= 20\ text(cm)` |
Juanita wanted to print a larger copy of her photo of a tree.
She increased the scale by a factor of 3.
She named the first picture Photo A and the second picture Photo B.
If Photo B is 3.2 cm high, how high is Photo A in centimetres, correct to 1 decimal place? (2 marks)
--- 4 WORK AREA LINES (style=lined) ---
`1.1\ text(cm)`
`text{Since Photo B is increased by a factor of 3,}`
`text(Height of Photo B)/text(Height of Photo A)` | `=3` |
`:.\ text(Height of Photo A)` | `=text(Height of Photo B)/3` |
`=3.2/3` | |
`=1.0666…` | |
`=1.1\ text{cm (1 d.p.)}` |
`C`
`text{Scale factor}\ =3/2 =1.5`
`:.\ x = 1.5 xx 12 = 18`
`text{Alternate solution}`
`text{Using sides of similar figures in the same ratio:}`
`x/12` | `=3/2` | |
`x` | `=12 xx (3/2)` | |
`x` | `=18` |
`=> C`
`A`
`text(Take two corresponding sides)`
`text(In)\ Delta A:\ 3\ text(cm)`
`text(In)\ Delta B:\ 1 \frac{1}{2}\ text(cm)`
`:.\ text(Scale factor converting)\ Delta A\ text(to)\ Delta B = frac{1}{2}`
`=> A`
Triangles `ABC` and `DEF` are similar.
Which expression could be used to find the value of `x`?
`C`
`text(We know)\ \ Delta ABC\ text(|||)\ Delta DEF`
`:.\ (AB)/(AC)` | `=y/10=(DE)/(DF)=x/15` |
`x/15` | `=y/10` |
`x` | `=yxx15/10` |
`=> C`