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Calculus, 2ADV C4 2020 HSC 20

Kenzo is driving his car along a road while his friend records the velocity of the car, `v(t)`, in km/h every minute over a 5-minute period. The table gives the velocity  `v(t)`  at time  `t`  hours.
 

 

The distance covered by the car over the 5-minute period is given by

`int_0^(5/60) v(t)\ dt`.

Use the trapezoidal rule and the velocity at each of the six time values to find the approximate distance in kilometres the car has travelled in the 5-minute period. Give your answer correct to one decimal place.  (2 marks)

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`5.4\ text(km)`

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`int_0^(5/60) v(t)\ dt` `~~ 1/2 xx 1/60 [60 + 2(55 + 65 + 68 + 70) + 67]`
  `~~ 1/120 (643)`
  `~~ 5.358…`
  `~~ 5.4\ text(km)`

Filed Under: Trapezium Rule and Newton, Trapezoidal Rule (Y12) Tagged With: Band 4, smc-5145-04-Trapezium rule, smc-5145-10-Table provided, smc-976-10-Table provided

Calculus, 2ADV C4 2011* HSC 5c

The table gives the speed `v` of a jogger at time `t` in minutes over a  20-minute period. The speed `v` is measured in metres per minute, in intervals of 5 minutes.

\begin{array} {|l|c|}
\hline
\rule{0pt}{2.5ex} \ \ \ t\ \ \  \rule[-1ex]{0pt}{0pt} & \ \ \ 0\ \ \ &\ \ \ 5\ \ \ &\ \ \ 10\ \ \ &\ \ \ 15\ \ \ &\ \ \ 20\ \ \  \\
\hline
\rule{0pt}{2.5ex} \ \ \ v\ \ \  \rule[-1ex]{0pt}{0pt} & 173 & 81 & 127 & 195 & 168 \\
\hline
\end{array}

The distance covered by the jogger over the 20-minute period is given by  `int_0^20 v\ dt`.

Use the Trapezoidal rule and the speed at each of the five time values to find the approximate distance the jogger covers in the 20-minute period.   (3 marks)

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 `text(2867.5 metres)`

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\begin{array} {|l|c|}
\hline
\rule{0pt}{2.5ex} \ \ \ t\ \ \  \rule[-1ex]{0pt}{0pt} & \ \ \ 0\ \ \ &\ \ \ 5\ \ \ &\ \ \ 10\ \ \ &\ \ \ 15\ \ \ &\ \ \ 20\ \ \  \\
\hline
\rule{0pt}{2.5ex} \ \ \ v\ \ \  \rule[-1ex]{0pt}{0pt} & 173 & 81 & 127 & 195 & 168 \\
\hline
\rule{0pt}{2.5ex} \text{weight} \rule[-1ex]{0pt}{0pt} & 1 & 2 & 2 & 2 & 1 \\
\hline
\end{array}

`int_0^20 v\ dt`

`~~ 5/2[173 + 2(81 + 127 + 195) + 168]`
  `~~ 5/2(1147)`
  `~~ 2867.5\ text(metres)`

Filed Under: Trapezium Rule and Newton, Trapezoidal Rule (Y12) Tagged With: Band 4, smc-5145-04-Trapezium rule, smc-5145-10-Table provided, smc-976-10-Table provided

Calculus, 2ADV C4 2005* HSC 6a

Five values of the function  `f(x)`  are shown in the table.
 

Integration, 2UA 2005 HSC 6a

Use the Trapezoidal rule with the five values given in the table to estimate

`int_0^20 f(x)\ dx`.  (3 marks)

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`387.5`

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`:. int_0^20 f(x)\ dx` `~~ 5/2[15 + 2(25 + 22 + 18) + 10]`
  `~~ 5/2(155)`
  `~~ 387.5`

Filed Under: Trapezium Rule and Newton, Trapezoidal Rule (Y12) Tagged With: Band 4, smc-5145-04-Trapezium rule, smc-5145-10-Table provided, smc-976-10-Table provided

Calculus, 2ADV C4 2016* HSC 14a

The diagram shows the cross-section of a tunnel and a proposed enlargement.

hsc-2016-14a

The heights, in metres, of the existing section at 1 metre intervals are shown in Table `A.`

hsc-2016-14ai

The heights, in metres, of the proposed enlargement are shown in Table `B.`

hsc-2016-14aii

Use the Trapezoidal rule with the measurements given to calculate the approximate increase in area.   (3 marks)

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`1.3\ text(m²)`

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`text(Consider the shaded area distances:)`

`A` `~~ 1/2[0 + 2(0.4 + 0.5 + 0.4) + 0]`
  `~~ 1/2(2.6)`
  `~~ 1.3\ text(m²)`

Filed Under: Trapezium Rule and Newton, Trapezoidal Rule (Y12) Tagged With: Band 3, smc-5145-04-Trapezium rule, smc-5145-10-Table provided, smc-5145-30-Estimate comparison, smc-976-10-Table provided, smc-976-30-Estimate Comparison

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