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v1 Algebra, STD2 A1 2014 HSC 26c

Solve the equation  \(\dfrac{4x-3}{5}-6=7-6x\).   (3 marks)

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 \(x=2\)

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\(\dfrac{4x-3}{5}-6\) \(=7-6x\)
\(4x-3-5\times 6\) \(=5(7-6x)\)
\(4x-3-30\) \(=35-30x\)
\(34x\) \(=68\)
\(\therefore\ x\) \(=2\)

Filed Under: Substitution and Other Equations (Std 2-X) Tagged With: Band 4, smc-5233-30-Algebraic Fractions

v1 Algebra, STD2 A1 2015 HSC 24 MC

Consider the equation  \(\dfrac{5x}{2}-3=\dfrac{3x}{5}+1\).

Which of the following would be a correct step in solving this equation?

  1. \(\dfrac{5x}{2}-2=\dfrac{3x}{5}\)
  2. \(\dfrac{10x}{4}-4=\dfrac{6x}{5}\)
  3. \(\dfrac{5x}{2}=\dfrac{3x}{5}+4\)
  4. \(5x-3=\dfrac{6x}{5}+2\)
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\(C\)

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\(\dfrac{5x}{2}-3\) \(=\dfrac{3x}{5}+1\)
\(\dfrac{5x}{2}-3+3\) \(=\dfrac{3x}{5}+1+3\)
\(\dfrac{5x}{2}\) \(=\dfrac{3x}{5}+4\)

 
\(\Rightarrow C\)

Filed Under: Substitution and Other Equations (Std 2-X) Tagged With: Band 4, smc-5233-30-Algebraic Fractions

v1 Algebra, STD2 A1 SM-Bank 3

Find the value of  \(b\)  given  \(\dfrac{b}{9}-5=3\).  (1 mark)

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\(72\)

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\(\dfrac{b}{9}-5\) \(=3\)
\(\dfrac{b}{9}\) \(=8\)
\(\therefore\ b\) \(=72\)

Filed Under: Substitution and Other Equations (Std 2-X) Tagged With: Band 2, smc-5233-30-Algebraic Fractions

v1 Algebra, STD2 A1 SM-Bank 13

If  \(\dfrac{x-8}{9}=2\),  find  \(x\).  (1 mark)

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\(26\)

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\(\dfrac{x-8}{9}\) \(=2\)
 \(x-8\) \(=18\)
 \(x\) \(=26\)

Filed Under: Substitution and Other Equations (Std 2-X) Tagged With: Band 2, smc-5233-30-Algebraic Fractions

v1 Algebra, STD2 A1 2018 HSC 28b

Solve the equation  \(\dfrac{3x}{4}+1=\dfrac{5x+1}{3}\), leaving your answer as a fraction.  (3 marks)

--- 6 WORK AREA LINES (style=lined) ---

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\(\dfrac{8}{11}\)

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♦ Mean mark 35%.

\(\underbrace{\dfrac{3x}{4} + 1}_\text{multiply x 12}\) \(=\underbrace{\dfrac{5x+1}{3}}_\text{multiply x 12}\)
\(9x+12\) \(=20x+4\)
\(11x\) \(=8\)
\(x\) \(=\dfrac{8}{11}\)

Filed Under: Substitution and Other Equations (Std 2-X) Tagged With: Band 5, smc-5233-30-Algebraic Fractions

v1 Algebra, STD2 A1 2021 HSC 29

Solve  \(x+\dfrac{x-3}{4}=5\), leaving your answer as a fraction.  (2 marks)

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\(\dfrac{23}{5}\)

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♦ Mean mark 40%.
\(x+\dfrac{x-3}{4}\) \(=5\)
\(4x+x-3\) \(=20\)
\(5x\) \(=23\)
\(x\) \(=\dfrac{23}{5}\)

Filed Under: Substitution and Other Equations (Std 2-X) Tagged With: Band 5, smc-5233-30-Algebraic Fractions

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