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Probability, 2ADV EQ-Bank 12

A new test has been developed for determining whether or not people are carriers of the Gaussian virus.

Two hundred people are tested. A two-way table is being used to record the results.
 

  1.  What is the value of `A`?   (1 mark)

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  2.  A person randomly selected from the tested group is a carrier of the virus.
  3. What is the probability that the test results would show this?   (1 mark) 

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  4. If the person randomly selected has a negative result from their test, what is the probability they are not a carrier of the virus?   (2 marks)

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Show Answers Only

a.    `98`

b.    `37/43`

c.    `49/55`

Show Worked Solution

a.    `A= 200-(74 + 12 + 16)= 98`
 

b.    `P` `= text(#Positive carriers)/text(Total carriers)`
  `= 74/86`
  `= 37/43`

 

c.    `text(Total number with negative results) = 110`

`text{Total non-carriers with negative results}\ = 98`

`P\text{(not a carrier)|negative result}\ = 98/110=49/55`

Filed Under: Conditional Probability and Venn Diagrams Tagged With: Band 3, Band 4, smc-6470-25-Two-way tables

Probability, 2ADV EQ-Bank 6 MC

A survey of 370 people was conducted to investigate the association between watching Anime and the age of the person.

The two-way table shows the responses collected.

One response is randomly chosen. If the responder does not watch Anime, what is the probability they are 30 years old or under?

  1. 16%
  2. 29%
  3. 33%
  4. 50%
Show Answers Only

\(C\)

Show Worked Solution

\(\text{Total respondents who don’t watch anime}\ = 184\)

\(\text{Total respondents 30 years and under who don’t watch amine}\ = 61\)

\(P\text{(30 or under)}|\text{no anime} = \dfrac{61}{184}=0.331… \)

\(\Rightarrow C\)

Filed Under: Conditional Probability and Venn Diagrams Tagged With: Band 4, smc-6470-25-Two-way tables

Probability, 2ADV EQ-Bank 6 MC

A group of 485 people was surveyed. The people were asked whether or not they smoke. The results are recorded in the table.
 

A person is selected at random from the group.

If the person chosen was a female, what is the chance she is a non-smoker?

  1. 31%
  2. 32%
  3. 68%
  4. 69%
Show Answers Only

`D`

Show Worked Solution

`P(text(Female chosen is a non-smoker))`

`= (text(Total female non-smokers))/(text(Total females))`

`= 153/221`

`= 0.6923…`
 

`=> D`

Filed Under: Conditional Probability and Venn Diagrams Tagged With: Band 4, smc-6470-25-Two-way tables

Probability, 2ADV EQ-Bank 14

Lie detector tests are not always accurate. A lie detector test was administered to 200 people.

The results were:

• 50 people lied. Of these, the test indicated that 40 had lied;
• 150 people did NOT lie. Of these, the test indicated that 20 had lied.

  1. Complete the table using the information above   (1 mark)
      
        

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  2. For what percentage of the people tested was the test accurate?   (1 mark)

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  3. What is the probability that the test indicated a lie for a person who did NOT lie?   (1 mark)

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Show Answers Only

a.    `text(See Worked Solutions)`

b.    `text(85%)`

c.    `2/15`

Show Worked Solution

a.

b.  `text(Percentage of people with accurate readings)`

`= text(# Accurate readings)/text(Total readings) xx 100`

`= (40+130)/200`

`= 85 text(%)`
 

c.  `text{P(lie detected when NOT a lie)}`

`= 20/150`

`= 2/15`

Filed Under: Conditional Probability and Venn Diagrams Tagged With: Band 3, Band 4, smc-6470-25-Two-way tables

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