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Measurement, STD2 EQ-Bank 1

2UG-2005-25b

Use Pythagoras’ theorem to show that `ΔABC` is a right-angled triangle.   (1 mark)

--- 3 WORK AREA LINES (style=lined) ---

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`ΔABC\ text(is right-angled if)\ \ a^2 + b^2 = c^2:`

`a^2 + b^2= 5^2 + 12^2= 169= 13^2= c^2`

Show Worked Solution

`ΔABC\ text(is right-angled if)\ \ a^2 + b^2 = c^2:`

`a^2 + b^2= 5^2 + 12^2= 169= 13^2= c^2`

Filed Under: Perimeter and Area Tagged With: Band 3, smc-6483-15-Pythagoras, smc-6520-15-Pythagoras

Measurement, STD2 M6 2023 HSC 12 MC

A cylindrical pipe with a radius of 12.5 cm is filled with water to a depth, `d` cm, as shown.

The surface of the water has a width of 20 cm.
 

What is the depth of water in the pipe?

  1. 2.5 cm
  2. 5.0 cm
  3. 7.5 cm
  4. 12.5 cm
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`B`

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`text{Triangle base}\ = 20/2=10\ text{cm}`

`text{Let}\ x =\ text{⊥ distance from centre to water}`

`text{Using Pythagoras:}`

`12.5^2` `=x^2+10^2`  
`x^2` `=12.5^2-10^2=56.25`  
`x` `=\sqrt{56.25}=7.5\ text{cm}`  

 
`d=12.5-7.5=5.0\ text{cm}`

`=>B`

♦ Mean mark 42%.

Filed Under: Perimeter and Area, Perimeter and Area, Pythagoras and Right-Angled Trig (Std2) Tagged With: Band 5, smc-6483-15-Pythagoras, smc-6520-15-Pythagoras, smc-802-10-Pythagoras

Measurement, STD2 M6 2011 HSC 9 MC

Two trees on level ground, 12 metres apart, are joined by a cable. It is attached 2 metres above the ground to one tree and 11 metres above the ground to the other.

What is the length of the cable between the two trees, correct to the nearest metre? 

  1.  `9\ text(m)`
  2. `12\ text(m)`
  3. `15\ text(m)`
  4. `16\ text(m)`
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`C`

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`text(Using Pythagoras)`

`c^2` `=12^2+9^2`
  `=144+81`
  `=225`
`c` `=\sqrt{225}=15,\ \ c>0`

 
`=>C`

Filed Under: M3 Right-Angled Triangles (Y12), Perimeter and Area, Perimeter and Area, Pythagoras and basic trigonometry, Pythagoras and Right-Angled Trig (Std2), Right-angled Triangles Tagged With: Band 3, num-title-ct-core, num-title-qs-hsc, smc-1103-20-Right-angled Trig, smc-4218-30-Hypotenuse, smc-6483-15-Pythagoras, smc-6520-15-Pythagoras, smc-802-10-Pythagoras

Measurement, STD2 M6 2010 HSC 3 MC

A field diagram has been drawn from an offset survey.
 

What is the distance from `G` to `H` correct to the nearest metre?

  1. \(11\)
  2. \(13\)
  3. \(16\)
  4. \(20\)
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`B`

Show Worked Solution

`text(Using Pythagoras:)`

`GH^2` `=12^2+(16-11)^2`
  `=144+25`
  `=169`
`GH` `=sqrt169=13\ text(m)`

 
` =>  B`

Filed Under: M3 Right-Angled Triangles (Y12), MM2 - Perimeter, Area and Volume (Prelim), Perimeter and Area, Perimeter and Area, Pythagoras and Right-Angled Trig (Std2) Tagged With: Band 4, smc-1103-10-Pythagoras, smc-6483-15-Pythagoras, smc-6520-15-Pythagoras, smc-802-10-Pythagoras

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