Use mathematical induction to prove that \(3^n+7^n\) is divisible by 10 for all odd \(n\). (3 marks)
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Use mathematical induction to prove that \(3^n+7^n\) is divisible by 10 for all odd \(n\). (3 marks)
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\(\text{Proof (See Worked Solutions)}\)
\(\text{Prove \(3^n+7^n\) is divisible by 10 for \(n\) odd.}\)
\(\text{Prove true for}\ \ n=1:\)
\(3^1+7^1=10 \ \ \text {(which is divisible by 10)}\)
\(\therefore \ \text{True for} \ \ n=1\)
\(\text{Assume true for} \ \ n=k\) :
\(3^k+7^k=10 P \ \text{(where \(P\) is an integer)}\)
\(\Rightarrow 3^k=10 P-7^k\ \ldots\ (1)\)
\(\text{Prove true for}\ \ n=k+2:\)
| \(3^{k+2}+7^{k+2}\) | \(=9 \times 3^k+49 \times 7^k\) |
| \(=9\left(10 P-7^k\right)+49 \times 7^k\) | |
| \(=90 P-9 \times 7^k+49 \times 7^k\) | |
| \(=90P+40 \times 7^k\) | |
| \(=10\left(9 P + 4 \times 7^k\right)\) |
\(\Rightarrow \ \text{True for} \ \ n=k+2\)
\(\therefore \ \text{Since true for \(n=1\), by PMI, true for integers \(n\) odd}.\)
Use mathematical induction to prove that `15 ^(n)+6^(2n+1)` is divisible by 7 for all integers `n >= 0`. (3 marks)
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`text{Proof (See Worked Solutions)}`
`text{Prove}\ \ 15 ^(n)+6^(2n+1)\ \ text{is divisible by 7 for}\ \ n>=0`
`text{If}\ \ n=0:`
`15^0+6^1=7`
`:.\ text{True for}\ \ n=0`
`text{Assume true for}\ \ n=k`
`text{i.e.}\ \ 15^(k)+6^(2k+1)=7P\ \ text{(where}\ P\ text{is an integer)}`
`=>6^(2k+1)=7P-15^(k)\ \ …\ (1)`
`text{Prove true for}\ \ n=k+1`
| `15^(k+1)+6^(2k+3)` | `=15*15^(k)+6^2*6^(2k+1)` |
| `=15*15^(k)+36(7P-15^(k))\ \ text{(see (1))}` | |
| `=15*15^(k)+36*7P-36*15^(k)` | |
| `=36*7P-21*15^(k)` | |
| `=7(36P-3*15^(k))\ \ text{(which is divisible by 7)}` |
`=>\ text{True for}\ \ n=k+1`
`:.\ text{S}text{ince true for}\ \ n=0, text{by PMI, true for integers}\ \ n>=0`
Use mathematical induction to prove that `7^n + 15^n` is divisible by 11 where `n` is an odd integer. (3 marks)
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`text(Proof)\ \ text{(See Worked Solutions)}`
`text(Prove)\ \ 7^n + 15^n\ \ text(is divisible by 11, where)\ n\ text(is odd)`
`text(If)\ \ n = 1:`
| `7^n + 15^n` | `= 7 + 15 = 22` |
| `22/11` | `= 2\ \ \ text{(Divisible by 11)}` |
`text(Assume true for)\ \ n = k:`
| `text(i.e.)\ 7^k + 15^k` | `= 11P\ \ \ \ text{(}P\ text(integer) text{)}` |
| `7^k` | `= 11P\ – 15^k\ \ \ \ \ …\ text{(∗)}` |
`text(Prove true for)\ \ n = k + 2:`
| `7^(k + 2) + 15^(k + 2)` | `= 7^2 * 7^k + 15^2 * 15^k` |
| `= 49 (11P-15^k) + 225 (15^k)\ \ \ text(… from)\ text{(∗)}` | |
| `= 49 * 11P-49 * 15^k + 225 (15^k)` | |
| `= 49 * 11P + 176 * 15^k` | |
| `= 11 (49P + 16 * 15^k)` |
`=>text(True for)\ n = k + 2`
`:.\ text(S)text(ince true for)\ n = 1,\ text(by PMI, true for odd integral)\ \ n >= 1`