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Calculus, MET2 2020 VCAA 15 MC

Part of the graph of a function  `f`, where `a>0`, is shown below.
 

The average value of  the function  `f` over the interval  `[2a, a]` is

  1. `0`
  2. `a/3`
  3. `a/2`
  4. `3a/4`
  5. `a`
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`B`

Show Worked Solution

♦♦ Mean mark 32%.

`text(Average Value)`

`=(1)/(a-(-2a))int_(-2a)^(a)f(x)\ dx`

`=(1)/(3a)(int_(-2a)^(0)(-(3)/(2)x-a)\ dx+int_(0)^(a)(2x-a)\ dx)`

`=(a)/(3)`

`=>B`

Filed Under: Average Value and Other Tagged With: Band 5, smc-756-35-Other functions, smc-756-40-Graphs and Avg Value

Calculus, MET2 2013 VCAA 15 MC

Let `h` be a function with an average value of 2 over the interval  `[0, 6].`

The graph of `h` over this interval could be

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`C`

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`text(Draw the line)\ \ y=2\ \ text(on each graph.)`

♦♦♦ Mean mark 25%.

`=>\ text(An average value of 2 occurs when the same area)`

`text(is enclosed above and below the graph.)`

 

`text(Consider)\ C,`

VCAA 2013 15mc-iv

`text(Area)\ A =\ text(Area)\ B`

`=>   C`

 

Filed Under: Average Value and Other Tagged With: Band 6, smc-756-40-Graphs and Avg Value

Calculus, MET2 2015 VCAA 8 MC

The graph of a function  `f:\ text{[−2, p]} -> R`  is shown below.
 

VCAA 2015 8mc

The average value of  `f` over the interval  `text{[−2, p]}`  is zero.

The area of the shaded region is  `25/8.`

If the graph is a straight line, for  `0 <= x <= p`, then the value of `p` is

A.   `2`

B.   `5`

C.   `5/4`

D.   `5/2`

E.   `25/4`

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`D`

Show Worked Solution
`text(Shaded Area)` `=\ text(Area below)\ \ f(x)\ text(from)\ \ 0 to p`
`1/2 p^2` `= 25/8`
`p^2` `=25/4`
`:. p` `= 5/2,quadp > 0`

`=>   D`

Filed Under: Average Value and Other Tagged With: Band 4, smc-756-40-Graphs and Avg Value

Calculus, MET2 2014 VCAA 20 MC

The graph of a function, `h`, is shown below.
 

VCAA 2014 20mc
 

The average value of `h` is

  1. `4`
  2. `5`
  3. `6`
  4. `7`
  5. `10`
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`D`

Show Worked Solution

`text(From inspection, the average value of)\ h`

♦ Mean mark 44%.

`text(is either 6 or 7.)`

vcaa-2014-20mc-answer

`h_text(avg) = 7\ text(as area bounded by)\ h(x)`

`text(and)\ y = 7\ text(above)\ y = 7\ text(is equivalent)`

`text(to area bounded below)`

vcaa-2014-20mc-answer-1

`=>   D`

Filed Under: Average Value and Other Tagged With: Band 5, smc-756-40-Graphs and Avg Value

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