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Algebra, STD1 EQ-Bank 34

Two water tanks sit side by side on a farm.

Tank A has a capacity of 1000 litres and is full. It is being emptied at a constant rate of 60 litres per minute.

At the same time, Tank B is empty and is being filled at a constant rate of 40 litres per minute.

Let    \(V\) = volume of water in litres, and 

   \(t\) = time in minutes.

  1. The equation  \(V=1000-60t\)  models the volume of water in Tank A.
  2. Write an equation to model the volume of water in Tank B.   (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  3. Complete the table below and use the values to graph the volume of water in Tank A and Tank B on the grid below.   (3 marks)
     
          \(\begin{array}{|c|c|c|c|c|c|c|c|} \hline t & 0 & 2 & 4 & 6 & 8 & 10 & 12 \\ \hline \text{Tank A} & \ \ \ \ \ \ \ \  & 880 & 760 & 640 & 520 & 400 & 280 \\ \hline \text{Tank B} & 0 & \ \ \ \ \ \ \ \ \  & 160 & 240 & 320 & 400 & \ \ \ \ \ \ \ \  \\ \hline \end{array}\)
  
    1. --- 0 WORK AREA LINES (style=lined) ---

  1. After how many minutes do both tanks contain the same volume of water?   (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  2. What is the volume of water in each tank at this time?   (1 mark)

    --- 4 WORK AREA LINES (style=lined) ---

Show Answers Only

a.    \(V=40t\)

b.    \(\text{Table of values:}\)

\(\begin{array}{|c|c|c|c|c|c|c|c|} \hline t & 0 & 2 & 4 & 6 & 8 & 10 & 12 \\ \hline \text{Tank A} & 1000 & 880 & 760 & 640 & 520 & 400 & 280 \\ \hline \text{Tank B} & 0 & 80 & 160 & 240 & 320 & 400 & 480 \\ \hline \end{array}\)

 

c.    \(10\ \text{minutes}\)

d.    \(400\ \text{litres}\)

Show Worked Solution

a.    \(V=40t\)

b.    \(\text{Table of values:}\)

\(\begin{array}{|c|c|c|c|c|c|c|c|} \hline t & 0 & 2 & 4 & 6 & 8 & 10 & 12 \\ \hline \text{Tank A} & 1000 & 880 & 760 & 640 & 520 & 400 & 280 \\ \hline \text{Tank B} & 0 & 80 & 160 & 240 & 320 & 400 & 480 \\ \hline \end{array}\)

 

c.    \(\text{From the graph, the lines intersect at }\ t=10.\)

\(\therefore\ \text{Both tanks contain the same volume after 10 minutes}\)
  

d.    \(\text{Method 1: Graphically}\)

\(\text{From the graph, when }\ t=10,\ \text{the volume in both tanks = 400 litres}\)
  

\(\text{Method 2: Algebraically}\)

\(\text{When }\ t=10:\)

\(\text{Tank A volume:}\ \ V=1000-60\times10=400\ \text{L}\)

\(\text{Tank B volume:}\ \ V=40\times10=400\ \text{L}\ \checkmark\)

\(\therefore\ \text{Each tank contains } 400\ \text{litres}\)

Filed Under: Simultaneous Linear Equations Tagged With: Band 4, Band 5, Band 6, smc-6839-20-Other SE Applications, smc-6839-30-Find Intersection

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