Inequalities (Ext1-2027)

Functions, EXT1 F1 2025 HSC 1 MC

What is the solution to \(\abs{2 x+3}<5\) ?

\(-4<x<1\)
\(x<-4\) or \(x>1\)
\(-1<x<4\)
\(x<-1\) or \(x>4\)

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\(A\)

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\(\abs{2 x+3}<5\)

\(-5 < 2x+3 <5\)

\(-8< 2x < 2\)

\(-4<x<1\)

\(\Rightarrow A\)

Functions, EXT1 F1 2024 HSC 12e

The diagram shows the graph of \(y=\dfrac{1}{\abs{x-5}}\).

For what values of \(x\) is \(\dfrac{x}{6} \geq\dfrac{1}{\abs{x-5}}\) ? (3 marks)

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\(x \in[2,3] \cup[6, \infty)\)

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\(\dfrac{x}{6} \geqslant \dfrac{1}{|x-5|}\)

\(x|x-5| \geqslant 6\)

\(\text{Case 1:}\)

\(x(x-5) \geqslant 6\)

\(x^2-5 x-6 \geqslant 0\)

\((x-6)(x+1) \geqslant 0\)

\(x \leqslant-1\ \ \text{or}\ \ x \geqslant 6\)

\(\text {By inspection of graph} \ \Rightarrow \ x \leqslant -1\ \text{is not a solution}\)

\(\Rightarrow x \geqslant 6\)

Mean mark 55%.

\(\text {Case 2: }\)

\(-x(x-5) \geqslant 6\)

\(-x^2+5 x-6 \geqslant 0\)

\(x^2-5 x+6 \leqslant 0\)

\((x-3)(x-2) \leqslant 0\)

\(\Rightarrow 2 \leqslant x \leqslant 3\)

\(\therefore x \in[2,3] \cup[6, \infty)\)

Functions, EXT1 F1 2022 HSC 11f

Solve `(x)/(2-x) >= 5`. (3 marks)

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`5/3<=x<2`

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`(x)/(2-x) >= 5`

`text{Multiply b.s. by}\ \ (2-x)^2\ \ (>0):`

`x(2-x)`	`>=5(2-x)^2`
`2x-x^2`	`>=5(x^2-4x+4)`

`6x^2-22x+20`	`<=0`
`2(3x^2-11x+10)`	`<=0`
`(3x-5)(x-2)`	`<=0`

`text{Test}\ \ x=0:`

`(-5)(-2)=10>0`

`:. 5/3<=x<2\ \ (x!=2)`

Functions, EXT1 F1 2020 SPEC1 4

Solve the inequality `3 - x > 1/|x - 4|` for `x`, expressing your answer in interval notation. (3 marks)

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`x ∈ (– oo, (7 – sqrt 5)/2)`

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`3 – x > 1/|x – 4|`

`|x – 4| (3 – x) > 1`

`text(If)\ \ x – 4 > 0, x > 4`

`(x – 4) (3 – x)`	`> 1`
`3x – x^2 – 12 + 4x`	`> 1`
`-x^2 + 7x – 13`	`> 0`

`Delta = 7^2 – 4 ⋅ 1 ⋅ 13 = -3 < 0`

`=>\ text(No Solutions)`

`text(If)\ \ x – 4 < 0, x < 4`

`-(x – 4) (3 – x)`	`> 1`
`x^2 – 7x + 12`	`> 1`
`x^2 – 7x + 11`	`> 0`

`x`	`= (7 +- sqrt(7^2 – 4 ⋅ 1 ⋅ 11))/2`
	`= (7 +- sqrt 5)/2`

`text(Combining solutions)`

`(x < (7 – sqrt 5)/2 ∪ x > (7 + sqrt 5)/2) nn x < 4`

`x ∈ (– oo, (7 – sqrt 5)/2)`

Functions, EXT1 F1 2019 HSC 11b

For what values of `x` is `x/(x + 1) < 2`? (3 marks)

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`x < -2 or x > -1`

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`x/(x + 1) < 2`

`text(Multiply b.s. by)\ \ (x + 1)^2`

`x(x + 1)`	`< 2(x + 1)^2`
`x^2 + x`	`< 2x^2 + 4x + 2`
`0`	`< x^2 + 3x + 2`
`0`	`< (x + 2)(x + 1)`

`text(From graph:)`

`x < -2 or x > -1`

Functions, EXT1* F1 2019 HSC 11g

The parabola `y = x^2` meets the line `y = x + 2` at the points `(-1, 1)` and `(2, 4)`. Do NOT prove this.

By first sketching the graphs of `y = x^2` and `y = x + 2`, shade the region which simultaneously satisfies the two inequalities `y >= x^2` and `y >= x + 2`. (2 marks)

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Functions, EXT1 F1 SM-Bank 2

Solve `3/(|\ x - 3\ |) < 3`. (3 marks)

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`x < 2\ ∪\ x > 4`

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`text(Solution 1)`

`3/(|\ x – 3\ |) < 3`

`\|\ x – 3\ \|`	`> 1`
`(x^2 – 6x + 9)`	`> 1^2`
`x^2 – 6x + 8`	`> 0`
`(x – 4)(x – 2)`	`> 0`

`:. {x: \ x < 2\ ∪\ x > 4}`

`text(Solution 2)`

`|\ x – 3\ | > 1`

`text(If)\ \ (x – 3)`	`> 0,\ text(i.e.)\ x >3`
`x – 3`	`> 1`
`x`	`> 4`

`=> x > 4\ (text(satisfies both))`

`text(If)\ \ (x – 3)`	`< 0,\ text(i.e.)\ x <3`
`−(x – 3)`	`> 1`
`−x + 3`	`> 1`
`x`	`< 2`

`=> x < 2\ (text(satisfies both))`

`:. {x: \ x < 2\ ∪\ x > 4}`

Functions, EXT1 F1 SM-Bank 3

A circle has centre `(5,3)` and radius 3.

Describe, with inequalities, the region that consists of the interior of the circle and more than 2 units above the `x`-axis. (2 marks)

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Sketch the region. (1 mark)

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`(x-5)^2 + (y-3)^2 < 9\ ∩\ y > 2`

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i. `text(Equation of circle:)`

`(x-5)^2 + (y-3)^2 = 3^2`

`:.\ text(Region is:)`

`(x-5)^2 + (y- 3)^2 < 9\ ∩\ y > 2`

COMMENT: The broken line on the graph represents an excluded boundary.

ii.

Functions, EXT1 F1 2017 HSC 11c

Solve `(2x)/(x + 1) > 1`. (3 marks)

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`:. x < −1\ \ text(or)\ \ x > 1`

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`(2x)/(x + 1) > 1`

`text(If)\ \ x + 1 > 0,\ \ text(i.e.)\ \ x > −1`

`2x`	`> x + 1`
`x`	`> 1`

`=> x > 1`

`text(If)\ \ x + 1 < 0,\ \ text(i.e.)\ \ x < −1`

`2x`	`< x + 1`
`x`	`< 1`

`=> x < −1`

`:. x < −1\ \ text(or)\ \ x > 1`

Functions, EXT1* F1 2017 HSC 8 MC

The region enclosed by `y = 4 - x,\ \ y = x` and `y = 2x + 1` is shaded in the diagram below.

Which of the following defines the shaded region?

A.	`y <= 2x + 1, qquad`	`y <= 4-x, qquad`	`y >= x`
B.	`y >= 2x + 1, qquad`	`y <= 4-x, qquad`	`y >= x`
C.	`y <= 2x + 1, qquad`	`y >= 4-x, qquad`	`y >= x`
D.	`y >= 2x + 1, qquad`	`y >= 4-x, qquad`	`y >= x`

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`A`

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`text(Consider)\ \ y = 2x + 1,`

`text(Shading is below graph)`

`=> y <= 2x + 1`

`text(Consider)\ \ y = 4-x,`

`text(Shading is below graph)`

`=> y <= 4-x`

`=> A`

Functions, EXT1 F1 2016 HSC 11e

Solve `3/(2x + 5) - x > 0`. (3 marks)

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`x < -3,\ \ – 5/2 < x < 1/2`

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`3/(2x + 5) – x > 0`

`3 (2x + 5) > x (2x + 5)^2,\ \ x != – 5/2`

`3 (2x + 5)-x(2x+5)^2`	`> 0`
`(2x + 5) [3- x(2x + 5)]`	`> 0`
`(2x + 5) (-2x^2 – 5x + 3)`	`> 0`
`(2x + 5) (1-2x) (x + 3)`	`> 0`

`x < -3,\ \ \ – 5/2 < x < 1/2`

Functions, EXT1* F1 2016 HSC 11c

Solve `|\ x - 2\ | <= 3.` (2 marks)

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`-1 <= x <= 5`

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`\|\ x – 2\ \|`	`<= 3`
`(x – 2)^2`	`<= 3^2`
`(x^2 – 4x + 4)`	`<= 9`
`x^2 – 4x – 5`	`<= 0`
`(x – 5) (x + 1)`	`<= 0`

`:. -1 <= x <= 5`

Functions, EXT1 F1 2007 HSC 3b

Find the vertical and horizontal asymptotes of the hyperbola `y = (x − 2)/(x − 4)`

and hence sketch the graph of `y = (x − 2)/(x − 4)`. (3 marks)

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Hence, or otherwise, find the values of `x` for which

`qquad qquad (x − 2)/(x − 4) ≤ 3`. (2 marks)

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`text(See Worked Solutions.)`
`x < 4\ text(and)\ x ≥ 5`

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i. `y = (x − 2)/(x − 4)`

`text(Vertical asymptote at)\ x = 4`

`lim_(x → ∞) (x − 2)/(x − 4)`

`= lim_(x → ∞) (1 − 2/x)/(1 − 4/x)=1`

`ytext(–intercept)\ = 1/2`

`xtext(–intercept)\ = 2`

ii. `text(Find)\ \ x\ \ text(so that)\ \ (x − 2)/(x − 4) ≤ 3`

`text(When)\ \ (x − 2)/(x − 4)`	`= 3`
`x − 2`	`= 3x − 12`
`2x`	`= 10`
`x`	`= 5`

`=>(5, 3)\ \ text(is the intersection of)\ \ y = 3\ and\ y = (x − 2)/(x − 4)`

`:. (x − 2)/(x − 4) ≤ 3\ \ text(when)\ \ x < 4\ \ text(and)\ \ x ≥ 5.`

Functions, EXT1 F1 2004 HSC 1b

Solve `4/(x + 1) < 3.` (3 marks)

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`x < −1\ \ text(or)\ \ x > 1/3`

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`4/(x + 1) < 3`

`text(Multiply both sides by)\ (x + 1)^2`

`4(x + 1)`	`< 3(x + 1)^2`
`4x + 4`	`< 3(x^2 + 2x + 1)`
`4x + 4`	`< 3x^2 + 6x + 3`

`3x^2 + 2x − 1`	`> 0`
`(3x − 1)(x + 1)`	`> 0`

`text(LHS) = 0\ \ text(when)\ \ x = 1/3\ \ text(or)\ \ −1`

`text(From the graph,)`

`x < −1\ text(or)\ x > 1/3`

Functions, EXT1 F1 2004 HSC 1a

Indicate the region on the number plane satisfied by `y ≥ |\ x + 1\ |.` (2 marks)

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`text(See Worked Solution)`

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`y ≥ |\ x + 1\ |`

`text(Test)\ (0, 0)`

`0 ≥ |\ 0 + 1\ |`

`0 ≥ 1\ \ \ \ \ \ ⇒\ text(False)`

`:.\ text(Shaded area represents)`

`y ≥ |\ x + 1\ |`

Functions, EXT1 F1 2015 HSC 11c

Solve the inequality `4/(x + 3) ≥ 1`. (3 marks)

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`−3 < x ≤ 1, \ \ x ≠ −3`

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`text(Solution 1)`

`4/(x + 3) ≥ 1`

`4(x + 3)`	`≥ (x + 3)^2`
`4x + 12`	`≥ x^2 + 6x + 9`
`x^2 + 2x − 3`	`≤ 0`
`(x + 3)(x − 1)`	`≤ 0`

`:.−3 < x ≤ 1, \ \ x ≠ −3`

`text(Solution 2)`

`text(If)\ (x + 3)`	`> 0`
`x`	`> −3`

`4/(x + 3)`	`≥ 1`
`4`	`≥ x + 3`
`x`	`≤ 1`

`:. −3 < x ≤ 1`

`text(If)\ (x + 3)`	`< 0`
`x`	`< −3`

`4/(x + 3)`	`≥ 1`
`4`	`≤ x + 3`
`x`	`≥ 1`
`:.\ text(No solution.)`

`:. −3 < x ≤ 1`

Functions, EXT1* F1 2015 HSC 13b

Find the domain and range for the function `f(x) = sqrt (9 - x^2)`. (2 marks)

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On a number plane, shade the region where the points `(x, y)` satisfy both of the inequalities

`qquad y <= sqrt (9 - x^2)` and `y >= x` . (2 marks)

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`text(Domain)\ -3 <= x <= 3\ \ \ \ \ \ \ \ text(Range)\ 0<= y <= 3`
`text(See Worked Solutions)`

Show Worked Solution

i. `f(x) = sqrt(9 – x^2)`

`text(Domain)`

`9 – x^2`	`>= 0`
`x^2`	`<= 9`

`-3 <= x <= 3`

`text(Range)`

`0 <= y <= 3`

♦ Mean mark 34%.

ii.

Functions, EXT1* F1 2005 HSC 1e

Find the values of `x` for which `|\ x − 3\ | ≤ 1`. (2 marks)

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`2 ≤ x ≤ 4`

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`|\ x − 3\ | ≤ 1`

`text(Solution 1)`

`(x − 3)^2 ≤ 1`

`x^2 − 6x + 9 ≤ 1`

`x^2 − 6x +8 ≤ 0`

`(x − 4)(x − 2) ≤ 0`

`:. 2 ≤ x ≤ 4`

`text(Alternative Solution)`

`(x − 3)`	`≤1`	`–(x − 3)`	` ≤ 1`
`x`	`≤4`	`–x +3`	`≤ 1`
		`–x`	`≤−2`
		`x`	`≥ 2`

`:. 2 ≤ x ≤ 4`

Functions, EXT1* F1 2004 HSC 1f

Find the values of `x` for which `|\ x + 1\ |<= 5`. (2 marks)

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`-6 <= x <= 4`

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`text(Solution 1)`

`|\ x + 1\ |<= 5`

`-5`	`≤x+1≤5`
`:.-6`	`≤x≤4`

`text(Solution 2)`

`|\ x + 1\ |<= 5`

`(x+1)^2`	`<= 5^2`
` x^2 + 2x + 1`	`<= 25`
`x^2 + 2x – 24`	`<= 0`
`(x + 6)(x – 4)`	`<= 0`

`:.\ -6 <= x <= 4`

Functions, EXT1 F1 2008 HSC 3a

Sketch the graph of `y = |\ 2x - 1\ |`. (1 mark)

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Hence, or otherwise, solve `|\ 2x - 1\ | <= |\ x - 3\ |`. (3 marks)

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`-2 <= x <= 4/3`

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ii. `text(Solving for)\ \ |\ 2x – 1\ | <= |\ x – 3\ |`

`text(Graph shows the statement is TRUE)`

`text(between the points of intersection.)`

`=>\ text(Intersection occurs when)`

`(2x – 1)`	`= (x – 3)\ \ \ text(or)\ \ \ `	`-(2x – 1)`	`= x – 3`
`x`	`= -2`	`-2x + 1`	`= x – 3`
		`-3x`	`= -4`
		`x`	`= 4/3`

`:.\ text(Solution is)\ \ {x: -2 <= x <= 4/3}`

Functions, EXT1 F1 2014 HSC 11e

Solve `(x^2 + 5)/x > 6`. (3 marks)

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`0<x<1\ \ text(or)\ \ x>5`

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`(x^2 + 5)/x`	`> 6`
`x^2 ((x^2 + 5)/x)`	`> 6x^2`
`x^3 + 5x`	`> 6x^2`
`x^3 – 6x^2 + 5x`	`> 0`
`x (x^2 – 6x + 5)`	`> 0`
`x (x – 5)(x – 1)`	`> 0`

`:.\ 0 < x < 1\ \ text(or)\ \ x > 5`

Functions, EXT1 F1 2009 HSC 1d

Solve the inequality `(x + 3)/(2x) > 1`. (3 marks)

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`0 < x < 3`

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`text(Solution 1)`

`(2x)^2 xx (x + 3)/(2x)`	`> (2x)^2`
`2x (x + 3)`	`> 4x^2`
`2x^2 + 6x`	`> 4x^2`
`2x^2\ – 6x`	`< 0`
`2x (x\ – 3)`	`< 0`

`:.\ {x: 0 < x < 3}`

`text(Solution 2)`

`text(If)\ \ x > 0,`

`x + 3`	`> 2x`
`x`	`< 3`

`:.\ 0 < x < 3`

`text(If)\ \ x < 0,`

`x + 3`	`< 2x`
`x`	`> 3\ \ \ =>\ text(No solution)`

`:.\ {x: 0 < x < 3}`

Functions, EXT1 F1 2013 HSC 10 MC

Which inequality has the same solution as `|\ x + 2\ | + |\ x- 3\ | = 5`?

`5/(3 - x) >= 1`
`1/(x - 3)\ - 1/(x + 2) <= 0`
`x^2 - x - 6 <= 0`
`|\ 2x - 1\ | >= 5`

Show Answers Only

`C`

Show Worked Solution

♦♦ Mean mark 39%
COMMENT: Note that the quick elimination of `A, B` and `D` is sufficient to get to the correct answer without proving `C` (although we have done this in the solution).

`text(In)\ A\ text(and)\ B, \ x ≠ 3\ text(but when)\ x=3,`

`|\ 3 + 2\ | + |\ 3 – 3\ | = 5\ \ text(is correct.)`

`:.\ text(Not)\ \ A\ \ text(or)\ \ B.`

`text(Consider)\ D`

`x -> oo\ text(satisfies)\ |\ 2x – 1\ | >= 5,\ \ text(but)`

`text(obviously not)\ |\ x + 2\ | + |\ x – 3\ | = 5.`

`text(Consider)\ C`

`x^2 – x – 6`	`<= 0`
`(x – 3)(x + 2)`	`<= 0`

`text(True when)\ \ \ -2 <= x <= 3.`

`text(In this range,)`

`(x + 2) >= 0\ \ text(and)\ \ (x – 3)<= 0`

`:.\ text(We can write)`

`\|\ x + 2\ \| + \|\ x – 3\ \|`	`= (x + 2)\ – (x – 3)`
	`= x + 2 – x + 3`
	`= 5`

`:. C\ text(has the same solution)`

`=> C\ text(is correct.)`

Functions, EXT1 F1 2010 HSC 1d

Solve `3/(x+2) < 4`. (3 marks)

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`x < -2\ \ text(or)\ \ x > -5/4`

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`text(Solution 1)`

`3/(x + 2) < 4`

`text(Multiply b.s. by)\ \ (x + 2)^2`

`3(x + 2)`	`< 4(x + 2)^2`
`3x + 6`	`< 4 (x^2 + 4x + 4)`
`3x + 6`	`< 4x^2 + 16x + 16`

`4x^2 + 13x + 10`	`> 0`
`(4x + 5)(x + 2)`	`> 0`

`text(LHS)\ = 0\ \ text(when)\ \ x = -5/4\ \ text(or)\ \ -2`

`text(From graph)`

`x < -2\ \ text(or)\ \ x > -5/4`

`text(Alternate Solution)`

`text(If)\ \ x + 2 > 0\ \ \ \ text{(i.e.}\ \ x > –2 text{)}`

`3`	`< 4(x + 2)`
`3`	`< 4x + 8`
`4x`	`> -5`
`x`	`> -5/4`

`text(If)\ \ x + 2 < 0\ \ \ \ text{(i.e.}\ x < –2 text{)}`

`3`	`> 4 (x + 2)`
`3`	`> 4x + 8`
`4x`	`< -5`
`x`	`< -5/4`
`:. x`	`< –2\ \ \ \ text{(satisfies both)}`

`:.\ x < –2\ \ text(or)\ \ x > –5/4`

Functions, EXT1 F1 2012 HSC 11c

Solve `x/(x - 3) < 2`. (3 marks)

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`x<3\ \ text(or)\ \ x>6`

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`text(Solution 1)`

`x/(x – 3) < 2`

`text(When)\ \ x – 3 > 0,\ \ \ (text(i.e.)\ \ x > 3)`

`x`	`< 2 ( x – 3)`
`x`	`< 2x\ – 6`
`=>x`	`>6\ \ \ text{(satisfies both)}`

`text(When)\ \ x\ – 3 < 0,\ \ \ (text(i.e.)\ \ x<3)`

`x`	`>2 (x – 3)`
`x`	`> 2x – 6`
`x`	`<6`
`=> x`	`<3\ \ \ text{(satisfies both)}`

`:.\ text(Equation is correct for)\ x<3\ text(or)\ x>6`

`text(Solution 2)`

`x/((x\ – 3)) < 2`

`text(Multiply b.s. by)\ \ (x-3)^2`

`x(x – 3)`	`< 2(x^2 – 6x + 9)`
`x^2 – 3x`	`< 2x^2 – 12x + 18`
`x^2 – 9x + 18`	`>0`
`(x – 3)(x – 6)`	`>0`

`:.\ text(Equation correct for)\ x<3\ \ text(or)\ \ x>6`

Functions, EXT1 F1 2011 HSC 1c

Solve `(4-x)/x <1`. (3 marks)

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`x<0\ \ text(or)\ \ x>2`

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`text(Solution 1)`

`(4-x)/x < 1`

`text(If)\ x<0,\ \ \ \ \ 4-x`	`> x`
`2x`	`< 4`
`x`	`<2`

`=> x<0\ \ \ text{(satisfies both)}`

`text(If)\ x>0,\ \ \ \ \ 4-x`	`<x`
`2x`	`>4`
`x`	`>2`

`=> x>2\ \ \ text{(satisfies both)}`

`:.\ x < 0\ \ text(or)\ \ x > 2`

`text(Solution 2)`

`text(Multiply both sides by)\ \ x^2`

`x(4-x)`	`< x^2`
`4x-x^2`	`< x^2`
`2x^2-4x`	`>0`
`2x(x-2)`	`>0`

`text(From graph)`

`x<0\ \ text(or)\ \ x >2`

Functions, EXT1* F1 2009 HSC 3c

Shade the region in the plane defined by `y >= 0` and `y <= 4-x^2`. (2 marks)

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`text(Shaded area is region where)`

`y >= 0\ text(and)\ y >= 4-x^2`

Show Worked Solution

COMMENT: This past “Advanced” HSC question now fits into the Ext1 (new) syllabus.

`text(Shaded area is region where)`

`y >= 0\ \ text(and)\ \ y >= 4-x^2`

Functions, EXT1* F1 2011 HSC 4e

The diagram shows the graphs `y = |\ x\ |\ - 2` and `y = 4- x^2`.

Write down inequalities that together describe the shaded region. (2 marks)

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`text(Inequalities are)`

`y <= 4\ – x^2`

`y >= |\ x\ |\ – 2`

Show Worked Solution

♦ Mean mark 46%.

`text(Inequalities are)`

`y <= 4 – x^2`

`y >= |\ x\ |\ – 2`

Functions, EXT1* F1 2012 HSC 11b

Solve `|\ 3x -1\ | < 2` (2 marks)

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` -1/3 < x < 1 `

Show Worked Solution

MARKER’S COMMENT: Note that both conditions must be satisfied! Dealing with negative signs and division for inequalities produced many errors.

`|\ 3x -1\ | < 2`

`3x -1`	`<2`	`\ \ \ \ \-(3x -1)`	`< 2`
`3x`	`<3`	`-3x + 1`	`< 2`
`x`	`< 1`	`3x`	`> -1`
		`x`	`> -1/3`

`:. -1/3 < x < 1`

Functions, EXT1* F1 2012 HSC 8 MC

The diagram shows the region enclosed by `y = x- 2` and `y^2 = 4-x`.

Which of the following pairs of inequalities describes the shaded region in the diagram?

`y^2 <= 4-x\ \ and\ \ y <= x-2`
`y^2 <= 4-x\ \ and\ \ y >= x-2`
`y^2 >= 4-x\ \ and\ \ y<= x-2`
`y^2 >= 4-x\ \ and\ \ y >= x-2`

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`A`

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♦ Mean mark 44%.

`text(Using information from diagram)`

`(3,0)\ text(is in the shaded region)`

`text{Substituting (3,0) into}\ \ \ y^2<=4-x,\ \ \ 0 <= 4-3 => text(true)`

`:.\ text(Cannot be)\ C\ text(or)\ D`

`text(Similarly)`

`(3,0)\ text(must satisfy other inequality)`

`text(i.e.)\ \ y <= x-2\ \ text(becomes)\ \ 0<= 3-2 =>\ text(true)`

`=> A`

Functions, EXT1* F1 2013 HSC 11g

Sketch the region defined by `(x-2)^2 + ( y-3)^2 >= 4`. (3 marks)

--- 10 WORK AREA LINES (style=lined) ---

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`text(The region is the exterior of a circle,)`

COMMENT: This past “Advanced” HSC question now fits into the Ext1 (new) syllabus.

`text(centre)\ text{(2,3)}\ text(and radius 2.)`