When \(2x^3-x^2+p x-6\) is divided by \(x+2\) the remainder is \(-4\). What is the value of \(p\) ?
- \(-11\)
- \(-7\)
- \(-5\)
- \(-2\)
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When \(2x^3-x^2+p x-6\) is divided by \(x+2\) the remainder is \(-4\). What is the value of \(p\) ?
\(A\)
\(\text{Since}\ (2x^3-x^2+p x-6)\ ÷\ (x+2)=-4 \ \ \Rightarrow\ \ P(-2)=-4\)
\(2\times (-2)^3-(-2)^2-2p-6\) | \(=-4\) | |
\(-16-4-2p-6\) | \(=-4\) | |
\(2p\) | \(=-22\) | |
\(p\) | \(=-11\) |
\(\Rightarrow A\)
Consider the polynomial
\(P(x)=x^3+a x^2+b x-12\),
where \(a\) and \(b\) are real numbers.
It is given that \(x+1\) is a factor of \(P(x)\) and that, when \(P(x)\) is divided by \(x-2\), the remainder is \(-18\) .
Find \(a\) and \(b\). (3 marks)
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\(a=2, \ b=-11\)
\((x+1)\ \ \text{is a factor of}\ P(x)\ \ \Rightarrow\ \ P(-1)=0 \)
\(0\) | \(=(-1)^3+a-b-12\) | |
\(a-b\) | \(=13\ \ …\ (1) \) |
\(P(x) ÷ (x-2) \ \text{has a remainder of}\ -18 \ \Rightarrow\ \ P(2)=-18 \)
\(-18\) | \(=8+4a+2b-12\) | |
\(4a+2b\) | \(=-14\) | |
\(2a+b\) | \(=-7\ \ …\ (2) \) |
\(\text{Add}\ \ (1) + (2): \)
\(3a=6\ \ \Rightarrow\ \ a=2\)
\(\text{Substitute}\ \ a=2\ \ \text{into (1):} \)
\(2-b=13\ \ \Rightarrow\ \ b=-11 \)
\(\therefore a=2, \ b=-11\)
Let `P(x)` be a polynomial of degree 5. When `P(x)` is divided by the polynomial `Q(x)`, the remainder is `2x+5`.
Which of the following is true about the degree of `Q`?
`D`
`text{Given}\ \ P(x)\ \ text{has degree 5}`
`P(x) -: Q(x)\ \ text{has remainder}\ \ 2x+5`
`text{Consider examples to resolve possibilities:}`
`text{eg.}\ \ x^5+2x+5 -: x^3 = x^2+\ text{remainder}\ 2x+5`
`:.\ text{Degree must be 2 is incorrect}`
`Q(x)\ \ text{can have a degree of 2, 3 or 4}`
`=>D`
Let `p(x)=x^{3}-2 a x^{2}+x-1`. When `p(x)` is divided by `x+2`, the remainder is 5.
The value of `a` is
`D`
`P(-2)` | `=5` | |
`5` | `=(-2)^3-2a(-2)^2-2-1` | |
`5` | `=-8-8a-2-1` | |
`8a` | `=-16` | |
`:.a` | `=-2` |
`=>D`
What is the remainder when `P(x) = -x^3-2x^2-3x + 8` is divided by `x + 2`?
`D`
`P(-2)` | `= -(-2)^3-2(-2)^2-3(-2) + 8` |
`= 8-8 + 6 + 8` | |
`= 14` |
`=> D`
What is the remainder when `2x^3-10x^2 + 6x + 2` is divided by `x-2`?
`B`
`P(2)` | `= 2 · 2^3-10 · 2^2 + 6 · 2 + 2` |
`= -10` |
`=> B`
The polynomial `P(x) = x^2 + ax + b` has a zero at `x = 2`. When `P(x)` is divided by `x + 1`, the remainder is `18`.
Find the values of `a` and `b`. (3 marks)
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`a = -7\ \ text(and)\ \ b = 10`
`P(x) = x^2 + ax + b`
`text(S)text(ince there is a zero at)\ \ x = 2,`
`P(2)` | `=0` | |
`2^2 + 2a + b` | `= 0` | |
`2a + b` | `= -4` | `…\ (1)` |
`P(-1) = 18,`
`(-1)^2-a + b` | `= 18` | |
`-a + b` | `= 17` | `…\ (2)` |
`text(Subtract)\ \ (1)-(2),`
`3a` | `= -21` |
`a` | `= -7` |
`text(Substitute)\ \ a = -7\ \ text{into (1),}`
`2(-7) + b` | `= -4` |
`b` | `= 10` |
`:.a = -7\ \ text(and)\ \ b = 10`
Let `P(x) = (x + 1) (x − 3)Q(x) + a(x + 1) + b`, where `Q(x)` is a polynomial and `a` and `b` are real numbers.
When `P(x)` is divided by `(x + 1)` the remainder is `−11`.
When `P(x)` is divided by `(x − 3)` the remainder is `1`.
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i. `P(x)= (x + 1) (x − 3)Q(x) + a(x + 1) + b`
`P(-1)=-11`
`-11=(−1 + 1)(−1 − 3)Q(x) + a(−1 + 1) + b`
`-11=(0)(-4)Q(x)+a(0)+b`
`:.b = −11`
(ii) `P(3) = 1`
`:.(3 + 1)(3 − 3)Q(x) + a(3 + 1) −11 = 1`
`4a` | `= 12` |
`a` | `= 3` |
`text(When)\ \ P(x)\ \ text(is divided by)\ \ (x + 1)(x − 3)`
`R(x)` | `= a(x + 1) + b` |
`= 3(x + 1) − 11` | |
`= 3x + 3 − 11` | |
`= 3x − 8` |
What is the remainder when `x^3-6x` is divided by `x + 3`?
`A`
`text(Remainder)` | `= P(-3)` |
`= (-3)^3-6(-3)` | |
`= -27 + 18` | |
`= -9` |
`=> A`
The polynomial `x^3` is divided by `x + 3`. Calculate the remainder. (2 marks)
`-27`
`P(-3)` | `= (-3)^3` |
`= -27` |
`:.\ text(Remainder when)\ x^3 -: (x + 3) = -27`
The remainder when the polynomial `P(x) = x^4-8x^3-7x^2 + 3` is divided by `x^2 + x` is `ax + 3`.
What is the value of `a`?
`C`
`P(x) = x^4-8x^3-7x^2 + 3`
`text(Given)\ \ P(x)` | `= (x^2 + x) *Q(x) + ax + 3` |
`= x (x + 1) Q(x) + ax + 3` |
`P(-1) = 1 + 8-7 + 3 = 5`
`:. -a + 3` | `= 5` |
`a` | `= -2` |
`=> C`
The polynomial `p(x) = x^3-ax + b` has a remainder of `2` when divided by `(x-1)` and a remainder of `5` when divided by `(x + 2)`.
Find the values of `a` and `b`. (3 marks)
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`a` | `= 4` |
`b` | `= 5` |
`p(x)` | `= x^3-ax + b` |
`P(1)` | `= 2` |
`1-a + b` | `= 2` |
`b` | `= a+1\ \ \ …\ text{(1)}` |
`P (-2)` | `= 5` |
`-8 + 2a + b` | `= 5` |
`2a + b` | `= 13\ \ \ …\ text{(2)}` |
`text(Substitute)\ \ b = a+1\ \ text(into)\ \ text{(2)}`
`2a + a+1` | `= 13` |
`3a` | `= 12` |
`:. a` | `= 4` |
`:. b` | `= 5` |
Let `P(x) = (x + 1)(x-3) Q(x) + ax + b`,
where `Q(x)` is a polynomial and `a` and `b` are real numbers.
The polynomial `P(x)` has a factor of `x-3`.
When `P(x)` is divided by `x + 1` the remainder is `8`.
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i. `P(x) = (x+1)(x-3)Q(x) + ax + b`
`(x-3)\ \ text{is a factor (given)}`
`:. P (3)` | `= 0` |
`3a + b` | `= 0\ \ \ …\ text{(1)}` |
`P(x) ÷ (x+1)=8\ \ \ text{(given)}`
`:.P(-1)` | `= 8` |
`-a + b` | `= 8\ \ \ …\ text{(2)}` |
`text{Subtract (1) – (2)}`
`4a` | `= -8` |
`a` | `= -2` |
`text(Substitute)\ \ a = -2\ \ text{into (1)}`
`-6 + b` | `= 0` |
`b` | `= 6` |
`:. a= – 2, \ b=6`
ii. `P(x) -: (x + 1)(x-3)`
`= ((x+1)(x-3)Q(x)-2x + 6)/((x+1)(x-3))`
`= Q(x) + (-2x + 6)/((x+1)(x-3))`
`:.\ text(Remainder is)\ \ -2x + 6`
Let `P(x) = x^3-ax^2 + x` be a polynomial, where `a` is a real number.
When `P(x)` is divided by `x-3` the remainder is `12`.
Find the remainder when `P(x)` is divided by `x + 1`. (3 marks)
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`-4`
`P(x) = x^3 – ax^2 + x`
`text(S)text(ince)\ \ P(x) -: (x – 3)\ \ text(has remainder 12,)`
`P(3) = 3^3-a xx 3^2 + 3` | `=12` |
`27-9a + 3` | `= 12` |
`9a` | `= 18` |
`a` | `=2` |
`:.\ P(x) = x^3-2x^2 + x`
`text(Remainder)\ \ P(x) -: (x + 1)\ \ text(is)\ \ P(–1)`
`P(-1)` | `= (-1)^3-2(-1)^2-1` |
`= – 4` |
When the polynomial `P(x)` is divided by `(x + 1)(x-3)`, the remainder is `2x + 7`.
What is the remainder when `P(x)` is divided by `x-3`?
`D`
`text(Let)\ \ P(x) =A(x) * Q(x) + R(x)`
`text(where)\ \ A(x) = (x + 1)(x-3),\ text(and)\ \ R(x)=2x+7`
`text(When)\ \ P(x) -: (x-3),\ text(remainder) = P(3)`
`P(3)` | `= 0 + R(3)` |
`= (2 xx 3) + 7` | |
`= 13` |
`=> D`