Consider the relation \(x\, \arcsin \left(y^2\right)=\pi\).
Use implicit differentiation to find \(\dfrac{d y}{d x}\) at the point \(\left(6, \dfrac{1}{\sqrt{2}}\right)\).
Give your answer in the form \(-\dfrac{\pi \sqrt{a}}{b}\), where \(a, b \in Z^{+}\). (3 marks)
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