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Calculus, MET1 2024 VCAA 7

Part of the graph of  \(f:[-\pi, \pi] \rightarrow R, f(x)=x \sin (x)\)  is shown below.

  1. Use the trapezium rule with a step size of \(\dfrac{\pi}{3}\) to determine an approximation of the total area between the graph of  \(y=f(x)\) and the \(x\)-axis over the interval  \(x \in[0, \pi]\).   (3 marks)

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  2.   i. Find \(f^{\prime}(x)\).   (1 mark)

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  3.  ii. Determine the range of \(f^{\prime}(x)\) over the interval \(\left[\dfrac{\pi}{2}, \dfrac{2 \pi}{3}\right]\).   (1 mark)

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  4. iii. Hence, verify that \(f(x)\) has a stationary point for \(x \in\left[\dfrac{\pi}{2}, \dfrac{2 \pi}{3}\right]\).   (1 mark)

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  5. On the set of axes below, sketch the graph of  \(y=f^{\prime}(x)\)  on the domain \([-\pi, \pi]\), labelling the endpoints with their coordinates.
  6. You may use the fact that the graph of  \(y=f^{\prime}(x)\)  has a local minimum at approximately \((-1.1,-1.4)\) and a local maximum at approximately \((1.1,1.4)\).   (3 marks)

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a.    \(\dfrac{\sqrt{3}\pi^2}{6}\)

bi.   \(x\cos(x)+\sin(x)\)

bii.  \(\left[-\dfrac{\pi}{3}+\dfrac{\sqrt{3}}{3},\ 1\right]\)

biii. \(\text{In the interval }\left[\dfrac{\pi}{2}, \dfrac{2\pi}{3}\right],\ f^{\prime}(x)\ \text{changes from positive to negative.}\)

\(f^{\prime}(x)=0\ \text{at some point in the interval.}\)

\(\therefore\ \text{A stationary point must exist in the given range.}\)

c. 

Show Worked Solution

a.     \(A\) \(=\dfrac{\pi}{3}\times\dfrac{1}{2}\left(f(0)+2f\left(\dfrac{\pi}{3}\right)+2f\left(\dfrac{2\pi}{3}\right)+f(\pi)\right)\)
    \(=\dfrac{\pi}{6}\left(0+2\times \dfrac{\pi}{3}\sin\left(\dfrac{\pi}{3}\right)+2\times \dfrac{2\pi}{3}\sin\left(\dfrac{2\pi}{3}\right)+\pi\sin({\pi})\right)\)
    \(=\dfrac{\pi}{6}\left(2\times \dfrac{\pi}{3}\times\dfrac{\sqrt{3}}{2}+2\times\dfrac{2\pi}{3}\times \dfrac{\sqrt{3}}{2}+0\right)\)
    \(=\dfrac{\pi}{6}\left(\dfrac{2\pi\sqrt{3}}{6}+\dfrac{4\pi\sqrt{3}}{6}\right)\)
    \(=\dfrac{\pi}{6}\times \dfrac{6\pi\sqrt{3}}{6}\)
    \(=\dfrac{\sqrt{3}\pi^2}{6}\)
♦ Mean mark (a) 48%.
bi.    \(f(x)\) \(=x\sin(x)\)
  \(f^{\prime}(x)\) \(=x\cos(x)+\sin(x)\)

 

b.ii.  \(\text{Gradient in given range gradually decreases.}\)

\(\text{Range of}\ f^{\prime}(x)\ \text{will be defined by the endpoints.}\)

  \(f^{\prime}\left(\dfrac{\pi}{2}\right)\) \(=1\)
  \(f^{\prime}\left(\dfrac{2\pi}{3}\right)\) \(=\dfrac{2\pi}{3}\left(\dfrac{-1}{2}+\dfrac{\sqrt{3}}{2}\right)=-\dfrac{\pi}{3}+\dfrac{\sqrt{3}}{3}\)

 
\(\therefore\ \text{Range of }\ f^{\prime} (x)\ \text{is}\quad\left[-\dfrac{\pi}{3}+\dfrac{\sqrt{3}}{3},\ 1\right]\)

♦♦♦ Mean mark (b.ii.) 20%.
♦♦♦ Mean mark (b.iii.) 12%.

 
biii. \(\text{In the interval }\left[\dfrac{\pi}{2}, \dfrac{2\pi}{3}\right],\ f^{\prime}(x)\ \text{changes from positive to negative.}\)

\(f^{\prime}(x)=0\ \text{at some point in the interval.}\)

\(\therefore\ \text{A stationary point must exist in the given range.}\)

 
c.   
\(f^{\prime}(\pi)=\pi\cos(\pi)+\sin(\pi)=-\pi\)

\(f^{\prime}(-\pi)=-\pi\cos(-\pi)+\sin(-\pi)=\pi\)

\(\therefore\ \text{Endpoints are }\ (-\pi,\ \pi)\ \text{and}\ (\pi,\ -\pi).\)

♦♦ Mean mark (c) 36%.

Filed Under: Curve Sketching, The Derivative Function and its Graph, Trapezium Rule and Newton Tagged With: Band 4, Band 5, Band 6, smc-2830-20-Find f'(x) graph given f(x), smc-2830-50-SP problems, smc-5145-04-Trapezium rule, smc-5145-20-No table, smc-724-45-Other graphs, smc-744-40-Product Rule

Calculus, MET2 2024 VCAA 13 MC

The function  \(f:(0, \infty) \rightarrow R, f(x)=\dfrac{x}{2}+\dfrac{2}{x}\)  is mapped to the function \(g\) with the following sequence of transformations:

  1. dilation by a factor of 3 from the \(y\)-axis
  2. translation by 1 unit in the negative direction of the \(y\)-axis.

The function \(g\) has a local minimum at the point with the coordinates

  1. \((6,1)\)
  2. \(\left(\dfrac{2}{3}, 1\right)\)
  3. \((2,5)\)
  4. \(\left(2,-\dfrac{1}{3}\right)\)
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\(A\)

Show Worked Solution

\(\text{Dilate by a factor of 3 from the}\ y\text{-axis:}\)

\(f(x) \rightarrow f_1(x)=\dfrac{\frac{x}{3}}{2}+\dfrac{2}{\frac{x}{3}}=\dfrac{x}{6}+\dfrac{6}{x}\)

\(\text{Translate 1 unit down:}\)

\(f_1(x) \rightarrow g(x)=\dfrac{x}{6}+\dfrac{6}{x}-1\)

\(g'(x)=\dfrac{1}{6}-6x^{-2}\)

♦ Mean mark 45%.
 

\(\Rightarrow A\)

Filed Under: The Derivative Function and its Graph, Transformations Tagged With: Band 5, smc-2830-20-Find f'(x) graph given f(x), smc-2830-50-SP problems, smc-753-40-Combinations, smc-753-85-Other functions

Calculus, MET2 2022 VCAA 7 MC

The graph of `y=f(x)` is shown below.
 

The graph of `y=f^{\prime}(x)`, the first derivative of `f(x)` with respect to `x` could be
 

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`E`

Show Worked Solution

`=>E`

Filed Under: The Derivative Function and its Graph Tagged With: Band 4, smc-2830-20-Find f'(x) graph given f(x)

Calculus, MET2 2021 VCAA 8 MC

The graph of the function  `f`  is shown below.
 

The graph corresponding to  `f^{′}` is
 


 


 

Show Answers Only

`E`

Show Worked Solution

`text(By elimination:)`

♦ Mean mark 40%.

`text{As} \ \ x to a^+ \ , \ f^{′}(x) to ∞`

`:. \ text{Eliminate}\ A, B, C`

`f(x) \ text{exists for} \ x ∈ (a,∞)`

`f^{′}(x) \ text{only exists for} \ \ x ∈ (a, ∞)`

`:. \ text{Eliminate}\ D`

`=> E`

Filed Under: The Derivative Function and its Graph Tagged With: Band 5, smc-2830-20-Find f'(x) graph given f(x)

Calculus, MET2 2019 VCAA 16 MC

Part of the graph of  `y = f(x)`  is shown below.
 

The corresponding part of the graph of  `y = f^{\prime}(x)`  is best represented by

A.    B.   
C.    D.   
E.       
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`A`

Show Worked Solution

`text(By Elimination):`

`text(S.P. at)\ \ x = 5`

`=> f^{\prime}(x) = 0\ \ text(when)\ \ x = 0`

`text(Eliminate  C, E)`

`text(Gradient is negative when)\ \ x < 5,\ \ text(and positive when)\ \ x >5`

`text(Eliminate  B, D)`
 

`=>   A`

Filed Under: The Derivative Function and its Graph Tagged With: Band 4, smc-2830-20-Find f'(x) graph given f(x)

Calculus, MET2 2008 VCAA 19 MC

The graph of a function  `f` is shown below.

VCAA 2008 19mc

The graph of an antiderivative of  `f` could be

VCAA 2008 19mci

VCAA 2008 19mcii 

VCAA 2008 19mciii

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`B`

Show Worked Solution

`text(S)text(ince)\ \ f(x)>0\ \ text(for all)\ x,\ text(the)`

♦ Mean mark 50%.

`text(antiderivative function has no stationary)`

`text(points.)`

`=>\ text(Only B or E are possibilities.)`

 

`text(Also, the antiderivative function must have)`

`text(an increasing gradient for all)\ x.`

`=>   B`

Filed Under: The Derivative Function and its Graph Tagged With: Band 5, smc-2830-20-Find f'(x) graph given f(x)

Calculus, MET2 2016 VCAA 3 MC

Part of the graph  `y = f(x)`  of the polynomial function  `f` is shown below
 


 

`f prime (x) < 0`  for

  1. `x ∈ (−2, 0) uu (1/3, oo)`
  2. `x ∈ (−9, 100/27)`
  3. `x ∈ (−oo, −2) uu (1/3, oo)`
  4. `x ∈ (−2, 1/3)`
  5. `x ∈ (−oo, −2] uu (1, oo)`
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`C`

Show Worked Solution

`text(Outlining the sections of negative gradient:)`

`f prime (x) < 0`

`=>   C`

Filed Under: The Derivative Function and its Graph Tagged With: Band 3, smc-2830-20-Find f'(x) graph given f(x)

Calculus, MET2 2011 VCAA 9 MC

The graph of the function  `y = f(x)`  is shown below.
 

met1-2011-vcaa-9-mc
 

Which if the following could be the graph of the derivative function  `y = f′(x)`?

met1-2011-vcaa-9-mc-abc

met1-2011-vcaa-9-mc-de1

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`=> B`

Show Worked Solution

`text(Stationary points at)\ \ x = – 3, 0`

`:. f′(x)\ \ text(has)\ x text(-intercepts at)\ -3, 0.`

`text(Only)\ B, C or D\ text(possible).`

`text(By inspection of the)\ \ f(x)\ \ text(graph:)`

`f′(x) > 0quadtext(for)quadx < −3`

`text(Only)\ B\ text(satisfies.)`

`=> B`

Filed Under: The Derivative Function and its Graph Tagged With: Band 3, smc-2830-20-Find f'(x) graph given f(x)

Calculus, MET1 2007 VCAA 3

The diagram shows the graph of a function with domain `R`.

MET1 2007 VCAA Q3

  1. For the graph shown above, sketch on the same set of axes the graph of the derivative function.   (3 marks)

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  2. Write down the domain of the derivative function.   (1 mark)

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  1.  
    MET1 2007 VCAA Q3 Answer
  2. `R\ text(\)\ {0,3}`
Show Worked Solution
a.    MET1 2007 VCAA Q3 Answer
♦ Part (a) mean mark 42%, and part (b) mean mark 45%.

 

b.   `text(Derivative does not exist at either sharp)`

`text(points or discontinuous points.)`

`:. R\ text(\)\ {0,3}`

Filed Under: The Derivative Function and its Graph Tagged With: Band 5, smc-2830-20-Find f'(x) graph given f(x)

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