The table shows four separate tests used to identify a dilute, aqueous sample of a compound.
\begin{array} {|c|l|l|}
\hline
\rule{0pt}{2.5ex} \textbf{Test Number} \rule[-1ex]{0pt}{0pt} & \quad \quad \quad \quad \quad \textbf{Test} & \quad \quad \quad \textbf{Observation}\\
\hline
\rule{0pt}{2.5ex} 1\rule[-1ex]{0pt}{0pt} & \text{Test with Red litmus} & \text{Stays red}\\
\hline
\rule{0pt}{2.5ex} 2 \rule[-1ex]{0pt}{0pt} & \text{Add \( \ce{Ba}^{2+} \) ions to a sample} & \text{White precipitate formed}\\
\hline
\rule{0pt}{2.5ex} 3 \rule[-1ex]{0pt}{0pt} & \text{Add \( \ce{OH}^{-} \) ions to a sample}& \text{Brown precipitate formed} \\
\hline
\rule{0pt}{2.5ex} 4 \rule[-1ex]{0pt}{0pt} & \text{Add \( \ce{Cl}^{-}\) ions to a sample}& \text{White precipitate formed}\\
\hline
\end{array}
Which compound would produce the observations shown?
- Silver sulfate
- Lead(\(\text{II}\)) acetate
- Iron(\(\text{II}\)) bromide
- Magnesium carbonate