An electron gun fires a beam of electrons at 2.0 × 10\(^6\) m s\(^{-1}\) through a pair of parallel charged plates towards a screen that is 30 mm from the end of the plates as shown. There is a uniform electric field between the plates of 1.5 × 10\(^4\) N C\(^{-1}\). The plates are 5.0 mm wide and 20 mm apart. The electron beam enters mid-way between the plates. \(X\) marks the spot on the screen where an undeflected beam would strike. Ignore gravitational effects on the electron beam. --- 4 WORK AREA LINES (style=lined) --- --- 4 WORK AREA LINES (style=lined) --- --- 6 WORK AREA LINES (style=lined) ---
PHYSICS, M6 2023 HSC 12 MC
Figure \(\text{I}\) shows a positively charged particle accelerating freely from \(X\) to \(Y\), between oppositely charged plates. The change in the particle's kinetic energy is \(W\).
The distance between the plates is then doubled as shown in Figure \(\text{II}\) . The same charge accelerates from rest over the same distance from \(X\) to \(Y\).
What is the change in kinetic energy of the positively charged particle shown in Figure \(\text{II}\) ?
- \(W\)
- \(\dfrac{W}{2}\)
- \(\sqrt{W}\)
- \(2 W\)
PHYSICS, M6 EQ-Bank 22
An 'electron gun' like that used by JJ Thomson is shown.
Electrons leave the cathode and are accelerated towards the anode.
- Show that the acceleration of the electrons as they just leave the cathode is `4 × 10^(16) \ text{m s}^(-2)`. (2 marks)
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- Calculate the velocity of an electron as it reaches the anode. (2 marks)
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PHYSICS, M6 2015 HSC 24
A part of a cathode ray oscilloscope was represented on a website as shown.
Electrons leave the cathode and are accelerated towards the anode.
- Explain why the representation of the path of the electron between the deflection plates is inaccurate. (3 marks)
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- Calculate the force on an electron due to the electric field between the cathode and the anode. (2 marks)
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- Calculate the velocity of an electron as it reaches the anode. (2 marks)
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PHYSICS, M6 2020 HSC 34
A charged particle, `q_1`, is fired midway between oppositely charged plates `X` and `Y`, as shown in Figure 1. The voltage between the plates is `V` volts.
The particle strikes plate `Y` at point `P`, a horizontal distance `s` from the edge of the plate. Ignore the effect of gravity.
Plate `Y` is then moved to the position shown in Figure 2, with the voltage between the plates remaining the same.
An identical particle, `q_2`, is fired into the electric field at the same velocity, entering the field at the same distance from plate `X` as `q_1`.
- Compare the work done on `q_1` and `q_2`. (3 marks)
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- Compare the horizontal distances travelled by `q_1` and `q_2` in the electric field. (3 marks)
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PHYSICS M6 2022 HSC 18 MC
A charged oil droplet was observed between metal plates, as shown.
While the switch was open, the oil droplet moved downwards at a constant speed. After the switch was closed, the oil droplet moved upwards at the same constant speed.
Assume that the only three forces that may act on the oil droplet are the force of gravity, the force due to the electric field and the frictional force between the air and the oil droplet. The magnitudes of these forces are `F_G` (due to gravity), `F_E` (due to the electric field) and `F_F` (due to the frictional force).
Which row of the table shows all the forces affecting the motion of the oil droplet in the direction indicated, and the relationship between these forces?
\begin{align*}
\begin{array}{l}
\rule{0pt}{2.5ex} \ \rule[-1ex]{0pt}{0pt}& \\
\rule{0pt}{2.5ex}\textbf{A.}\rule[-1ex]{0pt}{0pt}\\
\rule{0pt}{2.5ex}\textbf{B.}\rule[-1ex]{0pt}{0pt}\\
\rule{0pt}{2.5ex}\textbf{C.}\rule[-1ex]{0pt}{0pt}\\
\rule{0pt}{2.5ex}\textbf{D.}\rule[-1ex]{0pt}{0pt}\\
\end{array}
\begin{array}{|c|c|}
\hline
\rule{0pt}{2.5ex}\text{Downwards motion}\rule[-1ex]{0pt}{0pt}& \text{Upwards motion} \\
\hline
\rule{0pt}{2.5ex}F_{\text{G}}>F_{\text{F}}\rule[-1ex]{0pt}{0pt}&F_{\text{E}}>F_{\text{F}}\\
\hline
\rule{0pt}{2.5ex}F_{\text{G}}>F_{\text{F}}\rule[-1ex]{0pt}{0pt}& F_{\text{E}}>F_{\text{G}}+F_{\text{F}}\\
\hline
\rule{0pt}{2.5ex}F_{\text{G}}=F_{\text{F}}\rule[-1ex]{0pt}{0pt}& F_{\text{G}}=F_{\text{E}} \\
\hline
\rule{0pt}{2.5ex}F_{\text{G}}=F_{\text{F}}\rule[-1ex]{0pt}{0pt}& F_{\text{E}}=F_{\text{G}}+F_{\text{F}} \\
\hline
\end{array}
\end{align*}
PHYSICS M6 2022 HSC 3 MC
A radioisotope emits radiation which is deflected by an electric field, as shown.
What type of radiation is this?
- Alpha
- Gamma
- Beta positive (positron)
- Beta negative (electron)
PHYSICS, M6 2019 HSC 16 MC
The diagram shows the trajectory of a particle with charge `q` and mass `m` when fired horizontally into a vacuum chamber, where it falls under the influence of gravity.
The horizontal distance, `d`, travelled by the particle is recorded.
The experiment is repeated with a uniform vertical electric field applied such that the particle travels the same horizontal distance, `d`, but strikes the upper surface of the chamber.
What is the magnitude of the electric field?
- `mgq`
- `2mgq`
- `(mg)/q`
- `(2mg)/q`
PHYSICS, M6 2021 HSC 30
In an experiment, a proton accelerates from rest between parallel charged plates. The spacing of the plates is 12 cm and the proton is initially positioned at an equal distance from both plates, as shown. Ignore the effect of gravity.
- The electrical potential energy of the proton is recorded in the following graph for the first 5 cm of its motion.
- On the graph, sketch the corresponding kinetic energy of the proton over the same distance. (2 marks)
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- The experiment is repeated using an electron in the place of the proton.
- Explain how the motion of the electron would differ from that of the proton. (3 marks)
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Show Answers Only
a.
b. Motions differs from proton motion:
→ The electron will move in the opposite direction to the proton as the sign of its charge is opposite.
→ The electron will experience a force equal in magnitude to the proton as its charge has the same magnitude.
→ Since the mass of the electron is significantly smaller, it will experience a much greater acceleration compared to the proton.
Show Worked Solution
a.
b. Motions differs from proton motion:
→ The electron will move in the opposite direction to the proton as the sign of its charge is opposite.
→ The electron will experience a force equal in magnitude to the proton as its charge has the same magnitude.
→ Since the mass of the electron is significantly smaller, it will experience a much greater acceleration compared to the proton.
PHYSICS, M6 2021 HSC 18 MC
An evacuated chamber contains a pair of parallel plates connected to a power supply and a switch which is initially closed.
A positively charged mass (•) falls within the chamber, under the influence of gravity, from the position shown.
When the mass has fallen half the height of the chamber, the switch is opened.
Which of the following correctly shows the trajectory of the mass?
PHYSICS, M6 2021 HSC 2 MC
A positively charged particle is moving at velocity, `v`, in an electric field as shown.
What is the direction of the force acting on the particle due to the electric field?
- Into the page
- Out of the page
- Up the page
- Down the page