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Data Analysis, SM-Bank 038

Jason recorded the following marks out of 100 in his last 8 class tests.
 

74,  65,  70,  72,  95,  68,  70,  64
 

  1. Which one of his marks is an outlier?  (1 mark)

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  2. If the outlier is removed, by how many marks does the mean change?  (2 marks)

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  3. Explain why it would be more appropriate to use the median rather than the mean when including the outlier in Jason's marks.  (2 marks)

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Show Answers Only

a.   `95`

b.   `72.25 \-\69 = 3.25\ text(marks)`

c.   “

Show Worked Solution

a.   `text(The test mark of 95 is significantly different from the other marks)`

`:.\  95\ text(is an outlier)`
 

b.  `text(Initial Mean)`

`text(Mean)` `=(74 + 65 + 70 + 72 + 95 + 68 + 70 + 64)/8`  
  `= 578/8`  
  `= 72.25`  

 
`text(Mean without outlier)`

`text(New Mean)` `=(74 + 65 + 70 + 72  + 68 + 70 + 64)/7`
  `= 483/7`
  `= 69`

`:.\ text(The mean decreases by)\ 3.25\ text(marks)`

c.   `text(Ordered marks):\  64, \ 65, \ 68, \  70, \ 70, \ 72, \ 74, \ 95 `

`:.\ text(When 95 is included, the median is 70 where as the mean is 72.25.)`

`72.25\ text(lies between his 6th and 7th scores and is, therefore, not a)`

`text(good measure of centre for Jason’s marks.)`

Filed Under: Data Analysis Tagged With: num-title-ct-core, smc-4224-20-Median, smc-4224-25-Mean, smc-4224-30-Outliers, smc-4224-50-Add/remove data

Data Analysis, SM_Bank 037

For the following set of data, state any outliers.  (1 mark)

3,  5,  7,  7,  9,  10,  18

Show Answers Only

`18`

Show Worked Solution

`text(The score of 18 is significantly different from the other scores)`

`:.\  18\ text(is an outlier)`

Filed Under: Data Analysis Tagged With: num-title-ct-core, smc-4224-30-Outliers

Statistics, STD2 S1 2007 HSC 24a

Consider the following set of scores:

`3, \ 5, \ 5, \ 6, \ 8, \ 8, \ 9, \ 10, \ 10, \ 50.` 

  1. Calculate the mean of the set of scores.   (1 mark)

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  2. What is the effect on the mean and on the median of removing the outlier?   (2 marks)

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Show Answers Only

a.    `11.4`

b.    `text{If the outlier (50) is removed, the mean}`

`text(would become lower.)`

`text(Median will NOT change.)`

Show Worked Solution

a.    `text(Total of scores)`

`= 3 + 5 + 5 + 6 + 8 + 8 + 9 + 10 + 10 +50`

`= 114`

`:.\ text(Mean) = 114/10 = 11.4`
  

b.   `text(Mean)`

`text{If the outlier (50) is removed, the mean}`

`text(would become lower.)`
 

`text(Median)`

`text(The current median (10 data points))`

`= text(5th + 6th)/2 = (8 + 8)/2 = 8`

`text(The new median (9 data points))`

`=\ text(5th value)= 8`

`:.\ text(Median will NOT change.)`

Filed Under: Data Analysis, Measures of Centre and Spread, Measures of Centre and Spread, Summary Statistics, Summary Statistics - No graph, Summary Statistics - No Graph, Summary Statistics (no graph) Tagged With: Band 3, Band 4, common-content, num-title-ct-core, num-title-qs-hsc, smc-1131-10-Mean, smc-1131-20-Median and Mode, smc-4224-25-Mean, smc-4224-30-Outliers, smc-4224-50-Add/remove data, smc-6312-10-Mean, smc-6312-20-Median and Mode, smc-6532-10-Mean, smc-6532-20-Median and Mode, smc-824-10-Mean, smc-824-20-Median and Mode, smc-999-10-Mean, smc-999-20-Median and Mode

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