Simplify \(\dfrac{x^2}{x^2-2 x-15}-\dfrac{x}{x+3}\). (2 marks)
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Simplify \(\dfrac{x^2}{x^2-2 x-15}-\dfrac{x}{x+3}\). (2 marks)
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\(\dfrac{5 x}{(x+3)(x-5)}\)
| \(\dfrac{x^2}{x^2-2 x-15}-\dfrac{x}{x+3}\) | \(=\dfrac{x^2}{(x+3)(x-5)}-\dfrac{x}{x+3}\) |
| \(=\dfrac{x^2-x(x-5)}{(x+3)(x-5)}\) | |
| \(=\dfrac{x^2-x^2+5 x}{(x+3)(x-5)}\) | |
| \(=\dfrac{5 x}{(x+3)(x-5)}\) |
Simplify \(\dfrac{p+1}{q-q^3} \ ÷ \ \dfrac{p^3+p^2}{q^2-q}\). (2 marks)
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\(\dfrac{1}{p^2(1+q)}\)
| \(\dfrac{p+1}{q-q^3} \ ÷ \ \dfrac{p^3+p^2}{q^2-q}\) | \(=\dfrac{p+1}{q\left(1-q^2\right)} \times \dfrac{q\left(1-q\right)}{p^2(p+1)}\) |
| \(=\dfrac{(1-q)}{(1+q)(1-q) p^2}\) | |
| \(=\dfrac{1}{p^2(1+q)}\) |
Simplify \(\dfrac{a^3 b-a b^3}{a^2+2 a b+b^2}\). (2 marks)
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\(\dfrac{a b(a-b)}{a+b}\)
| \(\dfrac{a^3 b-a b^3}{a^2+2 a b+b^2}\) | \(=\dfrac{a b\left(a^2-b^2\right)}{(a+b)^2}\) |
| \(=\dfrac{a b(a+b)(a-b)}{(a+b)^2}\) | |
| \(=\dfrac{a b(a-b)}{a+b}\) |
Fully simplify the expression \(\dfrac{4}{x^2-9}-\dfrac{2x+1}{x+3}\) (3 marks)
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\(\dfrac{-(2x-7)(x+1)}{(x^2-9)}\)
| \(\dfrac{4}{x^2-9}-\dfrac{2x+1}{x+3}\) | \(=\dfrac{4-(2x+1)(x-3)}{(x+3)(x-3)}\) | |
| \(=\dfrac{4-(2x^2-5x-3)}{(x+3)(x-3)}\) | ||
| \(=\dfrac{-(2x^2-5x-7)}{(x+3)(x-3)}\) | ||
| \(=\dfrac{-(2x-7)(x+1)}{(x^2-9)}\) |
Solve `x+(x-1)/2 = 9`. (2 marks)
`19/3`
| `x+(x-1)/2` | `=9` | |
| `2x + x-1` | `=18` | |
| `3x` | `=19` | |
| `x` | `=19/3` |
Simplify `(9x^2)/(x+3) -: (3x)/(x^2-9)`. (2 marks)
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`3x(x-3)`
| `(9x^2)/(x+3) -: (3x)/(x^2-9)` | `=(9x^2)/(x+3) xx (x^2-9)/(3x)` | |
| `=(9x^2)/(x+3) xx ((x-3)(x+3))/(3x)` | ||
| `=3x(x-3)` |
Simplify `(4p-12p^2)/3 xx (6p)/(3p^2-p)`. (2 marks)
`-8p`
| `(4p-12p^2)/3 xx (6p)/(3p^2-p)` | `= (4p(1-3p))/3 xx (6p)/(p(3p-1))` | |
| `= (8p(1-3p))/(3p-1)` | ||
| `=-8p` |
Find the reciprocal of `1/a + 1/b -c/(ab)`. (2 marks)
`(ab)/(a+b-c)`
| `1/a + 1/b -c/(ab)` | `=b/(ab)+a/(ab)-c/(ab)` |
| `=(b+a-c)/(ab)` |
`text(Reciprocal of)\ \ x = x^(-1)`
`:.\ text(Reciprocal of)\ \ (b+a-c)/(ab)=((b+a-c)/(ab))^(-1)=(ab)/(a+b-c)`
Worker A picks a bucket of blueberries in `a` hours. Worker B picks a bucket of blueberries in `b` hours.
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i. `text(In one hour:)`
`text(Worker A picks)\ 1/a\ text(bucket.)`
`text(Worker B picks)\ 1/b\ text(bucket.)`
`:.\ text(Fraction picked in 1 hour working together)`
`= 1/a + 1/b`
`= (a + b)/(ab)`
ii. `text(The reciprocal represents the number of hours it would)`
`text(take to fill one bucket, with A and B working together.)`
Simplify `(p/q)^3 ÷ (pq^(-2))`. (2 marks)
`(p^2)/q`
| `(p/q)^3 ÷ (pq^(-2))` | `= (p^3)/(q^3) ÷ p/(q^2)` |
| `= (p^3)/(q^3) xx (q^2)/p` | |
| `= (p^2)/q` |
Express `((2x-3))/2-((x-1))/5` as a single fraction in its simplest form. (2 marks)
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`(8x-13)/10`
`((2x-3))/2-((x-1))/5`
`= (5(2x-3)-2(x-1))/10`
`= (10x-15-2x + 2)/10`
`= (8x-13)/10`
Solve `(x-5)/3-(x+1)/4 = 5`. (2 marks)
`83`
| `(x-5)/3-(x+1)/4` | `= 5` |
| `12((x-5)/3)-12((x+1)/4)` | `= 12 xx 5` |
| `4x-20-3x-3` | `= 60` |
| `x-23` | `= 60` |
| `:. x` | `= 83` |
Simplify `2/n-1/(n+1)`. (2 marks)
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`(n + 2)/(n(n+1))`
`2/n-1/(n+1)`
`= (2(n+1)-1(n))/(n(n+1))`
`= (2n + 2-n)/(n(n+1))`
`= (n+2)/(n(n+1))`