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Trigonometry, 2ADV T1 2021 HSC 18

The diagram shows a triangle `ABC` where `AC` = 25 cm, `BC` = 16 cm, `angle BAC` = 28° and angle `ABC` is obtuse.
 


 

Find the size of the obtuse angle `ABC` correct to the nearest degree.  (3 marks)

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`133°`

Show Worked Solution

`text(Using the sine rule:)`

`sin theta/25` `= (sin 28°)/16`
`sin theta` `= (25 xx sin 28°)/16`
`sin theta` `= 0.73355`
`theta` `= 47°`
 
`:. angleABC` `= 180-47`
  `= 133°`

Filed Under: Trig Ratios, Sine and Cosine Rules (Adv-2027), Trig Ratios, Sine and Cosine Rules (Y11) Tagged With: 2adv-std2-common, Band 4, common-content, smc-6392-30-Sine Rule, smc-6392-60-Ambiguous Case, smc-980-30-Sine Rule, smc-980-50-Ambiguous Case

Trigonometry, 2ADV T1 EQ-Bank 2

Determine all possible dimensions for triangle  `ABC`  given  `AB = 6.2\ text(cm)`, `angleABC = 35°`  and  `AC = 4.1`.

Give all dimensions correct to one decimal place.  (3 marks)

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`text(7.1 cm, 6.2 cm, 4.1 cm or)`

`text(3.0 cm, 6.2 cm, 4.1 cm.)`

Show Worked Solution

`text(Using the sine rule:)`

`(sinangleACB)/6.2` `= (sin35^@)/4.1`
`sinangleACB` `= (6.2 xx sin35^@)/4.1`
  `= 0.8673…`
`angleACB` `= 60.15…^@\ text(or)\ 119.84…^@`

  
`text(If)\ \ angleACB = 60.15^@,`

`angleBAC = 180 – (35 + 60.15) = 84.85^@`
 

`(BC)/(sin84.85)` `= 4.1/(sin35^@)`
`BC` `= 7.11…`
  `= 7.1\ text(cm)`

 
`text(If)\ \ angleACB = 119.85^@,`

`angleBAC = 180 – (35 + 119.85) = 25.15^@`
 

`(BC)/(sin25.15)` `= 4.1/(sin35^@)`
`BC` `= 3.03…`
  `= 3.0\ text(cm)`

 
`:.\ text(Possible dimensions are:)`

`text(7.1 cm, 6.2 cm, 4.1 cm or)`

`text(3.0 cm, 6.2 cm, 4.1 cm.)`

Filed Under: Trig Ratios, Sine and Cosine Rules (Adv-2027), Trig Ratios, Sine and Cosine Rules (Y11) Tagged With: Band 4, smc-6392-30-Sine Rule, smc-6392-60-Ambiguous Case, smc-980-30-Sine Rule, smc-980-50-Ambiguous Case

Trigonometry, 2ADV T1 2009 HSC 5c

The diagram shows a circle with centre `O` and radius 2 centimetres. The points  `A`  and  `B`  lie on the circumference of the circle and  `/_AOB = theta`.
 

2009 5c  
 

  1. There are two possible values of  `theta`  for which the area of  `Delta AOB`  is  `sqrt 3`  square centimetres. One value is  `pi/3`.

     

    Find the other value.    (2 marks)

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  2. Suppose that  `theta = pi/3`.

     

    (1)  Find the area of sector  `AOB`   (1 mark)

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    (2)  Find the exact length of the perimeter of the minor segment bounded by the chord  `AB`  and the arc  `AB`.   (2 marks)

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  1. `(2pi)/3`
  2. (1)  `(2pi)/3\ \ text(cm²)`
  3. (2)  `(2 + (2pi)/3)\ text(cm)`
Show Worked Solution
i.    `text(Area)\ Delta AOB` `= 1/2 ab sin theta`
    `= 1/2 xx 2 xx 2 xx sin theta`
    `= 2 sin theta`
`2 sin theta` `= sqrt 3\ \ \ text{(given)}`
`sin theta` `= sqrt3/2`
`:. theta` `= pi/3,\ pi\ – pi/3`
  `= pi/3,\ (2pi)/3`

 

`:.\ text(The other value of)\ theta\ text(is)\ \ (2pi)/3\ \ text(radians)` 

 

ii. (1)    `text(Area of sector)\ AOB` `= pi r^2 xx theta/(2pi)`
    `= 1/2 r^2 theta`
    `= 1/2 xx 2^2 xx pi/3`
    `= (2pi)/3\ text(cm²)` 

 

ii. (2)    `text(Using the cosine rule:)`
`AB^2` `= OA^2 + OB^2\ – 2 xx OA xx OB xx cos theta`
  `= 2^2 + 2^2\ – 2 xx 2 xx 2 xx cos (pi/3)`
  `= 4 + 4\ – 4`
  `= 4`
`:.\ AB` `= 2`

 

`text(Arc)\ AB` `= 2 pi r xx theta/(2pi)`
  `= r theta`
  `= (2pi)/3\ text(cm)`

 

`:.\ text(Perimeter) = (2 + (2pi)/3)\ text(cm)`

Filed Under: Circular Measure, Circular Measure (Adv-2027), Circular Measure (Y11), Sine and Cosine Rules, Bearings, Trig Ratios, Sine and Cosine Rules (Adv-2027), Trig Ratios, Sine and Cosine Rules (Y11) Tagged With: Band 4, Band 5, smc-6392-30-Sine Rule, smc-6392-60-Ambiguous Case, smc-6394-10-Arc Length/Perimeter, smc-6394-20-Area of Sector, smc-978-10-Arc Length/Perimeter, smc-978-20-Area of Sector, smc-980-30-Sine Rule, smc-980-50-Ambiguous Case

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