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Calculus, 2ADV C1 EQ-Bank 8

The displacement \(x\) metres from the origin at time, \(t\) seconds, of a particle travelling in a straight line is given by

\(x=t^3-9 t^2+9 t, \quad t \geqslant 0\)

  1. Find the time(s) when the particle is at the origin.   (2 marks)

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  2. On the graph below, sketch the displacement, \(x\) metres, with respect to time \(t\).   (2 marks)
     
       

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  3. Find the velocity of the particle when  \(t=2\).   (2 marks)

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Show Answers Only

a.  \(\text{Particle at origin when}\ \ t=0, t=3.\)

b.
       
 

c.   \(\dot{x}=-15\  \text{m s}^{-1}\)

Show Worked Solution

a.    \(x\) \(=t^3-9 t^2+9 t\)
    \(=t\left(t^2-9 t+9\right)\)
    \(=t(t-3)^2\)

 
\(\text{Particle at origin when}\ \ t=0, t=3.\)

 
b.
       
 

c.    \(x=t^3-9 t^2+9 t\)

\(\dot{x}= \dfrac{dx}{dt} = 3 t^2-18 t+9\)

\(\text {When } t=2:\)

\(\dot{x}=3 \times 2^2-18 \times 2+9=-15\  \text{m s}^{-1}\)

Filed Under: Rates of Change (Adv-2027) Tagged With: Band 3, Band 4, smc-6438-10-Motion Graphs, smc-6438-20-Polynomial Function

Calculus, 2ADV C1 2019 HSC 8 MC

A particle is moving along a straight line. The graph shows the acceleration of the particle.
 


 

For what value of `t` is the velocity `v` a maximum?

  1. `1`
  2. `2`
  3. `3`
  4. `5`
Show Answers Only

`C`

Show Worked Solution

`text(Velocity increases when)\ \ a > 0.`

`:. v_text(max)\ \ text(occurs when)\ \ t = 3.`

`=>  C`

Filed Under: Rates of Change (Adv-2027), Rates of Change (Y11) Tagged With: Band 4, smc-1083-10-Motion Graphs, smc-6438-10-Motion Graphs

Calculus, 2ADV C1 2008 HSC 6b

The graph shows the velocity of a particle,  `v`  metres per second, as a function of time,  `t`  seconds.

  1. What is the initial velocity of the particle?   (1 mark)

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  2. When is the velocity of the particle equal to zero?    (1 mark)

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  3. When is the acceleration of the particle equal to zero?    (1 mark)

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Show Answers Only
  1. `20\ text(m/s)`
  2. `t=10\ text(seconds)`
  3. `t=6\ text(seconds)`
Show Worked Solution

i.    `text(Find)\   v  \ text(when)  t=0`

`v=20\ \ text(m/s)`
 

ii.    `text(Particle comes to rest at)\  t=10\ text{seconds  (from graph)}`

 

iii.  `text(Acceleration is zero when)\ t=6\ text{seconds  (from graph)}`

Filed Under: Rates of Change (Adv-2027), Rates of Change (Y11) Tagged With: Band 2, Band 3, smc-1083-10-Motion Graphs, smc-6438-10-Motion Graphs

Calculus, 2ADV C1 2017 HSC 10 MC

A particle is moving along a straight line.

The graph shows the velocity, `v`, of the particle for time  `t >= 0`.
 


 

How many times does the particle change direction?

  1. 1
  2. 2
  3. 3
  4. 4
Show Answers Only

`A`

Show Worked Solution
♦♦♦ Mean mark 33%.

`=>A`

Filed Under: Motion, Rates of Change (Adv-2027), Rates of Change (Y11) Tagged With: Band 6, smc-1083-10-Motion Graphs, smc-1091-60-Other, smc-6438-10-Motion Graphs

Calculus, 2ADV C1 2014 HSC 9 MC

The graph shows the displacement  `x`  of a particle moving along a straight line as a function of time  `t`.

2014 9 mc

 Which statement describes the motion of the particle at the point  `P`? 

  1. The velocity is negative and the acceleration is positive.
  2. The velocity is negative and the acceleration is negative.
  3. The velocity is positive and the acceleration is positive.
  4. The velocity is positive and the acceleration is negative.
Show Answers Only

`A`

Show Worked Solution

`text(At)\ P,\ text(the particle is moving back towards)\ O`

`text{after hitting a max (positive) displacement}`

`:.\ text(Velocity is negative.)`

`text(Its displacement hits a minimum just after)\ P`

`text(and increases again.)`

`:.\ text{Acceleration is working against (negative) velocity}`

`text(and must be positive.)`

`=>  A` 

Filed Under: Motion, Rates of Change (Adv-2027), Rates of Change (Y11) Tagged With: Band 4, smc-1083-10-Motion Graphs, smc-6438-10-Motion Graphs

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