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Measurement, STD1 M3 2022 HSC 32

The diagram shows two right-angled triangles, `A B C` and `A B D`,

where `A C=35 \ text{cm}`, `B D=93 \ text{cm}`, `/_ A C B=41^@` and ` /_ A D B=\theta`.
 


 

Calculate the size of angle `\theta`, to the nearest minute.   (4 marks)

--- 8 WORK AREA LINES (style=lined) ---

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`19^@6^{′}`

Show Worked Solution

`text{In}\ Delta ABC:`

`tan 41^@` `=(AB)/35`
`AB` `=35xxtan 41^@`
  `=30.425\ …`

  
`text{In}\ Delta ABD:`

`sin theta` `=(AB)/(BD)`
  `=(30.425\ …)/93`
`:.theta` `=sin^(-1)((30.425\ …)/93)`
  `=19.09…`
  `=19^@6^{′}\ \ text{(nearest minute)}`

♦♦♦ Mean mark 17%.

Filed Under: M3 Right-Angled Triangles (Y12), Right-angled Triangles (Y12) Tagged With: Band 6, smc-1103-20-Right-angled Trig, smc-1103-50-Rounding to the Minute, smc-6834-20-Trigonometry, smc-6834-50-Rounding to the Minute

Measurement, STD1 M3 2019 HSC 31

Two right-angled triangles, `ABC` and `ADC`, are shown.
 


 

Calculate the size of angle `theta`, correct to the nearest minute.   (3 marks)

--- 6 WORK AREA LINES (style=lined) ---

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`41^@5^{′}\ text{(nearest minute)}`

Show Worked Solution

`text(Using Pythagoras in)\ DeltaACD:`

♦♦♦ Mean mark 15%.

`AC^2` `= 2.5^2 + 6^2`
  `= 42.25`
`:.AC` `= 6.5\ text(cm)`

 
`text(In)\ DeltaABC:`

`costheta` `= 4.9/6.5`
`theta` `= cos^(−1)\ 4.9/6.5`
  `= 41.075\ …`
  `= 41^@4^{′}31^{″}`
  `= 41^@5^{′}\ text{(nearest minute)}`

Filed Under: M3 Right-Angled Triangles (Y12), Right-angled Triangles (Y12) Tagged With: Band 6, smc-1103-10-Pythagoras, smc-1103-20-Right-angled Trig, smc-1103-50-Rounding to the Minute, smc-6834-10-Pythagoras, smc-6834-20-Trigonometry, smc-6834-50-Rounding to the Minute

Measurement, STD2 M6 2017 HSC 8 MC

The diagram shows a right-angled triangle.
 


 

What is the value of  `theta`, to the nearest minute?

  1. `70°16^{′}`
  2. ` 70°17^{′}`
  3. `70°27^{′}`
  4. `70°28^{′}`
Show Answers Only

`B`

Show Worked Solution
`tan theta` `= text(opp)/text(adj)`
  `= 5.3/1.9= 2.789\ …`
COMMENT: An angle that has over 30″ (seconds) is rounded up to the next minute (i.e. rounded up to 70°17′).

 

`:. theta` `= 70.277\ …^@`
  `=70°16^{′}39.8^{″}~~ 70^@17^{′}`

 
`=>B`

Filed Under: M3 Right-Angled Triangles (Y12), Pythagoras and basic trigonometry, Pythagoras and Right-angled Trig, Pythagoras and Right-Angled Trig, Right-angled Triangles (Y12) Tagged With: Band 4, smc-1103-20-Right-angled Trig, smc-1103-50-Rounding to the Minute, smc-6834-20-Trigonometry, smc-6834-50-Rounding to the Minute, smc-6928-20-Right-Angled Trig, smc-6928-50-Rounding to the Minute, smc-802-20-Right-Angled Trig, smc-802-50-Rounding to the Minute

Measurement, STD2 M6 2005 HSC 25b

2UG-2005-25b

  1. Use Pythagoras’ theorem to show that `ΔABC` is a right-angled triangle.   (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  2. Calculate the size of `∠ABC` to the nearest minute.   (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

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a.    `text(Proof)`

b.    `67°23^{′}`

Show Worked Solution

a.    `ΔABC\ text(is right-angled if)\ \ a^2 + b^2 = c^2`

`a^2 + b^2` `= 5^2 + 12^2`
  `= 169`
  `= 13^2`
  `= c^2\ …\ text(as required.)`

MARKER’S COMMENT: Know your calculator process for producing an angle in minutes/seconds. Note >30 “seconds” rounds up to the higher “minute”.

 
b.   
`sin ∠ABC = 12/13`

`:.∠ABC` `= 67.38\ …°`
  `=67°22^{′}48^{″}`
  `= 67°23^{′}\ \ \ text{(nearest minute)}`

Filed Under: M3 Right-Angled Triangles (Y12), Pythagoras and basic trigonometry, Pythagoras and Right-angled Trig, Pythagoras and Right-Angled Trig, Right-angled Triangles (Y12) Tagged With: Band 3, Band 4, smc-1103-10-Pythagoras, smc-1103-20-Right-angled Trig, smc-1103-50-Rounding to the Minute, smc-6834-10-Pythagoras, smc-6834-20-Trigonometry, smc-6834-50-Rounding to the Minute, smc-6928-10-Pythagoras, smc-6928-20-Right-Angled Trig, smc-6928-50-Rounding to the Minute, smc-802-10-Pythagoras, smc-802-20-Right-Angled Trig, smc-802-50-Rounding to the Minute

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