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Algebra, STD2 A4 2024 HSC 9 MC

The time taken to paint a school varies inversely with the number of painters completing the task.

It takes 6 painters a total of 20 days to paint a school.

How many days would it take 15 painters to paint the same school?

  1. 4.5
  2. 8
  3. 15.5
  4. 50
Show Answers Only

\(B\)

Show Worked Solution

\(T \propto \dfrac{1}{N} \ \Rightarrow \ \ T=\dfrac{k}{N}\)

\(\text {Find}\ k\ \text{given}\ \  T=20\ \ \text {when}\ \ N=6 \text {:}\)

\(20=\dfrac{k}{6} \ \Rightarrow\ \ k=120\)

\(\therefore\ T=\dfrac{120}{N}\)

\(\text {Find}\ T \ \text {if}\ \ N=15:\)

\(T=\dfrac{120}{15}=8 \text { days }\)

\(\Rightarrow B\)

Filed Under: Non-Linear: Inverse and Other Problems, Reciprocal Relationships Tagged With: Band 4, smc-6923-10-\(\large y \propto \frac{1}{x}\), smc-6923-40-Practical Problems, smc-795-10-Inverse, smc-795-40-Proportional

Algebra, STD2 A4 2022 HSC 24

A student believes that the time it takes for an ice cube to melt (`M` minutes) varies inversely with the room temperature `(T^@ text{C})`. The student observes that at a room temperature of `15^@text{C}` it takes 12 minutes for an ice cube to melt.

  1. Find the equation relating `M` and `T`.   (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

  2. By first completing this table of values, graph the relationship between temperature and time from `T=5^@C` to `T=30^@ text{C}`.   (2 marks)

\begin{array} {|l|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \ T\ \  \rule[-1ex]{0pt}{0pt} & \ \ \ 5\ \ \  & \ \ 15\ \ \  & \ \ \ 30\ \ \  \\
\hline
\rule{0pt}{2.5ex} \ \ M\ \ \rule[-1ex]{0pt}{0pt} & & & \\
\hline
\end{array}

 
           

--- 0 WORK AREA LINES (style=lined) ---

Show Answers Only

a.    `M prop 1/T \ \ =>\ \ M=k/T`

  `12` `=k/15`
  `k` `=15 xx 12=180`

 
`:.M=180/T`

b.   

\begin{array} {|l|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \ T\ \  \rule[-1ex]{0pt}{0pt} & \ \ \ 5\ \ \  & \ \ 15\ \ \  & \ \ 30\ \  \\
\hline
\rule{0pt}{2.5ex} \ \ M\ \ \rule[-1ex]{0pt}{0pt} & 36 & 12 & 6 \\
\hline
\end{array}

 

     

Show Worked Solution
a.     `M` `prop 1/T`
  `M` `=k/T`
  `12` `=k/15`
  `k` `=15 xx 12=180`

 
`:.M=180/T`


♦♦ Mean mark part (a) 29%.

b.   

\begin{array} {|l|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \ T\ \  \rule[-1ex]{0pt}{0pt} & \ \ \ 5\ \ \  & \ \ 15\ \ \  & \ \ 30\ \  \\
\hline
\rule{0pt}{2.5ex} \ \ M\ \ \rule[-1ex]{0pt}{0pt} & 36 & 12 & 6 \\
\hline
\end{array}

 

     


♦ Mean mark (b) 44%.

Filed Under: Circles and Hyperbola, Non-Linear: Inverse and Other Problems, Reciprocal Relationships Tagged With: 2adv-std2-common, Band 5, num-title-ct-pathc, num-title-qs-hsc, smc-4445-60-Hyperbola applications, smc-6923-10-\(\large y \propto \frac{1}{x}\), smc-6923-30-Draw Graph, smc-795-10-Inverse

Algebra, STD2 A4 2021 HSC 13 MC

The time taken to clean a warehouse varies inversely with the number of cleaners employed.

It takes 8 cleaners 60 hours to clean a warehouse.

Working at the same rate, how many hours would it take 10 cleaners to clean the same warehouse.

  1. 45
  2. 48
  3. 62
  4. 75
Show Answers Only

`B`

Show Worked Solution

`text{Time to clean}\ (T) prop 1/text{Number of cleaners (C)}`

♦ Mean mark 41%.

`T=k/C`

`text(When)\ \ T=60, C=8`

`60` `=k/8`
`k` `=480`

 
`text{Find}\ \ T\ \ text(when)\ \ C=10:`

`T=480/10=48\ text(hours)`

`=>  B`

Filed Under: Non-Linear: Inverse and Other Problems, Reciprocal Relationships Tagged With: Band 5, smc-6923-10-\(\large y \propto \frac{1}{x}\), smc-795-10-Inverse, smc-795-40-Proportional

Algebra, STD2 A4 EQ-Bank 30

The number of trees that can be planted along the fence line of a paddock varies inversely with the distance between each tree.

There will be 108 trees if the distance between them is 5 metres.

  1. How many trees can be planted if the distance between them is 6 metres?   (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

  2. What is the distance between the trees if 120 trees are planted.   (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

Show Answers Only

a.    `90`

b.    `4.5\ text(metres)`

Show Worked Solution

a.    `t \prop 1/d \ \ =>\ \ t=k/d`

`108` `= k/5`
`k` `= 540`

 
`text(Find)\ \ t\ \ text(when)\ \ d = 6:`

`t= 540/6= 90`
 

b.   `text(Find)\ \ d\ \ text(when)\ \ t = 120:`

`120` `= 540/d`
`d` `= 540/120= 4.5\ text(metres)`

Filed Under: Non-Linear: Inverse and Other Problems, Reciprocal Relationships Tagged With: Band 5, smc-6923-10-\(\large y \propto \frac{1}{x}\), smc-6923-40-Practical Problems, smc-795-10-Inverse, smc-795-40-Proportional

Algebra, STD2 A4 2018 HSC 29c

When people walk in snow, the depth (`D` cm) of each footprint depends on both the area (`A` cm²) of the shoe sole and the weight of the person. The graph shows the relationship between the area of the shoe sole and the depth of the footprint in snow, for a group of people of the same weight.
 

  1. The graph is a hyperbola because `D` is inversely proportional to `A`. The point `P` lies on the hyperbola.
  2. Find the equation relating `D` and `A`.   (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

  3. A man from this group walks in snow and the depth of his footprint is 4 cm.
  4. Use your equation from part (i) to calculate the area of his shoe sole.   (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

Show Answers Only

i.    `D = 4500/A`

ii.   `1125\ text(cm)^{2}`

Show Worked Solution

i.    `D prop 1/A \ \ =>\ \ D = k/A`

♦♦ Mean mark part (i) 22%.

`text(When)\ D = 15, A = 300:`

`15= k/300\ \ =>\ \ k= 15 xx 300=4500`

`:. D=4500/A`
 

♦♦ Mean mark part (ii) 33%.

ii.    `4` `= 4500/A`
  `:. A` `= 4500/4= 1125\ text(cm)^{2}`

Filed Under: Non-Linear: Inverse and Other Problems, Reciprocal Relationships Tagged With: Band 5, smc-6923-10-\(\large y \propto \frac{1}{x}\), smc-6923-40-Practical Problems, smc-795-10-Inverse, smc-795-40-Proportional

Algebra, STD2 A4 2007 HSC 15 MC

If pressure `(p)` varies inversely with volume `(V)`, which formula correctly expresses `p` in terms of `V` and `k`, where `k` is a constant?

  1. `p = k/V`
  2. `p = V/k`
  3. `p = kV`
  4. `p = k + V`
Show Answers Only

`A`

Show Worked Solution

`p prop 1/V\ \ =>\ \ p = k/V`

`=>  A`

Filed Under: Inverse, Non-Linear: Inverse and Other Problems, Reciprocal Relationships, Variation and Rates of Change Tagged With: Band 5, num-title-ct-patha, num-title-qs-hsc, smc-4239-30-a prop 1/b, smc-6923-10-\(\large y \propto \frac{1}{x}\), smc-795-10-Inverse, smc-795-40-Proportional

Algebra, STD2 A4 2011 HSC 28a

The air pressure, `P`, in a bubble varies inversely with the volume, `V`, of the bubble. 

  1. Write an equation relating `P`, `V` and `a`, where `a` is a constant.   (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  2. It is known that `P = 3` when `V = 2`.
  3. By finding the value of the constant, `a`, find the value of `P` when `V = 4`.   (2 marks)

    --- 4 WORK AREA LINES (style=lined) ---

  4. Sketch a graph to show how `P` varies for different values of `V`.
  5. Use the horizontal axis to represent volume and the vertical axis to represent air pressure.   (2 marks)

    --- 8 WORK AREA LINES (style=lined) ---


Show Answers Only

a.    `P = a/V`

b.    `P = 1 1/2`

c.    
       

Show Worked Solution
♦ Mean mark (a) 39%

a.    `P prop 1/V\ \ =>\ \ P= a/V`
 

b.    `text(When)\ P=3,\ V=2:`

`3= a/2\ \ =>\ \ a=6`

`text(Find)\ P\ text(when)\ V = 4:`  

♦ Mean mark (b) 47%

`P=6/4=3/2`

 

♦♦ Mean mark (c) 26%
c.

Filed Under: Inverse, Non-Linear: Inverse and Other Problems, Reciprocal Relationships, Variation and Rates of Change Tagged With: Band 5, num-title-ct-patha, num-title-qs-hsc, smc-4239-30-a prop 1/b, smc-6923-10-\(\large y \propto \frac{1}{x}\), smc-795-10-Inverse, smc-795-40-Proportional

Algebra, STD2 A4 2010 HSC 13 MC

The number of hours that it takes for a block of ice to melt varies inversely with the temperature. At 30°C it takes 8 hours for a block of ice to melt.

How long will it take the same size block of ice to melt at 12°C?  

  1. 3.2 hours
  2. 20 hours
  3. 26  hours
  4. 45 hours
Show Answers Only

`B`

Show Worked Solution
♦ Mean mark 50% 

`text{Time to melt}\ (T) prop1/text(Temp) \ \ =>\ \ T=k/text(Temp)`

`text(When) \ T=8, text(Temp = 30 :)`

`8=k/30\ \ =>\ \ k=240`
   

`text{Find}\ T\ text{when  Temp = 12:}`

`T=240/12=20\ text(hours)`

`=>  B`

Filed Under: Inverse, Non-Linear: Inverse and Other Problems, Reciprocal Relationships, Variation and Rates of Change Tagged With: Band 5, num-title-ct-patha, num-title-qs-hsc, smc-4239-30-a prop 1/b, smc-6923-10-\(\large y \propto \frac{1}{x}\), smc-6923-40-Practical Problems, smc-795-10-Inverse, smc-795-40-Proportional

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