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Functions, EXT1 F2 2022 HSC 13d

The monic polynomial, `P`, has degree 3 and roots `alpha, \beta, \gamma`.

It is given that

           `alpha^(2)+beta^(2)+gamma^(2)=85\ \ and`

           `P^(')(alpha)+P^(')(beta)+P^(')(gamma)=87.`

Find  `alpha beta+beta gamma+gamma alpha`.   (3 marks)

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`-2`

Show Worked Solution

`P(x)=x^3-(alpha+beta+gamma)x^2+(alphabeta+alphagamma+betagamma)x-alphabetagamma`

`P^(′)(x)=3x^2-2(alpha+beta+gamma)x+alphabeta+alphagamma+betagamma`

`P^(′)(alpha)+P^(′)(beta)+P^(′)(gamma)`

  `=3alpha^2-2(alpha+beta+gamma)alpha+alphabeta+alphagamma+betagamma`

`+ 3beta^2-2(alpha+beta+gamma)beta+alphabeta+alphagamma+betagamma`

`+ 3gamma^2-2(alpha+beta+gamma)gamma+alphabeta+alphagamma+betagamma`

  `=3(alpha^(2)+beta^(2)+gamma^(2))-2(alpha^(2)+beta^(2)+gamma^(2))`

`-2(alphabeta+alphagamma+alphabeta+betagamma+alphagamma+betagamma)+3(alphabeta+alphagamma+betagamma)`

  `=(alpha^(2)+beta^(2)+gamma^(2))-(alphabeta+alphagamma+betagamma)`

`text{Substituting in given values:}`

`85-(alphabeta+alphagamma+betagamma)` `=87`  
`:.alphabeta+alphagamma+betagamma` `=-2`  

♦♦ Mean mark 33%.

Filed Under: Multiplicity of Zeroes in Polynomials, Sum, Products and Multiplicity of Roots Tagged With: Band 5, smc-1205-20-Multiplicity of Roots, smc-7292-20-Unknown Roots

Functions, EXT1′ F2 2017 HSC 12d

Let `P(x)` be a polynomial.

  1. Given that `(x-alpha)^2` is a factor of `P(x)`, show that
  2. `qquad qquad P(alpha) = P^{′}(alpha) = 0`.   (2 marks)

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  3. Given that the polynomial  `P(x) = x^4-3x^3 + x^2 + 4`  has a factor `(x-alpha)^2`, find the value of `alpha`.   (2 marks)

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i.    `text(Proof)\ \ text{(See Worked Solutions)}`

ii.   `2`

Show Worked Solution
i.   `P(x)` `= (x-alpha)^2 · Q(x)`
  `P^{′}(x)` `= 2 (x-alpha) · Q (x) + (x-alpha)^2 *Q^{′}(x)`
    `= (x-alpha) [2 Q (x) + (x-alpha) *Q^{′}(x)]`

 

`P (alpha)` `= 0 xx Q(x) = 0`
`P^{′}(alpha)` `= 0 [2Q (x) + 0 xx Q^{′}(x)] = 0`

 
`:. P(alpha) = P^{′}(alpha) = 0\ text(… as required.)`

 

ii.   `P(x)` `= x^4-3x^3 + x^2 + 4`
  `P^{′}(x)` `= 4x^3-9x^2 + 2x`
    `= x (4x^2-9x + 2)`
    `= x (4x-1) (x-2)`

 
`:. P^{′}(x) = 0\ \ text(when)\ \ x = 0, 1/4 or 2`

`=>\ text(Multiple roots may exist at)\ \ x=0, 1/4 or 2.`

`text(Test each root in)\ \ P(x):`

`P(0)` `= 0-0 + 0 + 4 = 4`
`P(1/4)` `= (1/4)^4-3(1/4)^3 + (1/4)^2 + 4= 4 \frac{5}{256}`
`P(2)` `= 16-3(8) + 4 + 4 = 0`

 
`(x-2)^2\ \text(is a factor of)\ P(x)`

`:. alpha = 2`

Filed Under: Multiplicity of Zeroes in Polynomials, Roots and Coefficients, Sum, Products and Multiplicity of Roots Tagged With: Band 3, Band 4, smc-1205-20-Multiplicity of Roots, smc-7292-20-Unknown Roots

Functions, EXT1′ F2 2015 HSC 4 MC

The polynomial  `x^3 + x^2-5x + 3`  has a double root at  `x = alpha.`

What is the value of  `alpha ?`

  1. `-5/3`
  2. `-1`
  3. `1`
  4. `5/3`
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`C`

Show Worked Solution

`P^{′}(x)= 3x^2 + 2x-5= (3x + 5) (x-1)`

 `:. text(Only possible double roots occur when)`

`x=1\ \ text(or)\ \ x=-5/3`
 

`P(1)=1+1-5+3=0`

`:. x = 1\ \ text(is double root.)`

`=>  C`

Filed Under: Multiplicity of Zeroes in Polynomials, Roots and Coefficients, Sum, Products and Multiplicity of Roots Tagged With: Band 3, smc-1205-20-Multiplicity of Roots, smc-7292-20-Unknown Roots

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