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Algebra, STD2 EQ-Bank 29_2

The number of monthly subscribers \((S)\) to a print magazine is decreasing. The number of subscribers is modelled using

\(S=k(1.06)^{-t}\)  for  \( t \geq 0,\)

where \(t\) is time in months.

The number of subscribers today is 12 000.

  1. Use the model to estimate the number of subscribers 10 months from today.   (2 marks)

  2. The number of subscribers needs to always be above 3000.
  3. Explain why this model is NOT appropriate to use in this case.   (1 mark)

Show Answers Only

a.    \(S=12\,000(1.06)^{-10}=6700.73…=6701\ \text{(nearest subscriber)}\)

b.    \(\text{When}\ \ t=30\ \ \Rightarrow\ \ S \approx 2089\)

\(\text{Since the number of subscribers needs to always be over 3000, it is not appropriate.}\)

Show Worked Solution

a.    \(\text{When}\ \ t=0,\ \ S=12\,000:\)

\(12\,000=k(1.06)^{0}\ \ \Rightarrow\ \ k=12\,000\)

\(\text{Find}\ S\ \text{when}\ \ t=10:\)

\(S=12\,000(1.06)^{-10}=6700.73…=6701\ \text{(nearest subscriber)}\)
 

b.    \(\text{When}\ \ t=30:\)

\(S=12\,000(1.06)^{-30} \approx 2089\)

\(\text{Since the number of subscribers needs to always be over 3000, it is not appropriate.}\)

v1 Algebra, STD2 EQ-Bank 29

The number \((N)\) of native birds in a wildlife reserve is decreasing. The number of birds is modelled using

\(N=k(1.08)^{-t}\)  for \( t \geq 0,\)

where \(t\) is time in years.

The number of birds in the reserve today is 8000.

  1. Use the model to estimate the number of birds in the reserve 12 years from today.   (2 marks)

  2. The number of birds in the reserve needs to always be above 1500.
  3. Explain why this model is NOT appropriate to use in this case.   (1 mark)

Show Answers Only

a.    \(N=8000(1.08)^{-12}=3176.91…=3177\ \text{(nearest bird)}\)

b.    \(\text{When}\ \ t=25:\)

\(N=8000(1.08)^{-25}=1168.14…\)

\(\text{Since the number of birds needs to always be over 1500, it is not appropriate.}\)

Show Worked Solution

a.    \(\text{When}\ \ t=0,\ \ N=8000:\)

\(8000=k(1.08)^{0}\ \ \Rightarrow\ \ k=8000\)

\(\text{Find}\ N\ \text{when}\ \ t=12:\)

\(N=8000(1.08)^{-12}=3176.91…=3177\ \text{(nearest bird)}\)
 

b.    \(\text{When}\ \ t=25:\)

\(N=8000(1.08)^{-25}=1168.14…\)

\(\text{Since the number of birds needs to always be over 1500, it is not appropriate.}\)