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Measurement, STD2 M1 2009 HSC 12 MC (Adapted)

How many square millimetres are in 0.004 square metres?

  1. 4
  2. 40
  3. 4000
  4. 40 000
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`D`

Show Worked Solution
`text{Since 1 m}^2` `= 1000\ text{mm} xx 1000\ text{mm}`
  `= 1\ 000\ 000\ \text{mm}^2`

 
`:. 0.004\ \text{m}^2= 0.004 xx 1\ 000\ 000= 4000\ \text{mm}^2`

`⇒ D`

Measurement, STD2 M1 2004 HSC 13 MC (Adapted)

During a study break, Sam is walking while Alex is sitting.
 

Sam breathes in air at a rate of 30 litres per minute while walking. Alex breathes in air at a rate of 8 litres per minute while sitting.

During a 20-minute break, how much more air would Sam breathe than Alex?

  1. 220 Litres
  2. 440 Litres
  3. 460 Litres
  4. 600 Litres
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`=>\ B`

Show Worked Solution
`text{Sam’s total}` `= 30 × 20 = 600\ \text{L}`
`text{Alex’s total}` `= 8 × 20 = 160\ \text{L}`
`text{Difference}` `= 600 − 160 = 440\ \text{L}`

`=>\ B`

Measurement, STD2 M1 2006 HSC 11 MC

Peter rides his bike at a speed of 27 km/h.

What is this speed in m/s?

  1.  `7.5`
  2. `18.75`
  3. `97.2`
  4. `450`
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`A`

Show Worked Solution
`text(27 km/h)` `= 27\ 000\ text(metres per hour)`
  `= (27\ 000)/60\ text(metres per minute)`
  `= (27\ 000)/(60 xx 60)\ text(metres per second)`
  `=7.5\ text(m/s)`

`=>  A`

Measurement, STD2 M1 2004 HSC 13 MC

During a ten-minute period, Kath is exercising and Jim is resting.

How much more air would Kath breathe than Jim during this time?

  1. 40 litres
  2. 94 litres
  3. 940 litres
  4. 1060 litres
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`C`

Show Worked Solution

`text(Kath’s air volume)= 10 xx 100=1000\ text(L)`

`text(Jim’s air volume)= 10 xx 6= 60\ text(L)`

`:.\ text(Extra air that Kath breathes)= 1000-60= 940\ text(L)`

`=>  C`

Measurement, STD2 M1 2009 HSC 12 MC

How many square centimetres are in 0.0075 square metres? 

  1. 0.75 
  2. 7.5 
  3. 75
  4. 7500
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`C`

Show Worked Solution

`text{Since 1 m}^2= 100\ text(cm) xx 100\ text(cm)= 10\ 000\ text{cm}^2`

 

♦♦♦ Mean mark 19%.

`:.0.0075\ text{m}^2= 0.0075 xx 10\ 000= 75\ text{cm}^2`

`=>  C`

Measurement, STD2 M1 2012 HSC 26g

Bhawana purchases pool chlorine in a new container which holds 35 kg.
 

2012 26g

 
She begins using this new container on the first day of a week.

How many full weeks should this container last?   (2 marks)

Show Answers Only

 `text(15 full weeks.)`

Show Worked Solution

`text(Cups used per week)= 3 + 6 = 9`

`text(Chlorine usage per week)= 9 xx 250text(g)= 2250 text(g)`

`text(Total chlorine available)\ = 35text(kg) = 35\ 000\  text(grams)`

MARKER’S COMMENT: Better answers converted all measurements to grams (rather than use decimals and kgs) and realised the answer should be in full weeks.

`text(Time it will last)= (35\ 000)/2250= 15.555…`

`:.\ text(The container will last 15 full weeks.)`