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Calculus, 2ADV C2 EQ-Bank 26

Show that  \(\dfrac{d}{d x}(\cot x)=-\operatorname{cosec}^2 x\).   (2 marks)

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\(\text{See Worked Solutions}\)

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\(\cot\,x=\dfrac{\cos\,x}{\sin\,x}\)

\(\text{Using the quotient rule:}\)

\(\dfrac{d}{d x}\left(\dfrac{\cos x}{\sin x}\right)\) \(=\dfrac{-\sin\, x\,\sin\, x-\cos\, x\, \cos \,x}{\sin ^2 x}\)  
  \(=\dfrac{-\sin ^2 x-\cos ^2 x}{\sin ^2 x}\)  
  \(=-\left(\dfrac{1}{\sin ^2 x}\right)\)  
  \(=-\operatorname{cosec}^2 x\)  

Filed Under: Trig Differentiation, Trigonometric Functions Tagged With: Band 4, smc-7129-10-Sin, smc-7129-20-Cos, smc-7129-50-Quotient Rule, smc-968-10-Sin, smc-968-20-Cos, smc-968-50-Quotient Rule

Calculus, 2ADV C2 EQ-Bank 25

Differentiate with respect to \(x\)

\(y=\sin ^2 x\)   (2 marks)

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\(\dfrac{dy}{dx}=2 \sin x\, \cos x\)

Show Worked Solution

\(y=\sin ^2 x=(\sin x)^2\)

\(\text{Using the chain rule:}\)

\(\dfrac{dy}{dx}=2 \sin x\, \cos x\)

Filed Under: Trig Differentiation, Trigonometric Functions Tagged With: Band 4, smc-7129-10-Sin, smc-968-10-Sin

Calculus, 2ADV C2 2022 HSC 25

Let  `f(x)=sin(2x)`.

Find the value of  `x`, for  `0 < x < pi`, for which  `f^(')(x)=-sqrt3`  AND  `f^('')(x)=2`.   (3 marks)

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`(7pi)/12`

Show Worked Solution

`f^(′)(x)=2cos(2x)`

`2cos(2x)` `=-sqrt3`
`cos(2x)` `=-sqrt3/2`
`2x` `=pi-pi/6,\ \ pi+pi/6`
  `=(5pi)/6,\ \ (7pi)/6`
`x` `=(5pi)/12,\ \ (7pi)/12`

 
`f^(″)(x)=-4sin(2x)`

`-4sin(2x)` `=2`
`sin(2x)` `=-1/2`
`2x` `=pi+pi/6,\ \ 2pi-pi/6`
  `=(7pi)/6,\ \ (11pi)/6`
`x` `=(7pi)/12,\ \ (22pi)/12`

 
`:.x=(7pi)/12\ \ text{(satisfies both equations)}`


Mean mark 53%.

Filed Under: Trig Differentiation, Trigonometric Functions Tagged With: Band 4, smc-7129-10-Sin, smc-7129-20-Cos, smc-7129-60-Chain Rule, smc-968-10-Sin, smc-968-20-Cos, smc-968-60-Chain Rule

Calculus, 2ADV C2 2006 HSC 2aii

Differentiate  `sin x/(x + 1)`  with respect to  `x`.   (2 marks)

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`dy/dx = {cos x (x + 1)-sin x} / (x + 1)^2`

Show Worked Solution

`y = sin x / (x + 1)`

`text(Using)\ \ d/dx (u/v) = (vu^{\prime}-uv^{\prime})/v^2`

`u` `= sin x` `v` `= x + 1`
`u^{prime}` `= cos x` `\ \ \ v^{prime}` `= 1`

  
`:.dy/dx = {cos x (x + 1)-sin x} / (x + 1)^2`

Filed Under: Trig Differentiation, Trigonometric Functions Tagged With: Band 3, smc-7129-10-Sin, smc-7129-50-Quotient Rule, smc-968-10-Sin, smc-968-50-Quotient Rule

Calculus, 2ADV C2 EQ-Bank 28

The function  `f(theta) = sin^3(2 theta)`.

If  `f^{prime}(theta) = 6 cos(2 theta)-6 cos^n (2 theta)`, find the value of `n`.   (2 marks)

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`3`

Show Worked Solution

`f(theta)= sin^3(2 theta)= (sin(2theta))^3`

`f^{prime}(theta)` `= 3 xx 2cos(2 theta) xx sin^2(2 theta)`
  `= 6 cos(2 theta)(1-cos^2(2 theta))`
  `= 6 cos (2 theta)-6 cos^3(2 theta)`

 
`:. \ n = 3`

Filed Under: Trig Differentiation, Trigonometric Functions Tagged With: Band 4, smc-7129-10-Sin, smc-7129-60-Chain Rule, smc-968-10-Sin, smc-968-60-Chain Rule

Calculus, 2ADV C2 2019 HSC 11b

Differentiate  `x^2 sin x`.   (2 marks)

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`x^2 ⋅ cos x + 2x sin x`

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`text(Using the product rule:)`

`d/(dx) (x^2 sin x) = x^2 ⋅ cos x + 2x sin x`

Filed Under: Trig Differentiation, Trigonometric Functions Tagged With: Band 2, smc-7129-10-Sin, smc-7129-40-Product Rule, smc-968-10-Sin, smc-968-40-Product Rule

Calculus, 2ADV C2 2018 HSC 5 MC

What is the derivative of  `sin(ln x),` where  `x > 0`?

  1. `cos (1/x)`
  2. `cos (ln x)`
  3. `cos ((ln x)/x)`
  4. `(cos (ln x))/x`
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`D`

Show Worked Solution
`y` `= sin (ln x)`
`(dy)/(dx)` `= cos (ln x) xx d/(dx) (ln x)`
  `= cos (ln x) xx 1/x`
  `= (cos (ln x))/x`

  
 `=>  D`

Filed Under: Differentiation and Integration, L&E Differentiation, Log Calculus, Log Calculus (Y12), Logs and Exponentials, Trig Differentiation, Trigonometric Functions Tagged With: Band 3, smc-7128-30-\(\log_e x\), smc-7128-50-Chain Rule, smc-7128-70-Trig Overlap, smc-7129-10-Sin, smc-7129-60-Chain Rule, smc-964-10-Differentiation, smc-964-40-Trig overlap, smc-967-20-Logs, smc-967-50-Chain Rule, smc-968-10-Sin, smc-968-60-Chain Rule

Calculus, 2ADV C2 2017 HSC 11c

Differentiate  `(sin x)/x`.   (2 marks)

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`(x cos x-sin x)/x^2`

Show Worked Solution

`y = (sin x)/x`

`text(Let)\ \ u` `=sin x` `u^{prime}` `= cos x`
`v` `=x` `v ^{prime}` `=1`

 

`(dy)/(dx)` `= (u^{prime}v-u v^{prime})/v^2`
  `= (x cos x-sin x)/x^2`

Filed Under: Differentiation and Integration, Trig Differentiation, Trig Differentiation, Trigonometric Functions Tagged With: Band 3, smc-7129-10-Sin, smc-7129-50-Quotient Rule, smc-968-10-Sin, smc-968-50-Quotient Rule

Calculus, 2ADV C2 2004 HSC 3aii

Differentiate with respect to  `x`:

`(1 + sin x)^5`.   (2 marks)

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`5 cos x\ (1 + sinx)^4`

Show Worked Solution
`y` `= (1 + sinx)^5`
`dy/dx` `= 5 (1 + sinx)^4 xx d/(dx)(sinx)`
  `= 5 cos x (1 + sinx)^4`

Filed Under: Differentiation and Integration, Trig Differentiation, Trig Differentiation, Trigonometric Functions Tagged With: Band 3, smc-7129-10-Sin, smc-7129-60-Chain Rule, smc-968-10-Sin, smc-968-60-Chain Rule

Calculus, 2ADV C2 2008 HSC 2aiii

Differentiate with respect to  `x`:

`sinx/(x+4)`.   (2 marks) 

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`(cosx (x+4)-sin x)/((x + 4)^2)`

Show Worked Solution

`y = sinx/(x + 4)`

`u` `= sinx` `\ \ \ \ \ u^{prime}` `= cos x`
`v` `= x + 4` `v^{prime}` `= 1`

 

`dy/dx` `= (u^{prime}v-uv^{prime})/v^2`
  `= (cos x (x + 4)-sin x)/(x+4)^2`

Filed Under: Differentiation and Integration, Trig Differentiation, Trig Differentiation, Trigonometric Functions Tagged With: Band 3, smc-7129-10-Sin, smc-7129-50-Quotient Rule, smc-968-10-Sin, smc-968-50-Quotient Rule

Calculus, 2ADV C2 2009 HSC 2ai

Differentiate with respect to  `x`: 

`x sin x`.   (2 marks)

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Show Worked Solution
`y` `= x sin x`
`dy/dx` `= x cos x + sin x xx 1`
  `= x cos x + sin x`

Filed Under: Differentiation and Integration, Trig Differentiation, Trig Differentiation, Trigonometric Functions Tagged With: Band 3, smc-7129-10-Sin, smc-7129-40-Product Rule, smc-968-10-Sin, smc-968-40-Product Rule

Calculus, 2ADV C2 2011 HSC 4a

Differentiate  `x/sinx`  with respect to  `x`.   (2 marks)

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 `(sin x-x cos x)/(sin^2x)`

Show Worked Solution

`y = x/sinx`

`u = x` `\ \ \ \ \ u^{prime}= 1`
`v = sin x` `\ \ \ \ \ v ^{prime} = cos x`

 

`text(Using)\ \ d/dx (uv) = (u ^{prime} v-uv ^{prime})/(v^2),`

`dy/dx` `= (1 * sinx-x * cos x)/((sin x)^2)`
  `= (sin x-x cos x)/(sin^2x)`

Filed Under: Differentiation and Integration, Trig Differentiation, Trig Differentiation, Trigonometric Functions Tagged With: Band 3, smc-7129-10-Sin, smc-7129-50-Quotient Rule, smc-968-10-Sin, smc-968-50-Quotient Rule

Calculus, 2ADV C2 2013 HSC 11c

Differentiate  `(sinx-1)^8`.   (2 marks)

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 `8cosx (sinx-1)^7`

Show Worked Solution

`y= (sinx-1)^8`

`dy/dx` `=8 (sinx-1)^7 xx d/dx (sinx-1)`
  `=8 (sinx-1)^7 xx cosx`
  `=8cosx (sinx-1)^7`

Filed Under: Differentiation and Integration, Trig Differentiation, Trig Differentiation, Trigonometric Functions Tagged With: Band 3, smc-7129-10-Sin, smc-7129-60-Chain Rule, smc-968-10-Sin, smc-968-60-Chain Rule

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