The graph below has the equation \(y=a \sin (b x)+c\) for \(0 \leqslant x \leqslant 50\).
Determine the values of \(a, b\) and \(c\). (3 marks) --- 5 WORK AREA LINES (style=lined) ---
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The graph below has the equation \(y=a \sin (b x)+c\) for \(0 \leqslant x \leqslant 50\).
Determine the values of \(a, b\) and \(c\). (3 marks) --- 5 WORK AREA LINES (style=lined) ---
\(a=16, b=9, c=24\)
\(\text {Amplitude}\ =\dfrac{40-8}{2}=16\ \ \Rightarrow a=16\)
\(\text {Centre of motion}\ =24\ \ \Rightarrow c=24\)
\(\text {Period }=\dfrac{360}{n}=40\ \ \Rightarrow n=b=9\)
For what values of `x`, in the interval `0 <= x <= pi/4`, does the line `y = 1` intersect the graph of `y = 2sin4x`? (2 marks)
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`pi/24, (5pi)/24`
`text(Find)\ x\ text(such that:)`
`2sin4x` | `= 1` |
`sin4x` | `= 1/2` |
`4x` | `= sin^(-1)\ 1/2` |
`4x` | `= pi/6, (5pi)/6, (13pi)/6, (17pi)/6, …` |
`:. x` | `= pi/24, (5pi)/24\ \ \ (0 <= x <= pi/4)` |
The function `f(x) = sin x` is transformed into the function `g(x) = (sin(4x))/3`.
Describe in words how the amplitude and period have changed in this transformation. (2 marks)
`text(See Worked Solutions)`
`g(x) = 1/3 sin (4x)`
`=>\ text(The new amplitude is one third of the original amplitude.)`
`text(Period)\ = (2pi)/n \ => \ \ n=1/4`
`=>\ text(The new period is one quarter of the original period.)`
The diagram shows part of the graph of `y = a sin(bx) + 4`.
What are the values of `a` and `b`?
`D`
`a = 1/2 (5.5 – 2.5) = 1.5`
`text(S)text(ince graph passes through)\ \ (pi/4, 5.5):`
`5.5 = 1.5 sin(b xx pi/4) + 4`
`sin (b xx pi/4)` | `= 1` |
`b xx pi/4` | `= pi/2` |
`:. b` | `= 2` |
`=> D`
`f(x) = 2 sin (2x)` is defined in the domain `{x: \ pi/8 <= x < pi/3)`
What is the range of the function `f(x)`? (2 marks)
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`text(Range) = [sqrt 2, 2]`
`sin(2x)_text(max)\ \ text(occurs when)\ \ x=pi/4\ \ text{(within domain)}`
`=> f(x)_text(max) = 2 sin(pi/2) = 2`
`text(Checking endpoints:)`
`text(When)\ \ x=pi/8\ \ =>\ \ y=2 sin(pi/4) = sqrt2`
`text(When)\ \ x=pi/3\ \ =>\ \ y=2 sin((2pi)/3) = sqrt3`
`:.\ text(Range) = [sqrt 2, 2],`
Let `f (x) = 5sin(2x) - 1`.
The period and range of this function are respectively
`C`
`text(Period) = (2pi)/2 = pi`
`text(Range)` | `= [−1 – 5, −1 + 5]` |
`= [−6 ,4]` |
`=> C`
`f(x) = 2sin(3x) - 3`
The period and range of this function are respectively
`A`
`text(Range:)\ [−3 -2, −3 + 2]`
`= [−5,−1]`
`text(Period) = (2pi)/n = (2pi)/3`
`=> A`
The graph shown is `y = A sin bx`.
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i. `A = 4`
ii. `text(S)text(ince the graph passes through)\ \ (pi/4, 4)`
`text(Substituting into)\ \ y = 4 sin bx`
`4 sin (b xx pi/4)` | `=4` |
`sin (b xx pi/4)` | `= 1` |
`b xx pi/4` | `= pi/2` |
`:. b` | `= 2` |
iii. |
`D`
`text(At)\ x = 0 text(,)\ \ y = sin (pi/3) = sqrt3/2`
`=>\ text(It cannot be A or C)`
`text(Find)\ x\ text(when)\ y = 0,`
`sin (2x + pi/3)` | `= 0` |
`:.\ 2x + pi/3` | `= 0\ \ \ \ \ text{(sin 0 = 0)}` |
`2x` | `=-pi/3` |
`x` | `= -pi/6` |
`=> D`