Ita publishes and sells calendars for $25 each. The cost of producing the calendars is $8 each plus a set up cost of $5950.
How many calendars does Ita need to sell to breakeven? (2 marks)
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Ita publishes and sells calendars for $25 each. The cost of producing the calendars is $8 each plus a set up cost of $5950.
How many calendars does Ita need to sell to breakeven? (2 marks)
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`350`
`text(Let)\ \ x =\ text(number of calendars sold)`
`text(C)text(ost) = 5950 + 8x`
`text(Sales revenue) = 25x`
`text(Breakeven occurs when:)`
`25x` | `= 5950 + 8x` |
`17x` | `= 5950` |
`:. x` | `= 350` |
Sue and Mikey are planning a fund-raising dance. They can hire a hall for $400 and a band for $300. Refreshments will cost them $12 per person.
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The graph shows planned income and costs when the ticket price is $20
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Sue and Mikey plan to sell 200 tickets. They want to make a profit of $1500.
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i. | `$C` | `= 400 + 300 + (12 xx x)` |
`= 700 + 12x` |
ii. `text(Using the graph intersection)`
`text(Approximately 90 people are needed)`
`text(to cover the costs.)`
iii. `text(If 150 people attend)`
`text(Income)` | `= 150 xx $20` |
`= $3000` |
`text(C)text(osts)` | `= 700 + (12 xx 150)` |
`= $2500` |
`:.\ text(Profit)` | `= 3000 − 2500` |
`= $500` |
iv. `text(C)text(osts when)\ x = 200:`
`C` | `= 700 + (12 xx 200)` |
`= $3100` |
`text(Income required to make $1500 profit)`
`= 3100 + 1500`
`= $4600`
`:.\ text(Price per ticket)` | `= 4600/200` |
`= $23` |
Fiona and John are planning to hold a fund-raising event for cancer research. They can hire a function room for $650 and a band for $850. Drinks will cost them $25 per person.
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i. | `text(Fixed C) text(osts)` | `= 650 + 850` |
`= $1500` |
`text(Variable C) text(osts) = $25x`
`:.\ $C = 1500 + 25x`
ii. | `text(From the graph)` |
`text(C) text(osts = Income when)\ x = 60` | |
`text{(i.e. where graphs intersect)}` |
iii. `text(When)\ \ x = 80:`
`text(Income)` | `= 80 xx 50` | |
`= $4000` |
`$C` | `= 1500 + 25 xx 80` |
`= $3500` |
`:.\ text(Profit)` | `= 4000 – 3500` |
`= $500` |
A clubhouse uses four long-life light globes for five hours every night of the year. The purchase price of each light globe is $6.00 and they each cost `$d` per hour to run.
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What is the mean life, in hours, of these light globes if 97.5% will last up to 5000 hours? (1 mark)
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i. `text(Purchase price) = 4 xx 6 = $24`
`text(Running cost)` | `= text(# Hours) xx text(Cost per hour)` |
`= 4 xx 5 xx 365 xx d` | |
`= 7300d` | |
`:.\ $c = 24 + 7300d` |
ii. `text(Given)\ \ $c = $250`
`250` | `= 24 + 7300d` |
`7300d` | `= 226` |
`d` | `= 226/7300` |
`= 0.03095…` | |
`= 0.031\ $ text(/hr)\ text{(3 d.p.)}` |
iii. `text(If)\ d\ text(doubles to 0.062)\ \ $text(/hr)`
`$c` | `= 24 + 7300 xx 0.062` |
`= $476.60` | |
`text(S) text(ince $476.60 is less than)\ 2 xx $250\ ($500),` | |
`text(the total cost increases to less than double)` | |
`text(the original cost.)` |
iv. `sigma = 170`
`z\ text(-score of 5000 hours) = 2`
`z` | `= (x – mu)/sigma` |
`2` | `= (5000 – mu)/170` |
`340` | `= 5000 – mu` |
`mu` | `= 4660` |
`:.\ text(The mean life of these globes is 4660 hours.)`
A function centre hosts events for up to 500 people. The cost `C`, in dollars, for the centre
to host an event, where `x` people attend, is given by:
`C = 10\ 000 + 50x`
The centre charges $100 per person. Its income `I`, in dollars, is given by:
`I = 100x`
How much greater is the income of the function centre when 500 people attend an event, than its income at the breakeven point?
`C`
`text(When)\ x=500,\ I=100xx500=$50\ 000`
`text(Breakeven when)\ \ x=200\ \ \ text{(from graph)}`
`text(When)\ \ x=200,\ I=100xx200=$20\ 000`
`text(Difference)` | `=50\ 000-20\ 000` |
`=$30\ 000` |
`=> C`