The floor plan of a home unit has been drawn to scale.
What is the total floor area of the home unit in square metres? (2 marks)
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The floor plan of a home unit has been drawn to scale.
What is the total floor area of the home unit in square metres? (2 marks)
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`text{55.5 m}^2`
`text{Conversion: 1000 mm = 1 metre}`
`text{Calculate area by splitting into 2 rectangles}`
`text{Area}` | `= 5.5 × 5 + (4.5 +2.5) xx 4` | |
`= 55.5\ text{m}^2` |
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i. \(\text{Scale factor}\ = \dfrac{\text{Diameter B}}{\text{Diameter A}} = \dfrac{0.8}{2.4} = \dfrac{1}{3} \)
ii. \(\text{Scale factor (B to A)} = \dfrac{\text{Diameter A}}{\text{Diameter B}} = \dfrac{2.4}{0.8} = 3 \)
\(\text{Scale factor (Area)} = 3^2 = 9 \)
\(\therefore\ \text{Area of Circle A = 9 × Area of Circle B} \)
The two triangles below are similar.
Find the length of \(ED\). (3 marks)
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\(ED = 15\)
\(\text{Using Pythagoras in}\ \Delta ABC: \)
\( AB=\sqrt{13^2-12^2}=\sqrt{25}=5 \)
\(\text{Scale factor}\ = \dfrac{FD}{AC} = \dfrac{39}{13} = 3 \)
\(\therefore ED = 3 \times AB = 3 \times 5 = 15 \)
A triangular prism is pictured below.
By what factor will its volume change if
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i. \(\text{Dimensions increase by a factor of 2}\)
\(\Rightarrow\ \text{Volume increases by a factor of}\ 2^3 = 8\)
ii. \(\text{Dimensions decrease by two-thirds}\)
\(\Rightarrow\ \text{i.e. adjust dimensions by a factor of}\ \ \dfrac{1}{3} \)
\(\Rightarrow\ \text{Volume decreases by a factor of}\ \Big{(} \dfrac{1}{3} \Big{)}^3 = \dfrac{1}{27} \)
Prove that the two triangles in the right cone pictured below are similar. (2 marks)
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\(\text{Proof (See Worked Solution)}\)
\(\angle ACD \ \text{is common to}\ \Delta ACE\ \text{and}\ \Delta BCD \)
\(\angle CAE=\angle CBD=90^\circ \ \text{(Right cone)} \)
\(\therefore \Delta ACE\ \text{|||}\ \Delta BCD\ \ \text{(equiangular)}\)
Show that \(\Delta ACD\) and \(\Delta DCB\) in the figure below are similar. (2 marks)
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\(\text{Proof (See Worked Solution)}\)
\(\angle BDC = 180-(88+44) = 48^{\circ} \ \text{(angle sum of Δ)} \)
\(\angle CAD = \angle CDB = 48^{\circ} \)
\(\angle ACD=44^{\circ} \ \text{is common to}\ \Delta ACD\ \text{and}\ \Delta BCD \)
\(\therefore \Delta ACD\ \text{|||}\ \Delta DCB\ \ \text{(equiangular)}\)
\(\text{Proof (See Worked Solution)}\)
\(\angle PQT = \angle SQR \ \text{(vertically opposite)} \)
\(\dfrac{PQ}{QS} = \dfrac{2.5}{5} = \dfrac{1}{2} \)
\(\dfrac{TQ}{QR} = \dfrac{2}{4} = \dfrac{1}{2} \)
\(\therefore \Delta PQT\ \text{|||}\ \Delta SQR\ \ \text{(sides adjacent to equal angles in proportion)}\)
Prove that this pair of triangles are similar. (2 marks)
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\(\text{Proof (See Worked Solution)}\)
\(\angle ACD = \angle BEA \ \text{(given)} \)
\(\angle BAE\ \text{is common to}\ \Delta ACD\ \text{and}\ \Delta BEA \)
\(\therefore \Delta ACD\ \text{|||}\ \Delta BEA\ \ \text{(equiangular)}\)
Prove that this pair of triangles are similar. (3 marks)
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\(\text{Proof (See Worked Solution)}\)
\(\text{Find unknown side}\ (x)\ \text{of smaller triangle}\)
\(\text{Using Pythagoras:}\)
\(x=\sqrt{5^2-4^2} = \sqrt{9} = 3\)
\(\dfrac{AC}{DE} = \dfrac{5}{15} = \dfrac{1}{3} \)
\(\dfrac{BC}{EF} = \dfrac{3}{9} = \dfrac{1}{3} \)
\(\angle ABC = \angle DEF = 90^{\circ} \ \ \text{(given)} \)
\(\therefore \Delta ABC\ \text{|||}\ \Delta DEF\ \ \text{(hypotenuse and second side of right-angled triangle in proportion)}\)
Prove that this pair of triangles are similar. (2 marks)
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\(\text{Proof (See Worked Solution)}\)
\(\dfrac{AB}{GH} = \dfrac{11}{22} = \dfrac{1}{2} \)
\(\dfrac{BC}{FG} = \dfrac{3.5}{7} = \dfrac{1}{2} \)
\(\angle ABC = \angle FGH = 95^{\circ} \ \ \text{(given)} \)
\(\therefore \Delta ABC\ \text{|||}\ \Delta HGF\ \ \text{(sides adjacent to equal angles in proportion)}\)
Prove that this pair of triangles are similar. (2 marks)
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\(\text{Proof (See Worked Solution)}\)
\(\angle ABE = \angle CBD\ \ \text{(vertically opposite)} \)
\(\angle AEB = \angle BCD\ \ \text{(alternate,}\ AE \parallel CD \text{)} \)
\(\therefore \Delta ABE\ \text{|||}\ \Delta DBC\ \ \text{(equiangular)}\)
Prove that this pair of triangles are similar. (2 marks)
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\(\text{Proof (See Worked Solution)}\)
\(\dfrac{RP}{AC} = \dfrac{18}{12} = \dfrac{3}{2} \)
\(\dfrac{QR}{BA} = \dfrac{12}{8} = \dfrac{3}{2} \)
\(\dfrac{PQ}{CB} = \dfrac{9}{6} = \dfrac{3}{2} \)
\(\therefore \Delta PQR\ \text{|||}\ \Delta CBA\ \ \text{(three pairs of sides in proportion)}\)
Triangle I and Triangle II are similar. Pairs of equal angles are shown.
Find the area of Triangle II? (3 marks)
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`24\ text{cm}^2`
`text(In Triangle I, using Pythagoras:)`
`text{Base}` | `= sqrt(5^2-3^2)` |
`= 4` |
`text(Triangle I ||| Triangle II (given))`
`=>\ text(corresponding sides are in the same ratio)`
`text{Scale factor}\ = 6/2=2`
`text{Scale factor (Area)}\ = 2^2=4`
`:. text(Area (Triangle II))` | `= 4 xx text{Area of triangle I}` |
`= 4 xx 1/2 xx 3 xx 4` | |
`=24\ text{cm}^2` |
Towns `A, B` and `C` are marked on the scale diagram below.
The distance from Town `A` to Town `B` is 9 km.
What is the distance, in kilometres, from Town `B` to Town `C`? (2 marks)
`3.6\ text(km)`
`text(Let)\ \ d = text(distance from Town)\ B\ text(to Town)\ \ C`
`text(S)text(ince the diagram is to scale,)`
`d/9` | `= 2/5` |
`:. d` | `= (9 xx 2)/5` |
`= 3.6\ text(km)` |
Spiro is making a scale drawing of his house.
What does 1 centimetre in Spiro's scale drawing represent in his real house?
`D`
`text(6 cm)` | `= 3\ text(m)` |
`= 300\ text(cm)` | |
`:. 1\ text(cm)` | `= 300 -: 6` |
`= 50\ text(cm)` |
`=>D`
Libby plays on a hockey field that is 120 metres long.
She makes a scale diagram of the field using a ratio of `1: 400`.
How long, in centimetres, should Libby make the scale diagram of the field? (2 marks)
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`text(30 cm)`
`text(Ratio is)\ \ 1:400`
`text{Converting to centimetres:}`
`text{120 m = 120 × 100 = 12 000 cm}`
`:.\ text(Length of the scale diagram)`
`=12\ 000 ÷ 400`
`= 30\ text(cm)`
Poppy uses a photocopier to enlarge this picture.
The enlarged picture is 3 times as high and 3 times as wide as the original.
By what factor is the area of the picture increased? (2 marks)
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`text(9 times the area of the original)`
`text{Method 1}`
`text{Dimensions increased by a factor of 3}`
`:.\ text{Area increased by a factor of}\ 3^2 = 9`
`text{Method 2}`
`text(Area of original picture)\ = 3 xx 5 = 15\ text(cm)^2`
`text(Area of enlarged picture)\ = 9 xx 15 = 135\ text(cm)^2`
`:.\ text(Factor)\ = 135/15 = 9\ text(times)`
Kransky has a photo which is 25 cm wide and 10 cm high
He wants to enlarge it to make a poster with a width of 50 cm.
What will be the height of the poster? (2 marks)
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`text(20 cm)`
`text(Scale factor)` | `= text(new width)/text(old width)` |
`= 50/25` | |
`= 2` |
`:.\ text(New height)` | `= 2 xx 10` |
`= 20\ text(cm)` |
The actual body length of a beetle Brad has caught is 24 mm.
A scale drawing of the beetle is shown below.
What scale is used in the drawing?
\(B\)
\(12\ \text{cm}\) | \(: 24\ \text{mm}\) |
\(120\ \text{mm}\) | \(: 24\ \text{mm}\) |
\(5\) | \(: 1\) |
\(1\ \text{cm}\) | \(: 2\ \text{mm (possible options)}\) |
\(\Rightarrow B\)
Juanita wanted to print a larger copy of her photo of a tree.
She increased the scale by a factor of 3.
She named the first picture Photo A and the second picture Photo B.
If Photo B is 3.2 cm high, how high is Photo A in centimetres, correct to 1 decimal place? (2 marks)
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`1.1\ text(cm)`
`text{Since Photo B is increased by a factor of 3,}`
`text(Height of Photo B)/text(Height of Photo A)` | `=3` |
`:.\ text(Height of Photo A)` | `=text(Height of Photo B)/3` |
`=3.2/3` | |
`=1.0666…` | |
`=1.1\ text{cm (1 d.p.)}` |
The picture below shows a flower.
The picture is 2 cm wide. The actual flower is 40 cm wide.
What scale is used in the picture?
`C`
`2:40\ \ =>\ \ 1:20`
`text(1 cm represents 20 cm)`
`=>C`
Two circles have the same centre, `O`, as shown in the diagram below.
The radius of the small circle is `2/3` the radius of the large circle.
Arc `CD` is 21 cm and the angle between the lines `AC` and `BD` is 45°.
What is the length of the arc `RS` in centimetres? (3 marks)
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`text(42 cm)`
`text{Circles are similar}`
`text(Arc)\ ST` | `= 2/3 xx text(arc)\ CD` |
`= 2/3 xx 21` | |
`= 14\ text(cm)` |
`angleSOR` | `= 180-45` |
`= 135^@` | |
`= 3 xx angleSOT` |
`:. text(Arc)\ RS` | `= 3 xx text(arc)\ ST` |
`= 3 xx 14` | |
`= 42\ text(cm)` |
Select the pair of similar triangles.
The triangles are not drawn to scale. (2 marks)
Triangle A | Triangle B | |
Triangle C | Triangle D | |
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`text(Triangles A and D)`
`text(Similar triangles are equiangular.)`
`text(Calculate triangle angles of each option.)`
`text(Triangle A: 55, 55, 70)`
`text(Triangle B: 50, 65, 65)`
`text(Triangle C: 50, 55, 65)`
`text(Triangle D: 55, 55, 70)`
`:.\ text{Triangles A and D are similar.}`
A traffic light is 2.4 m tall. Its shadow from a nearby floodlight is 3 m long.
What is the height of the floodlight? (3 marks)
`text(4.0 m)`
On a map, the distance between two towns is measured at 54 millimetres.
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i. `text{Convert both distance to the same unit (cm).}`
`text(54 mm)` | `= 5.4\ text(cm)` |
`text(16.2 km)` | `= 16\ 200\ text(m)` |
`= 1\ 620\ 000\ text(cm)` |
`:.\ text(Scale) \ \ 5.4\ ` | `: 1\ 620\ 000` |
`1\ ` | `: 300\ 000` |
ii. | `text(Actual distance)` | `= 9.2 xx 300\ 000` |
`= 2\ 760\ 000\ text(cm)` | ||
`= 27\ 600\ text(m)` | ||
`= 27.6\ text(km)` |
A map is drawn to scale, on 1-cm paper, showing the position of a supermarket and a cinema. A reservoir is also shown.
It takes 10 minutes to walk in a straight line from the cinema to the supermarket at a constant speed of 3 km/h. Show that the scale of the map is 1 cm = 100 m. (3 marks)
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`text(See Worked Solutions)`
`text(3 km/h = 3000 metres per 60 minutes)`
`text(In 10 minutes:)`
`text(Actual distance) = 3000 xx 10/60 = 500\ text(metres)`
`text(Distance on map = 5 cm)`
`:.\ text(Scale 5 cm)` | `: 500\ text(metres)` |
`text(1 cm)` | `: 100\ text(metres)` |
The scale on a given map is `1:80\ 000`.
If the actual distance between two points is 3.4 kilometres, how far apart on the map would be the two points be, in centimetres? (2 marks)
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`4.25\ text(cm)`
`text(Distance on map)`
`= text(real distance)/text(scale)`
`= text(3.4 km)/(80\ 000)`
`= text(3400 m)/(80\ 000)`
`= 0.0425\ text(m)`
`= 4.25\ text(cm)`
`C`
`text{Scale factor}\ =3/2 =1.5`
`:.\ x = 1.5 xx 12 = 18`
`text{Alternate solution}`
`text{Using sides of similar figures in the same ratio:}`
`x/12` | `=3/2` | |
`x` | `=12 xx (3/2)` | |
`x` | `=18` |
`=> C`
The diagrams show two similar shapes. The dimensions of the small shape are enlarged by a scale factor of 1.5 to produce the large shape.
Calculate the area of the large shape. (3 marks)
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`279\ text(cm)^2`
`text(Dimension of larger shape:)`
`text(Width) = 16 xx 1.5 = 24\ text(cm)`
`text(Height) = 9 xx 1.5 = 13.5\ text(cm)`
`text(Triangle height) = 2.5 xx 1.5 = 3.75\ text(cm)`
`:.\ text(Area)` | `= 24 xx (13.5-3.75) + 1/2 xx 24 xx 3.75` |
`= 279\ text(cm)^2` |
Two similar right-angled triangles are shown.
The length of side `AB` is 8 cm and the length of side `EF` is 4 cm.
The area of triangle `ABC` is 20 cm2.
Calculate the length in centimetres of side `DF` in Triangle II, correct to two decimal places. (4 marks)
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`7.55\ \text{cm}`
`text{Consider} \ Δ ABC :`
`text{Area}` | `= frac{1}{2} xx AB xx BC` |
`20` | `= frac{1}{2} xx 8 xx BC` |
`therefore \ BC` | `= 5` |
`text{Using Pythagoras in} \ Δ ABC :`
`AC = sqrt(8^2 + 5^2) = sqrt89`
`text{S} text{ince} \ Δ ABC\ text{|||}\ Δ DEF,`
`frac{AC}{BC}` | `= frac{DF}{EF}` |
`frac{sqrt89}{5}` | `= frac{DF}{4}` |
`therefore \ DF` | `= frac{4 sqrt89}{5}` |
`= 7.547 …` | |
`= 7.55 \ text{cm (to 2 d.p.)}` |
In `Delta ABC`, sides `AB` and `AC` have length 3, and `BC` has length 2. The point `D` is chosen on `AB` so that `DC` has length 2.
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i. `text(Prove)\ \ Delta ABC\ text(|||)\ Delta CBD`
`Delta ABC\ text{is isosceles:}`
`/_ ABC = /_ ACB qquad text{(angles opposite equal sides)}`
`Delta CBD\ text{is isosceles:}`
`/_ CBD = /_ CDB qquad text{(angles opposite equal sides)}`
`text{Since}\ \ /_ ABC = /_ CBD`
`:. Delta ABC\ text(|||)\ Delta CDB qquad text{(equiangular)}`
ii. `text(Using ratios of similar triangles)`
`(DB)/(CB)` | `= (BC)/(AC)` |
`{(3-AD)}/2` | `= 2/3` |
`3-AD` | `= 4/3` |
`:. AD` | `= 5/3` |
The width (`W`) of a river can be calculated using two similar triangles, as shown in the diagram.
What is the approximate width of the river?
`=> A`
`text{Triangles are similar (equiangular)}`
`text(Using similar ratios:)`
`W/(7.1)` | `= 20.3/8.1` |
`:. W` | `= (20.3 xx 7.1)/8.1` |
`= 17.79…` |
`=> A`
At a particular time during the day, a tower of height 19.2 metres casts a shadow. At the same time, a person who is 1.65 metres tall casts a shadow 5 metres long.
What is the length of the shadow cast by the tower at that time? (2 marks)
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`58\ text{m}`
`text(Both triangles have right angles and a common)`
`text(angle to the ground.)`
`:.\ text{Triangles are similar (equiangular)}`
`text(Let)\ x =\ text(length of tower shadow)`
`x/5` | `= 19.2/1.65\ \ text{(corresponding sides of similar triangles)}` |
|
`x` | `= (5 xx 19.2)/1.65` | |
`= 58.1818…` | ||
`= 58\ text{m (nearest m)}` |
`A`
`text(Take two corresponding sides)`
`text(In)\ Delta A:\ 3\ text(cm)`
`text(In)\ Delta B:\ 1 \frac{1}{2}\ text(cm)`
`:.\ text(Scale factor converting)\ Delta A\ text(to)\ Delta B = frac{1}{2}`
`=> A`
A point `P` lies between a tree, 2 metres high, and a tower, 8 metres high. `P` is 3 metres away from the base of the tree.
From `P`, the angles of elevation to the top of the tree and to the top of the tower are equal.
What is the distance, `x`, from `P` to the top of the tower?
`D`
`text(Triangles are similar)\ \ text{(equiangular)}`
`text(In smaller triangle:)`
`h^2` | `= 2^2 + 3^2` |
`= 13` | |
`h` | `= sqrt 13` |
`x/sqrt13` | `= 8/2\ \ \ text{(sides of similar Δs in same ratio)}` |
`x` | `= (8 sqrt 13)/2` |
`= 14.422…` |
`=> D`
Jacques and a flagpole both cast shadows on the ground. The difference between the lengths of their shadows is 3 metres.
What is the value of `d`, the length of Jacques’ shadow? (3 marks)
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`d = 1.8\ text(m)`
`text{Both triangles have right-angles with a common (ground) angle.}`
`:.\ text{Triangles are similar (equiangular)}`
` text{Since corresponding sides are in the same ratio}`
`d/1.5` | `= (d+3)/4` |
`4d` | `= 1.5(d + 3)` |
`8d` | `= 3(d + 3)` |
`= 3d + 9` | |
`5d` | `= 9` |
`:.d` | `= 9/5` |
`=1.8\ text(m)` |
A map has a scale of 1 : 500 000.
What is the actual distance between the two mountain peaks, in kilometres? (1 mark)
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i. `text{Actual distance (2 cm)}` | `= 2 xx 500\ 000` |
`= 1\ 000\ 000\ text(cm)` | |
`= 10\ 000\ text(m)` | |
`=10\ text(km)` |
`:.\ text(The 2 mountain peaks are 10 km apart.)`
ii. `text(Cities are 75 km apart.)`
`text{From part (i), we know 2 cm = 10 km}`
`=>\ text(1 cm = 5 km)`
`=>\ text(On the map, 75 km)= 75/5=15\ text(cm)`
`:.\ text(Distance on the map is 15 cm.)`
Triangles `ABC` and `DEF` are similar.
Which expression could be used to find the value of `x`?
`C`
`text(We know)\ \ Delta ABC\ text(|||)\ Delta DEF`
`:.\ (AB)/(AC)` | `=y/10=(DE)/(DF)=x/15` |
`x/15` | `=y/10` |
`x` | `=yxx15/10` |
`=> C`