Riley borrowed $4000 at a simple interest rate of 6% per annum. The loan is to be repaid as a single lump sum at the end of 8 months.
Calculate the total amount Riley must repay. (2 marks)
--- 4 WORK AREA LINES (style=lined) ---
Aussie Maths & Science Teachers: Save your time with SmarterEd
Riley borrowed $4000 at a simple interest rate of 6% per annum. The loan is to be repaid as a single lump sum at the end of 8 months.
Calculate the total amount Riley must repay. (2 marks)
--- 4 WORK AREA LINES (style=lined) ---
\(\$4160\)
| \(\text{Interest}\) | \(=Prn\) |
| \(=4000\times 0.06\times \dfrac{8}{12}=\$160\) |
\(\therefore\ \text{Total repayment} =4000+160=\$4160\)
Olivia borrowed $3600 at 8% per annum.
Calculate the simple interest for the first 5 months. (2 marks)
--- 4 WORK AREA LINES (style=lined) ---
\(\$120\)
| \(\text{Interest}\) | \(=Prn\) |
| \(=3600\times 0.08\times \dfrac{5}{12}=\$120\) |
Chloe invests $5000 for 2 years and 3 months. Simple interest is paid on the investment at a rate of 4% per annum.
What is the total value of the investment at the end of this period?
\(D\)
\(\text{2 years and 3 months = 27 months}\)
\(I=Prn=5000 \times 0.04 \times \dfrac{27}{12}=\$450\)
\(\therefore\ \text{Value of Investment} =5000+450=\$5450\)
\(\Rightarrow D\)
Ava is saving for a trip to Bali. She invests an amount of money at a simple interest rate of 3.5% per annum. After 2 years, she has earned $210 in interest.
How much money did Ava originally invest?
\(C\)
\(I=\$210,\ r=3.5\%=0.035,\ n=2\ \text{years}\)
\(\text{Using}\ \ I=Prn\ \ \text{to find}\ P:\)
| \(I\) | \(=Prn\) | |
| \(P\) | \(=\dfrac{I}{r \times n}=\dfrac{210}{0.035 \times 2}=\$3000\) |
\(\Rightarrow C\)
Liam invests $7500 in a term deposit with Westpac that pays simple interest at a rate of 5% per annum.
How much interest is earned over the first 4 years?
\(C\)
\(P=\$7500,\ r=5\%=0.05,\ n=4\ \text{years}\)
\(I=Prn=7500 \times 0.05 \times 4=\$1500\)
\(\Rightarrow C\)
Reece is preparing his annual budget for 2006.
His expected income is:
• $90 every week as a swimming coach
• Interest earned from an investment of $4500 at a rate of 4% per annum.
His planned expenses are:
• $30 every week on transport
• $12 every week on lunches
• $48 every month on entertainment.
Reece will save his remaining income. He uses the spreadsheet below for his budget.
--- 5 WORK AREA LINES (style=lined) ---
At the beginning of 2006, Reece starts saving.
--- 4 WORK AREA LINES (style=lined) ---
i. `text(Interest on Investment) = X`
| `X` | `= 4500 xx 4 text(%)` |
| `= $180` |
`text(Transport =)\ Y`
| `Y` | `= 52 × 30` |
| `= $1560` |
`text(Entertainment =)\ Z`
| `Z` | `= 48 × 12` |
| `= $576` |
| ii. | `text(Total Income)` | `= 4680 + 180` |
| `= $4860` |
| `text(Total Expenses)` | `= 1560 + 624 + 576` |
| `= $2760` |
| `text(Savings)` | `= 4860 − 2760` |
| `= $2100` |
`:.\ text(Reece will NOT have saved enough for)`
`text(a $2500 deposit.)`
Jared borrowed $9 000. He repaid the loan in full at the end of three years with a lump sum of $10 350.
What annual simple interest rate was he charged?
`C`
`text(Total interest paid) = 10\ 350-9000 = $1350`
| `I` | `=Prn` |
| `1350` | `=9000 xx r xx 3` |
| `r` | `=1350/(27\ 000)` |
| `=5 text(%)` |
`=> C`
Lina invests $2500 for 1 year and 2 months. The simple interest is calculated at a rate of 5% per annum.
What is the total value of the investment at the end of this period?
`C`
| `text(Interest)` | `=Prn` |
| `=2500 xx \text(5%)\ xx 14/12` | |
| `=$130` |
| `:.\ text(Value of Investment)` | `=2500+130` |
| `=$2630` |
`=> C`
Jan borrowed $1500 at 6% per annum.
Calculate the simple interest for the first three months. (2 marks)
--- 4 WORK AREA LINES (style=lined) ---
\($22.50\)
| \(\text{Interest}\) | \(=Prn\) |
| \(=1500\times 0.06\times \dfrac{3}{12}=$22.50\) |
Bobby invested $5000. The table shows the progress of his investment over the first 4 months. --- 4 WORK AREA LINES (style=lined) --- --- 4 WORK AREA LINES (style=lined) --- a. \(A=$30.54,\ \ B=$5121.08\) b. \($124\) b. \(P=$5000,\ \ r=\dfrac{0.62}{100},\ \ n=4\)
a.
\(A\)
\(=5090.54\times\dfrac{0.6}{100}\)
\(=$30.54\text{ (2 d.p.)}\)
\(B\)
\(=5090.54+30.54\)
\(=$5121.08\)
\(I\)
\(=Prn\)
\(=5000\times \dfrac{0.62}{100}\times 4\)
\(=$124\)
An amount of $2500 is invested at a simple interest rate of 3% per annum.
How much interest is earned in the first two years?
\(B\)
| \(I\) | \(=Prn\) |
| \(=2500 \times\ \dfrac{3}{100} \times\ 2=$150\) |
\(\Rightarrow B\)
What is the interest earned when $800 is invested for 7 months at a simple interest rate of 3% per annum? (2 marks)
`$14`
| `text(Interest)` | `= Prn` |
| `= 800 xx 0.03 xx 7/12= $14` |
George makes a single deposit of $9000 into an account that pays simple interest.
After 4 years, George's account has a balance of $10 350.
What simple interest rate did George receive on his investment? (2 marks)
--- 4 WORK AREA LINES (style=lined) ---
`3.75text(%)`
`text(Interest earned)= 10\ 350-9000= $1350`
`text(Using)\ \ I = Prn,`
| `1350` | `= 9000 xx r xx 4` |
| `:. r` | `= 1350/(4 xx 9000)= 0.0375= 3.75text(%)` |
$6000 is invested in an account that earns simple interest at the rate of 3.5% per annum.
The total interest earned in the first four years is
`D`
`P = 6000,\ \ r = 3.5text(%),\ \ n = 4`
| `I` | `= Prn` |
| `= 6000 xx 3.5/100 xx 4= 840` |
`=> D`
Reece is preparing his annual budget for 2006.
His expected income is:
• $90 every week as a swimming coach
• Interest earned from an investment of $5000 at a rate of 4% per annum.
His planned expenses are:
• $30 every week on transport
• $12 every week on lunches
• $48 every month on entertainment.
Reece will save his remaining income. He uses the spreadsheet below for his budget.
--- 5 WORK AREA LINES (style=lined) ---
At the beginning of 2006, Reece starts saving.
--- 4 WORK AREA LINES (style=lined) ---
a. `X =$200, Y = $1560\ text(and) \ Z = $576`
b. `text(Reece will have saved have saved enough for a $2100 deposit.)`
a. `text(Interest on Investment) (X)=5000 xx 4%= $200`
`text(Transport)(Y)= 52 × 30= $1560`
`text(Entertainment) (Z)= 48 × 12= $576`
b. `text(Total Income)= 4680 + 200= $4880`
`text(Total Expenses)= 1560 + 624 + 576= $2760`
`text(Savings)= 4880-2760= $2120`
`:.\ text(Reece will have saved enough for a $2100 deposit.)`
Lilly and Rose each have money to invest and choose different investment accounts.
The graph shows the values of their investments over time.
--- 1 WORK AREA LINES (style=lined) ---
--- 4 WORK AREA LINES (style=lined) ---
--- 2 WORK AREA LINES (style=lined) ---
`text{Rose 1 year longer (15 years) to reach the same value}`
i. `$5000\ text{(} y text(-intercept) text{)}`
ii. `text(After 6 years,)`
| `text(Lilly’s investment)` | `= $9000` |
| `text(Rose’s investment)` | `= $11\ 000` |
| `:.\ text(Rose’s is worth $2000 more.)` | |
iii. `text(It takes Lilly 14 years to reach $20 000 and it)`
`text{takes Rose 1 year longer (15 years) to reach the}`
`text(same value.)`
Lou bought a plasma TV which was priced at $3499. He paid $1000 deposit and got a loan for the balance that was paid off by 24 monthly instalments of $135.36.
What simple interest rate per annum, to the nearest percent, was charged on his loan?
\(B\)
\(\text{Loan = Price}\ -\ \text{Deposit}= 3499-1000= \$2499\)
\(\text{Total repaid}= 24 \times 135.36= \$3248.64\)
\(\text{Interest paid}= 3248.64-2499= \$749.64\)
| \(\text{Simple Interest}\) | \(= Prn\) |
| \(749.64\) | \(= 2499 \times r \times 2\) |
| \(\therefore r\) | \(= \dfrac{749.64}{2 \times 2499}= 0.1499\ …\approx 15\%\) |
\(\therefore B\)
Minjy invests $2000 for 1 year and 5 months. The simple interest is calculated at a rate of 6% per annum.
What is the total value of the investment at the end of this period?
\(A\)
\(\text{1 year and 5 months = 17 months}\)
\(I=Prn=2000 \times 6\%\ \times \dfrac{17}{12}=\$170\)
\(\therefore\ \text{Value of Investment} =2000+170=\$2170\)
\(\Rightarrow A\)
Polly borrowed $11 000. She repaid the loan in full at the end of two years with a lump sum of $12 000.
What annual simple interest rate was she charged?
`B`
`text(Total interest paid)=12\ 000-11\ 000=$1000`
| `I` | `=Prn` |
| `1000` | `=11\ 000 xx r xx2` |
| `r` | `=1000/(22\ 000)=4.55 text(%)` |
`=>\ B`
Lynne invests $1000 for a term of 15 months. Simple interest is paid on the investment at a rate of 3.75% per annum.
How much will Lynne's investment be worth at the end of the term?
`A`
`I=Prn=1000xx3.75/100xx15/12=$46.88`
`:.\ text(Investment worth)\ = 1000+46.88=$1046.88`
`=>\ A`