Which of the following compounds can be correctly described as an Arrhenius base when dissolved in water?
- Sodium nitrate
- Sodium sulfate
- Sodium chloride
- Sodium hydroxide
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Which of the following compounds can be correctly described as an Arrhenius base when dissolved in water?
\(D\)
→ An Arrhenius base is a compound that increases the concentration of \(\ce{OH-}\) ions when it is dissolved in water.
→ Sodium hydroxide is the only compound that dissolves in water to produce hydroxide ions.
\(\ce{NaOH(s) -> Na+(aq) + OH-(aq)}\)
\(\Rightarrow D\)
Explain how the following substances would be classified under the Arrhenius and Brønsted-Lowry definitions of acids. Support your answer with relevant equations. (4 marks)
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→ Acids are defined by Arrhenius as hydrogen-containing compounds that dissociate in water to give \(\ce{H+}\) ions.
→ \(\ce{HCl(aq)}\) produces \(\ce{H+}\) ions in water and therefore qualifies within Arrhenius’ definition of an acid.
\(\ce{HCl(aq) \rightarrow H+(aq) + Cl−(aq)}\)
→ The salt \(\ce{NH4Cl}\) would not be recognised as an acid with Arrhenius’ definition, since the predominant ions present in aqueous solution are ammonium and chloride.
→ The Brønsted−Lowry theory states that acids are proton donors. \(\ce{HCl(aq)}\) is a proton donor and therefore also qualifies as a Brønsted−Lowry acid.
→ In contradiction to Arrhenius, ammonium chloride \(\ce{(NH4Cl)}\) is also classified as a Brønsted−Lowry acid. This is due to the ammonium ion donating a proton to water to form a hydronium ion.
\(\ce{NH4+(aq) + H2O(l) \rightleftharpoons NH3(aq) + H3O+(aq)}\)
→ Acids are defined by Arrhenius as hydrogen-containing compounds that dissociate in water to give \(\ce{H+}\) ions.
→ \(\ce{HCl(aq)}\) produces \(\ce{H+}\) ions in water and therefore qualifies within Arrhenius’ definition of an acid.
\(\ce{HCl(aq) \rightarrow H+(aq) + Cl−(aq)}\)
→ The salt \(\ce{NH4Cl}\) would not be recognised as an acid with Arrhenius’ definition, since the predominant ions present in aqueous solution are ammonium and chloride.
→ The Brønsted−Lowry theory states that acids are proton donors. \(\ce{HCl(aq)}\) is a proton donor and therefore also qualifies as a Brønsted−Lowry acid.
→ In contradiction to Arrhenius, ammonium chloride \(\ce{(NH4Cl)}\) is also classified as a Brønsted−Lowry acid. This is due to the ammonium ion donating a proton to water to form a hydronium ion.
\(\ce{NH4+(aq) + H2O(l) \rightleftharpoons NH3(aq) + H3O+(aq)}\)
Which of the following is NOT a Bronsted-Lowry reaction?
`B`
→ A Bronsted-Lowry reaction occurs when one species (acid) transfers a proton to another species (base).
→ Although it is an acid-base reaction, no proton transfer occurs in \(\ce{CO2 + OH^- \rightleftharpoons HCO3^-}\)
`=> B`
Which of the following would NOT have been classified as an acid by Antoine Lavoisier in 1780?
`D`
→ A Levoisier acid must contain oxygen.
→ \(\ce{HCl}\) does not contain oxygen.
`=>D`
The equipment shown is set up. After some time a ring of white powder is seen to form on the inside of the glass tube.
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a. According to Arrhenius:
→ An acid is a solution that produces hydrogen ions when in a solution.
→ A base is a solution that produces hydroxide ions when in a solution.
→ This reaction does not occur in an aqueous solution and would not be an acid-base reaction according to Arrhenius.
b. \(\ce{HCl(g) + NH3(g) -> NH4+ + Cl-}\)
→ A Bronsted-Lowry acid donates a proton while a base accepts a proton.
→ This reaction involves proton transfer (\(\ce{HCl}\) donates, \(\ce{NH3}\) receives) and would therefore be considered a Bronsted-Lowry acid-base reaction.
a. According to Arrhenius:
→ An acid is a solution that produces hydrogen ions when in a solution.
→ A base is a solution that produces hydroxide ions when in a solution.
→ This reaction does not occur in an aqueous solution and would not be an acid-base reaction according to Arrhenius.
b. \(\ce{HCl(g) + NH3(g) -> NH4+ + Cl-}\)
→ A Bronsted-Lowry acid donates a proton while a base accepts a proton.
→ This reaction involves proton transfer (\(\ce{HCl}\) donates, \(\ce{NH3}\) receives) and would therefore be considered a Bronsted-Lowry acid-base reaction.
Assess the usefulness of the Brønsted-Lowry model in classifying acids and bases. Support your answer with at least TWO chemical equations. (5 marks)
→ The Bronsted-Lowry model is a way of classifying acids and bases based on their ability to donate or accept protons.
→ This model is more comprehensive than the Arrhenius model, as it can explain the acid-base behaviour of more species, including those that do not contain \(\ce{OH-}\) ions, and non-aqueous acid-base reactions.
→ Consider the reaction \(\ce{NH3(g) + HCl(g) -> NH4Cl(s)}\) where a proton is transferred from hydrogen chloride to ammonia (according to the Bronsted-Lowry model). Ammonia is not an Arrhenius base as it doesn’t dissociate to produce \(\ce{OH-}\) ions and the reaction cannot be described using the Arrhenius model.
→ However, the Bronsted-Lowry model does have some limitation, such as its inability to explain the acidity of certain acidic oxides and their reactions with basic oxides.
→ e.g. \(\ce{CaO(s) + SO3(g) -> CaSO4(s)}\) is an acid-base reaction but since there is no proton transfer, it cannot be described using the Bonsted-Lowry model.
→ The Bronsted-Lowry model is a way of classifying acids and bases based on their ability to donate or accept protons.
→ This model is more comprehensive than the Arrhenius model, as it can explain the acid-base behaviour of more species, including those that do not contain \(\ce{OH-}\) ions, and non-aqueous acid-base reactions.
→ Consider the reaction \(\ce{NH3(g) + HCl(g) -> NH4Cl(s)}\) where a proton is transferred from hydrogen chloride to ammonia (according to the Bronsted-Lowry model). Ammonia is not an Arrhenius base as it doesn’t dissociate to produce \(\ce{OH-}\) ions and the reaction cannot be described using the Arrhenius model.
→ However, the Bronsted-Lowry model does have some limitation, such as its inability to explain the acidity of certain acidic oxides and their reactions with basic oxides.
→ e.g. \(\ce{CaO(s) + SO3(g) -> CaSO4(s)}\) is an acid-base reaction but since there is no proton transfer, it cannot be described using the Bonsted-Lowry model.
Which of the following is an Arrhenius base?
`B`
Arrhenius bases produce `text{OH}^(-)` ions when dissolved in water.
`=>B`
The effect of concentration on the pH of acrylic acid `(text{C}_2 text{H}_3 text{COOH})` and hydrochloric acid `(text{HCl})` solutions is shown in the graph. Both of these acids are monoprotic.
Explain the trends in the graph. Include relevant chemical equations in your answer. (4 marks)
\(\ce{HCl(aq) -> H+ (aq) + Cl– (aq)}\)
\(\ce{C2H3COOH(aq) \rightleftharpoons H+ (aq) + C2H3COO– (aq)}\)
→ \(\ce{HCl}\) is a strong acid that fully dissociates in water, resulting in a high concentration of \(\ce{H+}\) ions and a low pH.
→ Acrylic acid, on the other hand, is a weak acid that only partially dissociates in water, resulting in a lower concentration of \(\ce{H+}\) ions and a higher pH.
→ When the concentration of \(\ce{HCl}\) decreases by a factor of 10, its pH increases by 1 due to the decrease in \(\ce{H+}\).
→ However, when the concentration of acrylic acid decreases by a factor of 10, its pH increases by less than 1.
→ This is due to the change in pH causing the equilibrium to shift right, producing more \(\ce{H+}\) ions in response to the dilution, resulting in a smaller change in the concentration of \(\ce{H+}\), and thus smaller change in pH.
→ At very dilute concentrations, the degree of dissociation of acrylic acid approaches 100% and its pH converges closely to that of \(\ce{HCl}\).
\(\ce{HCl(aq) -> H+ (aq) + Cl– (aq)}\)
\(\ce{C2H3COOH(aq) \rightleftharpoons H+ (aq) + C2H3COO– (aq)}\)
→ \(\ce{HCl}\) is a strong acid that fully dissociates in water, resulting in a high concentration of \(\ce{H+}\) ions and a low pH.
→ Acrylic acid, on the other hand, is a weak acid that only partially dissociates in water, resulting in a lower concentration of \(\ce{H+}\) ions and a higher pH.
→ When the concentration of \(\ce{HCl}\) decreases by a factor of 10, its pH increases by 1 due to the decrease in \(\ce{H+}\).
→ However, when the concentration of acrylic acid decreases by a factor of 10, its pH increases by less than 1.
→ This is due to the change in pH causing the equilibrium to shift right, producing more \(\ce{H+}\) ions in response to the dilution, resulting in a smaller change in the concentration of \(\ce{H+}\), and thus smaller change in pH.
→ At very dilute concentrations, the degree of dissociation of acrylic acid approaches 100% and its pH converges closely to that of \(\ce{HCl}\).
The pH of two aqueous solutions was compared.
Explain why the `\text{HCN}(aq)` solution has a higher pH than the `\text{HCl}(aq)` solution. Include a relevant chemical equation for the `\text{HCN}(aq)` solution. (3 marks)
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→ \( \ce{HCl} \) is a strong acid, ie it completely ionises in water to form \( \ce{H+} \) ions.
→ On the other hand, \( \ce{HCN} \) is a weak acid, ie it partially ionises in water to form \( \ce{H+} \) ions.
\( \ce{HCl(aq) -> H+ (aq) + Cl- (aq)} \)
\( \ce{HCN(aq) \rightleftharpoons H+ (aq) + CN– (aq)}\)
→ As \( \ce{[H+]} \) decreases, pH increases (\( \ce{\text{pH} = – log [H+]} \))
→ Therefore, at the same 0.2M, the \( \ce{HCN} \) solution would have a lower \( \ce{[H+]} \) and thus would have a higher pH than \( \ce{HCl} \).
→ \( \ce{HCl} \) is a strong acid, ie it completely ionises in water to form \( \ce{H+} \) ions.
→ On the other hand, \( \ce{HCN} \) is a weak acid, ie it partially ionises in water to form \( \ce{H+} \) ions.
\( \ce{HCl(aq) -> H+ (aq) + Cl- (aq)} \)
\( \ce{HCN(aq) \rightleftharpoons H+ (aq) + CN– (aq)}\)
→ As \( \ce{[H+]} \) decreases, pH increases (\( \ce{\text{pH} = – log [H+]} \))
→ Therefore, at the same 0.2M, the \( \ce{HCN} \) solution would have a lower \( \ce{[H+]} \) and thus would have a higher pH than \( \ce{HCl} \).
The following equation describes an equilibrium reaction.
\( \ce{HF(aq) + PO4^3-(aq) \rightleftharpoons HPO4^2-(aq) + F-(aq)} \)
Identify ONE base and its conjugate acid in the above equation. (2 marks)
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Possible answers:
\begin{array} {ll}
\text{Base} & \text{Conjugate Acid} \\
\hline \ce{PO4^3-(aq)} & \ce{HPO4^2-(aq)} \\
\ce{F-(aq)} & \ce{HF(aq)} \\
\end{array}
Possible answers:
\begin{array} {ll}
\text{Base} & \text{Conjugate Acid} \\
\hline \ce{PO4^3-(aq)} & \ce{HPO4^2-(aq)} \\
\ce{F-(aq)} & \ce{HF(aq)} \\
\end{array}