Determine the standard deviation of the following dataset, giving your answer correct to one decimal place. (1 mark)
\(13, \ 14, \ 18, \ 18, \ 23, \ 27, \ 31\)
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Determine the standard deviation of the following dataset, giving your answer correct to one decimal place. (1 mark)
\(13, \ 14, \ 18, \ 18, \ 23, \ 27, \ 31\)
\(\text{Std Dev}\ = 6.2\)
\(\text{By calculator (using Statistics mode):} \)
\(\text{Std Dev}\ = 6.207… = 6.2\ \text{(1 d.p.)} \)
Rhonda and her friends were surveyed about the number of concerts they have been to in the last 12 months.
Their responses are as follows:
\(3, \ 4, \ 8, \ 10, \ 12, \ 13\)
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i. \(\text{Median}\ = 9\)
ii. \(\text{Std Dev}\ = 3.8\)
i. \(3, \ 4, \ 8, \ 10, \ 12, \ 13\)
\(\text{6 data points}\)
\(\text{Median}\ = \dfrac{\text{3rd + 4th}}{2} = \dfrac{8+10}{2} = 9 \)
ii. \(\text{By calculator (using Statistics mode):} \)
\(\text{Std Dev}\ = 3.771… = 3.8\ \text{(1 d.p.)} \)
Albert teaches Physics and sets his class a mid-term exam.
The results are summarised in the Stem and Leaf plot drawn below.
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i. \(\text{Median}\ = 83\)
ii. \(\text{Std Dev}\ = 12.14\)
i. \(\text{Dataset values:}\ 62, 65, 78, 79, 83, 89, 94, 96, 97 \)
\(\text{9 data points}\ \ \Rightarrow\ \ \text{Median = 5th value} \)
\(\text{Median}\ = 83\)
ii. \(\text{By calculator (using Statistics mode):} \)
\(\text{Std Dev}\ = 12.139… = 12.14\ \text{(2 d.p.)} \)
Seven 40-year old males are asked how many children they have in a survey.
The results are summarised in the histogram drawn below.
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i. \(\text{Mean}\ = 2.57\)
ii. \(\text{Std Dev}\ = 1.05\)
i. \(\text{Dataset values:}\ 1, 2, 2, 2, 3, 4, 4 \)
\(\text{Mean}\ = \dfrac{1+2+2+2+3+4+4}{7} = \dfrac{18}{7} = 2.571… = 2.57\ \text{(2 d.p.)} \)
ii. \(\text{By calculator (using Statistics mode):} \)
\(\text{Std Dev}\ = 1.049… = 1.05\ \text{(2 d.p.)} \)
A dataset is represented by the dot plot drawn below.
Determine the standard deviation of the dataset, giving your answer correct to two decimal places. (2 marks)
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\(\text{Std Dev}\ = 1.25\)
\(\text{Dataset values:}\ 0, 1, 1, 2, 2, 3, 4 \)
\(\text{By calculator (using Statistics mode):}\)
\(\text{Std Dev}\ = 1.245… = 1.25\ \text{(2 d.p.)} \)
Isa Guha recorded the number of sixes hit in the first nine games of the Women's Big Bash Cricket League over two seasons.
The results are recorded in the two dot plots below.
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i. \(\text{Std Dev}\ = 1.9\ \text{(1 d.p.)} \)
ii. \(\text{By inspection, season 1 has a slightly higher range}\)
\(\text{(5 vs 4) and its data points can be seen to be much}\)
\(\text{wider spread about the expected mean value.}\)
\(\text{Season 1 will therefore have a higher standard deviation.}\)
i. \(\text{Season 1 dataset:}\ 6, 6, 7, 8, 10, 10, 10, 11, 11\)
\(\text{By calculator (using Statistics mode):}\)
\(\text{Std Dev}\ = 1.930… = 1.9\ \text{(1 d.p.)} \)
ii. \(\text{By inspection, season 1 has a slightly higher range}\)
\(\text{(5 vs 4) and its data points can be seen to be much}\)
\(\text{wider spread about the expected mean value.}\)
\(\text{Season 1 will therefore have a higher standard deviation.}\)
In a cricket test match, a scorebook recorded the number of runs scored by England's top six batsman.
The scores are summarised in the Stem and Leaf plot below.
Determine the standard deviation of the scores, giving your answer correct to one decimal place. (2 marks)
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\(\text{Std Dev}\ = 6.6\)
\(\text{Runs scored dataset:}\ 8, 12, 15, 21, 23, 27 \)
\(\text{By calculator (using Statistics mode):}\)
\(\text{Std Dev}\ = 6.574… = 6.6\ \text{(1 d.p.)} \)
Ms Arnott has seven students in her Ethics class. The results of the most recent exam, completed by the whole class, is summarised in the Stem and Leaf plot below.
Determine the standard deviation of the exam results, giving your answer correct to one decimal place. (2 marks)
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\(\text{Std Dev}\ = 8.8\)
\(\text{Exam result dataset:}\ 56, 63, 69, 72, 77, 78, 84 \)
\(\text{By calculator (using Statistics mode):}\)
\(\text{Std Dev}\ = 8.84… = 8.8\ \text{(1 d.p.)} \)
Seven players in two basketball teams, the Swifties and the Chiefs, recorded how many 3-point baskets they had shot in the last season.
The results are recorded in the two Stem and Leaf plots below.
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i. \(\text{Std Dev}\ = 13.4 \)
ii. \(\text{The results of the Chiefs have a much smaller range (18 vs 38)}\)
\(\text{and are a much tighter fit around the expected mean.}\)
\(\text{The Chiefs’ results will therefore have a smaller standard deviation.}\)
i. \(\text{Swifties’ dataset:}\ 1, 2, 17, 22, 26, 33, 39 \)
\(\text{By calculator (using Statistics mode):}\)
\(\text{Std Dev}\ = 13.43… = 13.4\ \text{(1 d.p.)} \)
ii. \(\text{The results of the Chiefs have a much smaller range (18 vs 38)}\)
\(\text{and are a much tighter fit around the expected mean.}\)
\(\text{The Chiefs’ results will therefore have a smaller standard deviation.}\)
9 students completed two quizzes and the results were summarised in the dot plot diagrams below.
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i. \(\text{Median}\ = 7\)
ii. \(\text{Std Dev (Quiz A)}\ = 1.3 \)
\(\text{Std Dev (Quiz B)}\ = 0.8\)
i. \(\text{9 data points}\ \ \Rightarrow \ \ \text{Median = 5th data point}\)
\(\text{Median}\ = 7 \)
ii. \(\text{By calculator (using Statistics mode):}\)
\(\text{Quiz A dataset:}\ 5, 5, 6, 7, 7, 8, 8, 8, 9 \)
\(\text{Std Dev (Quiz A)}\ = 1.33… = 1.3\ \text{(1 d.p.)} \)
\(\text{Quiz B dataset:}\ 6, 6, 7, 7, 7, 8, 8, 8, 8 \)
\(\text{Std Dev (Quiz B)}\ = 0.78… = 0.8\ \text{(1 d.p.)} \)
Two data sets are represented in the dot plot diagrams below.
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i. \(\text{Std Dev}\ = 1.79… = 1.8\ \text{(1 d.p.)} \)
ii. \(\text{By inspection, Data Set A has a smaller range and a tighter}\)
\(\text{spread against its expected mean value.}\)
\(\text{Data Set B will therefore have a higher standard deviation.}\)
i. \(\text{Data points:}\ 4, 4, 5, 5, 6, 6, 7, 8, 9, 9\)
\(\text{By calculator (using Statistics mode):} \)
\(\text{Std Dev}\ = 1.79... = 1.8\ \text{(1 d.p.)} \)
ii. \(\text{By inspection, Data Set A has a smaller range and a tighter}\)
\(\text{spread against its expected mean value.}\)
\(\text{Data Set B will therefore have a higher standard deviation.}\)
In a small business, the seven employees earn the following wages per week:
\(\$300, \ \$490, \ \$520, \ \$590, \ \$660, \ \$680, \ \$970\)
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Explain the effect that this increase will this have on the standard deviation? (2 marks)
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i. \(191.0\)
ii. \(\text{All values increase by \$20, but so too does the mean.} \)
\(\text{Therefore the spread about the new mean will not change} \)
\(\text{and therefore the standard deviation will remain the same.} \)
i. \(\text{By calculator (in Statistics mode:}\)
\(\text{Std Dev}\ = 191.044... =191.0\ \text{(1 d.p.)} \)
ii. \(\text{All values increase by \$20, but so too does the mean.} \)
\(\text{Therefore the spread about the new mean will not change} \)
\(\text{and therefore the standard deviation will remain the same.} \)
Ali’s class sits a Geography test and the results are recorded below.
\(58,\ \ 74,\ \ 65,\ \ 66,\ \ 73,\ \ 71,\ \ 72,\ \ 74,\ \ 62,\ \ 70\)
The mean for the test was 68.5.
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i. \(5.2\ \ \text{(to 1 d.p.)} \)
ii. \(\text{Median}\ = \dfrac{70+71}{2} = 70.5 \)
\(\Rightarrow\ \text{Median > Mean (70.5 > 68.5)} \)
i. \(\text{By calculator (in Statistics mode):}\)
\(\text{Std Dev}\ = 5.220… = 5.2\ \text{(1 d.p.)} \)
ii. \(\text{Reorder test results in ascending order:}\)
\(58,\ \ 62,\ \ 65,\ \ 66,\ \ 70, \ \ 71,\ \ 72,\ \ 73,\ \ 74,\ \ 74\)
\(\text{Median}\ = \dfrac{70+71}{2} = 70.5 \)
\(\Rightarrow\ \text{Median > Mean (70.5 > 68.5)} \)
The ages of nine students were recorded in the table below.
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i. \(\text{By calculator (in Statistics mode):} \)
\(\text{Std Dev}\ = 1.5947… = 1.59\ \ \text{(to 2 d.p.)} \)
ii. \(\text{Standard deviation is a measure of how much members}\)
\(\text{of a data group differ from the mean value of the group.}\)
i. \(\text{By calculator (in Statistics mode):} \)
\(\text{Std Dev}\ = 1.5947… = 1.59\ \ \text{(to 2 d.p.)} \)
ii. \(\text{Standard deviation is a measure of how much members}\)
\(\text{of a data group differ from the mean value of the group.}\)
Jamal surveyed eight households in his street. He asked them how many kilolitres (kL) of water they used in the last year. Here are the results.
`220, 105, 101, 450, 37, 338, 151, 205`
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i. | `text(Mean)` | `= (220 + 105 + 101 + 450 + 37 + 338 + 151 + 205) ÷ 8` |
`= 200.875` |
ii. | `text(Std Dev)` | `= 127.357…\ \ text{(by calc)}` |
`= 127.4\ \ text{(1 d.p.)}` |