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Probability, STD1 S2 2022 HSC 3 MC

A jar contains 12 red, 10 black and 13 white lollies.

Alex picks out a red lolly and eats it. He then randomly picks a second lolly.

What is the probability that the second lolly is also red?

  1. `(11)/(34)`
  2. `(11)/(35)`
  3. `(12)/(34)`
  4. `(12)/(35)`
Show Answers Only

`A`

Show Worked Solution
`P(E)` `=text{favourable outcomes}/text{total outcomes}`  
  `=(12-1)/((12-1)+10+13)=11/34`  

 
`=>A`

Filed Under: Single and Multi-Stage Events, Single and Multi-Stage Events Tagged With: Band 4, smc-1135-20-Other Multi-Stage Events, smc-6887-50-Other Multi-stage Events

Probability, STD1 S2 2021 HSC 20

In a bag, there are six playing cards, 2, 4, 6, 8, Queen and King. The Queen and King are known as picture cards.

Two of these cards are chosen randomly. All the possible outcomes are shown.
 

   
 

  1. What is the probability that the two cards chosen include one or both picture cards?   (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  2. What is the probability that the two cards chosen do NOT include any picture cards?   (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

Show Answers Only
  1. `9/15=3/5`
  2. `6/15=2/5`
Show Worked Solution

a.   `P text{(at least 1 picture card)} = 9/15=3/5`

 

b.    `P text{(no picture card)}` `= 1-9/15`
    `= 6/15=2/5`

Filed Under: Probability, Single and Multi-Stage Events, Single and Multi-Stage Events Tagged With: Band 4, num-title-ct-core, num-title-qs-hsc, smc-1135-20-Other Multi-Stage Events, smc-1135-30-\(P(\text{E})=1-P(\text{not E})\), smc-4225-15-Single-stage events, smc-4225-20-Complementary events, smc-6887-50-Other Multi-stage Events

Probability, STD1 S2 2020 HSC 26

Barbara plays a game of chance, in which two unbiased six-sided dice are rolled. The score for the game is obtained by finding the difference between the two numbers rolled. For example, if Barbara rolls a 2 and a 5, the score is 3.

The table shows some of the scores.
 


 

  1. Complete the six missing values in the table to show all possible scores for the game.   (1 mark)
  2. What is the probability that the score for a game is NOT 0?   (2 marks)

    --- 3 WORK AREA LINES (style=lined) ---

Show Answers Only

 a.

b.    `frac{5}{6}`

Show Worked Solution

a.     

♦ Mean mark part (b) 47%.
b.      `Ptext{(not zero)}` `= frac{text(numbers) ≠ 0}{text(total numbers)}`
    `= frac{30}{36}= frac{5}{6}`

 
\(\text{Alternate solution (b)}\)

b.      `Ptext{(not zero)}` `= 1-Ptext{(zero)}`
    `= 1-frac{6}{36}`
    `= frac{5}{6}`

Filed Under: Probability, Single and Multi-Stage Events, Single and Multi-Stage Events Tagged With: Band 4, Band 5, num-title-ct-core, num-title-qs-hsc, smc-1135-20-Other Multi-Stage Events, smc-1135-40-Arrays, smc-4225-20-Complementary events, smc-4225-45-Multi-stage events, smc-6887-50-Other Multi-stage Events, smc-6887-80-Arrays

Probability, STD2 S2 2011 HSC 26a

The two spinners shown are used in a game.

2UG 2011 26a1

Each arrow is spun once. The score is the total of the two numbers shown by the arrows.
A table is drawn up to show all scores that can be obtained in this game.

2UG 2011 26a2

  1. What is the value of `X` in the table?   (1 mark)

    --- 1 WORK AREA LINES (style=lined) ---

  2. What is the probability of obtaining a score less than 4?   (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

  3. On Spinner `B`, a 2 is obtained. What is the probability of obtaining a score of 3?   (1 mark)

    --- 2 WORK AREA LINES (style=lined) ---

Show Answers Only

a.    `5`

b.    `1/2`

c.    `2/3`

Show Worked Solution

a.    `X=3+2=5`

b.    `P(text{score}<4)=6/12=1/2`

c.    `P(3)=2/3`

Filed Under: Multi-Stage Events, Single and Multi-Stage Events, Single and Multi-Stage Events, Single and Multi-Stage Events Tagged With: Band 3, Band 4, smc-1135-20-Other Multi-Stage Events, smc-1135-40-Arrays, smc-6887-50-Other Multi-stage Events, smc-6887-80-Arrays, smc-6935-25-Other Multi-Stage Events, smc-6935-50-Arrays, smc-829-20-Other Multi-Stage Events, smc-829-50-Arrays

Probability, STD2 S2 2006 HSC 10 MC

Kay randomly selected a marble from a bag of marbles, recorded its colour and returned it to the bag. She repeated this process a number of times.
  


  

Based on these results, what is the best estimate of the probability that Kay will choose a green marble on her next selection?

  1. `5/24`
  2. `1/24`
  3. `1/6`
  4. `1/5`
Show Answers Only

`C`

Show Worked Solution
`text{P(Green)}` `= text(# Green chosen) / text(Total Selections)`
  `= 4/24= 1/6`

`=>  C`

Filed Under: Multi-stage Events, Multi-Stage Events, Probability, Single and Multi-Stage Events, Single and Multi-Stage Events, Single and Multi-Stage Events Tagged With: Band 4, num-title-ct-core, num-title-qs-hsc, smc-1135-20-Other Multi-Stage Events, smc-4225-35-Relative frequency, smc-6887-50-Other Multi-stage Events, smc-6935-25-Other Multi-Stage Events, smc-829-20-Other Multi-Stage Events

Probability, STD2 S2 2004 HSC 18 MC

Two dice are rolled. What is the probability that only one of the dice shows a six?

  1. `5/36`
  2. `1/6`
  3. `5/18`
  4. `11/36`
Show Answers Only

`C`

Show Worked Solution

`text(Method 1: Using an array)`

`P text{(only 1 six)}=10/36=5/18`

\begin{align}
\textbf{Die B }
\begin{array}{c}
\textbf{Die A}  \\
\begin{array}{c|c|c|c|c|c|c}
\ & 1 & 2 & 3 & 4 & 5 & 6  \\
\hline
\ 1 & 1,1  & 1,2 & 1,3 & 1,4 & 1,5 & \fcolorbox{red}{white}{1,6} \\
\hline
\ 2 & 2,1 & 2,2 & 2,3 & 2,4 & 2,5 & \fcolorbox{red}{white}{2,6}  \\
\hline
\ 3 & 3,1 & 3,2 & 3,3 & 3,4 & 3,5 & \fcolorbox{red}{white}{3,6}  \\
\hline
\ 4 & 4,1 & 4,2 & 4,3 & 4,4 & 4,5 & \fcolorbox{red}{white}{4,6}  \\
\hline
\ 5 & 5,1 & 5,2 & 5,3 & 5,4 & 5,5 & \fcolorbox{red}{white}{5,6}  \\
\hline
\ 6 & \fcolorbox{red}{white}{6,1} & \fcolorbox{red}{white}{6,2} & \fcolorbox{red}{white}{6,3} & \fcolorbox{red}{white}{6,4} & \fcolorbox{red}{white}{6,5} & 6,6  \\
\end{array}
\end{array}
\end{align}

 

`text(Method 2:)`

`text{P (Only 1 six)}`

`= P text{(6, not 6)} + P text{(not 6, 6)}`

`= 1/6 xx 5/6 + 5/6 xx 1/6`

`= 10/36= 5/18`

`=>  C`

Filed Under: Multi-stage Events, Multi-Stage Events, Single and Multi-Stage Events, Single and Multi-Stage Events, Single and Multi-Stage Events Tagged With: Band 5, smc-1135-20-Other Multi-Stage Events, smc-6887-50-Other Multi-stage Events, smc-6935-25-Other Multi-Stage Events, smc-829-20-Other Multi-Stage Events

Probability, STD2 S2 2012 HSC 12 MC

Two unbiased dice, each with faces numbered 1, 2, 3, 4, 5, 6, are rolled. 

What is the probability of a 6 appearing on at least one of the dice? 

  1. `1/6`  
  2. `11/36` 
  3. `25/36`  
  4. `5/6`  
Show Answers Only

`B`

Show Worked Solution

`text(Method 1: Using an array`

`P text{(at least 1 six)}=11/36`

\begin{align}
\textbf{Die B }
\begin{array}{c}
\textbf{Die A}  \\
\begin{array}{c|c|c|c|c|c|c}
\ & 1 & 2 & 3 & 4 & 5 & 6  \\
\hline
\ 1 & 1,1  & 1,2 & 1,3 & 1,4 & 1,5 & \fcolorbox{red}{white}{1,6} \\
\hline
\ 2 & 2,1 & 2,2 & 2,3 & 2,4 & 2,5 & \fcolorbox{red}{white}{2,6}  \\
\hline
\ 3 & 3,1 & 3,2 & 3,3 & 3,4 & 3,5 & \fcolorbox{red}{white}{3,6}  \\
\hline
\ 4 & 4,1 & 4,2 & 4,3 & 4,4 & 4,5 & \fcolorbox{red}{white}{4,6}  \\
\hline
\ 5 & 5,1 & 5,2 & 5,3 & 5,4 & 5,5 & \fcolorbox{red}{white}{5,6}  \\
\hline
\ 6 & \fcolorbox{red}{white}{6,1} & \fcolorbox{red}{white}{6,2} & \fcolorbox{red}{white}{6,3} & \fcolorbox{red}{white}{6,4} & \fcolorbox{red}{white}{6,5} & \fcolorbox{red}{white}{6,6}  \\
\end{array}
\end{array}
\end{align}

 

`text(Method 2: Using )P text{(E)} = 1-P\text{(not E)}`
  

`P text{(at least 1 six)}`

`=1-P text{(no six)} xx P text{(no six)} `

`=1-5/6 xx 5/6=11/36`

`=>  B`

♦♦♦ Mean mark 25%
COMMENT: The term “at least” should flag that calculating the probability of `1-P text{(event not happening)}` is likely to be the most efficient way to solve.

Filed Under: Multi-stage Events, Multi-Stage Events, Single and Multi-Stage Events, Single and Multi-Stage Events, Single and Multi-Stage Events Tagged With: Band 5, num-title-ct-pathb, num-title-qs-hsc, smc-1135-20-Other Multi-Stage Events, smc-1135-30-\(P(\text{E})=1-P(\text{not E})\), smc-4238-70-Complementary events, smc-4238-80-"at least", smc-6887-50-Other Multi-stage Events, smc-6887-80-Arrays, smc-6935-25-Other Multi-Stage Events, smc-6935-30-\(P\text{(E)} = 1-P\text{(not E)}\), smc-829-20-Other Multi-Stage Events, smc-829-30-P(E) = 1 - P(not E)

Probability, STD2 S2 2013 HSC 18 MC

Two unbiased dice, each with faces numbered  1, 2, 3, 4, 5, 6,  are rolled.

What is the probability of obtaining a sum of 6?

  1. `1/6`
  2. `1/12`
  3. `5/12`
  4. `5/36`
Show Answers Only

`D`

Show Worked Solution

`text(Total outcomes)=6xx6=36`

`text{Outcomes that sum to 6}=text{(1,5) (5,1) (2,4) (4,2) (3,3)} =5`

`:.\ P\text{(sum of 6)} =5/36`

`=> D`

♦♦ Mean mark 35%.

Filed Under: Multi-stage Events, Multi-Stage Events, Multi-Stage Events, Single and Multi-Stage Events, Single and Multi-Stage Events, Single and Multi-Stage Events Tagged With: Band 5, num-title-ct-corea, num-title-qs-hsc, smc-1135-20-Other Multi-Stage Events, smc-4238-20-Independent events, smc-6887-50-Other Multi-stage Events, smc-6935-25-Other Multi-Stage Events, smc-829-20-Other Multi-Stage Events

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