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Measurement, STD2 EQ-Bank 30

A 2500-watt air-conditioning system is turned on for 3 hours each day. Electricity is charged at 27 cents per kWh.

What is the cost of electricity for using the air-conditioning system over a seven-day period?   (2 marks)

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`$14.18`

Show Worked Solution
`text{Daily usage}`  `=2500 xx 3`
  `= 7500\ text{Wh}`
  `=7.5\ text{kWh  (1000 Wh = 1 kWh)}`

 

`text{Cost}`  `= 7 xx 7.5 xx 0.27` 
  `= 14.175=$14.18\ \ text{(nearest cent)}`

♦♦ Mean mark 39%.

Filed Under: Rates Tagged With: Band 4, smc-6932-20-Energy

Measurement, STD2 M7 2025 HSC 21

A house has a reverse-cycle air conditioner which uses 2.5 kW of power for cooling and 3.2 kW of power for heating. The cost of electricity is 29 cents per kWh .

  1. Find the cost, in dollars and cents, of cooling the house for 6 hours.   (1 mark)

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  2. The cost of operating the air conditioner to heat the house during winter last year was $640. There are 92 days in winter.
  3. Find the number of hours, to 1 decimal place, that the air conditioner was used on average per day.   (2 marks)

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a.    \(\text{Cooling cost (6 hours )}\ = 6 \times 2.5 \times 0.29 = \$4.35\)

b.    \(7.5\ \text{hours}\)

Show Worked Solution

a.    \(\text{Cooling cost (6 hours )}\ = 6 \times 2.5 \times 0.29 = \$4.35\)
 

b.    \(\text{Let \(h\) = hours used per day}\)

\(\text{Cost per day}\ = h \times 3.2 \times 0.29\)

\(\text{Cost (92 days )}\ = 92 \times h \times 3.2 \times 0.29\)

\(\text{Find \(h\) when cost = \$640:}\)

\(640\) \(=92 \times h \times 3.2 \times 0.29\)  
\(h\) \(=\dfrac{640}{92 \times 3.2 \times 0.29}=7.5\ \text{hours (1 d.p.)}\)  

Filed Under: Energy and Mass, Rates, Rates Tagged With: Band 3, Band 4, smc-6932-20-Energy, smc-799-20-Electricity, smc-805-20-Energy

Measurement, STD2 M7 2025 HSC 10 MC

An electricity company charges customers 37 cents per kWh for electricity used, \( U\), and pays customers 5 cents per kWh for electricity produced, \(P\).

The electricity company also charges customers a fee of 71 cents per day.

Which formula should be used to calculate a customer's daily cost of electricity, \(C\), in cents?

  1. \( C=71+37 U-5 P \)
  2. \( C=71+37 U+5 P \)
  3. \( C=71-37 U-5 P \)
  4. \( C=71-37 U+5 P \)
Show Answers Only

\(A\)

Show Worked Solution

\(\text{Customer pays:}\ 71 + 37 \times U\)

\(\text{Customer receives:}\ 5 \times P\)

\(\text{Daily cost}\ = 71 + 37 \times U-5 \times P\)

\(\Rightarrow A\)

Filed Under: Rates, Rates Tagged With: Band 4, smc-6932-20-Energy, smc-805-20-Energy

Measurement, STD2 M7 2024 HSC 17

The cost of electricity is 30.13 cents per kWh .

Calculate the cost of using a 650 W air conditioner for 6 hours.   (2 marks)

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\(\text{Cost} =\$ 1.18\)

Show Worked Solution

\(\text{Usage}=6 \times 650=3900\, \text{Wh}=3.9\, \text{kWh}\)

\(\text{Cost} =3.9 \times 30.13=117.507 \,\text{c}=\$ 1.18 \, \text {(nearest cent)}\)

Filed Under: Energy and Mass, Rates, Rates Tagged With: Band 4, smc-6932-20-Energy, smc-799-20-Electricity, smc-805-20-Energy

Measurement, STD2 M7 2021 HSC 27

The price and the power consumption of two different brands of television are shown.

The average cost for electricity is 25c/kWh. A particular family watches an average of 3 hours of television per day.

  1. The annual cost of electricity for Television A for this family is $48.18.
  2. For this family, what is the difference in the annual cost of electricity between Television A and Television B?   (2 marks)

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  3. For this family, how many years will it take for the total cost of buying and using Television A to be equal to the cost of buying and using Television B?   (2 marks)

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a.    `$4.38`

b.    `5\ text(years)`

Show Worked Solution
a.     `text{Annual power usage (B)}` `= 160 xx 3 xx 365`
    `=175\ 200`
    `=175.2\ text(kWh)`

♦ Mean mark part (a) 49%.

`text{Annual cost (B)}= 175.2 xx 0.25=$43.80`

`text{Difference in cost}= 48.18-43.80=$4.38`
  

♦♦ Mean mark part (b) 23%.

b.    `text{Difference in price}= 921.90-900=$21.90`

`text(Years to even out cost)=21.90/4.38=5\ text{years}`

Filed Under: Energy and Mass, M4 Rates (Y12), Rates, Rates Tagged With: Band 4, Band 5, smc-1104-25-Energy, smc-6932-20-Energy, smc-799-20-Electricity, smc-805-20-Energy

Measurement, STD2 M7 EQ-Bank 28

Francis is buying a fridge. The energy usage of his two choices are below:

Fridge 1 (5 star rating): 227 kWh per year

Fridge 2 (2 star rating): 492 kWh per year

Each fridge has an expected life of 8 years.

If electricity costs 32.4 cents per kWh, how much will Francis save in electricity over the expected life of the more energy efficient fridge, to the nearest dollar?  (2 marks)

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`$687`

Show Worked Solution

`text(Energy cost of fridge 1)`

`= 227 xx 0.324 xx 8 = $588.38`

`text(Energy cost of fridge 2)`

`= 492 xx 0.324 xx 8 = $1275.26`

`:.\ text(Energy saving)= 1275.26-588.38= 686.88~~ $687`

Filed Under: Rates, Rates Tagged With: Band 4, smc-6932-20-Energy, smc-805-20-Energy

Measurement, STD2 M7 2018 HSC 28c

Every day, a 1200-watt microwave oven is used for 45 minutes at 40% power. Electricity is charged at $0.25 per kWh.

What is the cost of running this microwave oven for 180 days?   (3 marks)

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`$16.20`

Show Worked Solution

`text(Daily usage)= 1200 xx 45/60 xx 40text(%)= 360\ text(watts)`

 

`text(180 day usage)` `= 180 xx 360`
  `= 64\ 800\ text(watt hours)= 64.8\ text(kWh)`

  
`:.\ text(C)text(ost over 180 days)= 64.8 xx 0.25= $16.20`

Filed Under: Energy and Mass, M4 Rates (Y12), Rates, Rates Tagged With: Band 4, smc-1104-25-Energy, smc-6932-20-Energy, smc-799-20-Electricity, smc-805-20-Energy

Measurement, STD2 M7 EQ-Bank 32

Bikram runs a hot yoga studio.

If it costs 34 cents for 1-kilowatt (1000 watts) for 1 hour, how much does it cost him to run three 3200-watt heaters from 9:00 am to 12:30 pm on a single day? (Give your answer to the nearest cent)   (2 marks)

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`$11.42`

Show Worked Solution

`text(Total energy usage)`

`= 3 xx 3200 xx 3.5\ text(hours)= 33\ 600\ text(Wh)=33.6\ text(kWh)`

  `:.\ text(C)text(ost)= (33.6 xx 0.34= 11.424= $11.42\ \ text{(nearest cent)}`

Filed Under: Energy and Mass, M4 Rates (Y12), Rates, Rates, Rates Tagged With: Band 4, smc-1104-25-Energy, smc-6932-20-Energy, smc-799-20-Electricity, smc-805-20-Energy

Measurement, STD2 M1 2016 HSC 28b

The cost of buying a new heater is $990. It has an energy consumption of 505 kWh per year.

Energy is charged at the rate of $0.35 kWh.

How much will it cost in total to purchase and then run this heater for five years?   (2 marks)

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`$1873.75`

Show Worked Solution

`text(C)text(ost to run heater for 5 years)`

`= 5 xx 505 xx 0.35= $883.75`
 

`:.\ text(Total purchase and running cost)`

`= 883.75 + 990= $1873.75`

Filed Under: Energy and Mass, FS Resources, M4 Rates (Y12), Rates, Rates Tagged With: Band 3, smc-1104-25-Energy, smc-6932-20-Energy, smc-799-20-Electricity, smc-805-20-Energy

Measurement, STD2 M1 2015 HSC 30a

The energy consumption of a computer in standby mode is 21 watts. The cost of electricity is 31 cents per kWh.

A school computer room has 20 computers.

How much will the school save by switching off all 20 computers during 11 weeks of school holidays?   (2 marks)

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`$240.61`

Show Worked Solution

`text(21 watts usage per computer per hour.)`

♦ Mean mark 49%.

`text(Watts used by 20 computers in 11 weeks)`

`= 21 xx 20 xx 24 xx 7 xx 11`

`= 776\ 160\ text(Wh)= 776.16\ text(kWh)` 
  

`:.\ text(C)text(ost of energy)`

`= 776.16 xx $0.31`

`= $240.6096= $240.61\ \ text{(nearest cent)}`
  

`:.\ text(The school will save $240.61 by switching)`

`text(off all the computers.)`

Filed Under: Energy and Mass, FS Resources, M4 Rates (Y12), Rates Tagged With: Band 5, smc-1104-25-Energy, smc-6932-20-Energy, smc-799-20-Electricity

Measurement, STD2 M1 2014 HSC 20 MC

In a household of 4, each member uses an average of 13 minutes of hot water per day.

The household uses a 9 kW hot water unit.

Electricity is charged at 11.97 c/kWh when the hot water unit is being used.

What is the electricity cost for the hot water used by this household in one week?

  1. $1.63
  2. $6.54
  3. $392.14
  4. $653.56
Show Answers Only

`B`

Show Worked Solution

`text(Usage per day) = 4 xx 13 = 52\ text(mins)`

♦ Mean mark 39%.

`text(Usage per week) = 7 xx 52 = 364\ text(mins)`

`text(Converting to kWh)`

`= text{(hours of usage)} xx 9\ text(kW)`

`= 364/60 xx 9 = 54.6\ text(kWh)`
 

`:.\ text(C)text(ost)` `= 54.6 xx 11.97 text(c)`
  `~~ 654 text(c)=$6.54`

`=>  B`

Filed Under: Energy and Mass, FS Resources, M4 Rates (Y12), Rates Tagged With: Band 5, smc-1104-25-Energy, smc-6932-20-Energy, smc-799-20-Electricity

Measurement, STD2 M1 2013 HSC 26d

A section of Jim’s electricity bill is shown.

2013 26d

  1. What is the value of `A`?   (1 mark)

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  2. How much will Jim save if he uses 154 kWh of energy at the Off-peak rate rather than at the Peak rate?   (2 marks)

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a.    `1084.4`

b.    `$ 58.78\ \ \ (text(nearest cent) )`

Show Worked Solution
a.     `A` `=\ text(Last reading + Energy used)`
    `= 560.9 + 523.5= 1084.4`
♦ Mean mark
part (a) 43%
part (b) 46%.

 

b.     `text(C)text(ost at off-peak)` `= 154 xx 9.6`
    `= 1478.4\ text(cents)`

 

`text(C)text(ost at peak)` `=154 xx 47.77`
  `= 7356.58\ text(cents)`

 

`:.\ text(Saving)` `=7356.58-1478.4`
  `=5878.18= $58.78\ text{(nearest cent)}`

Filed Under: Energy and Mass, FS Resources, M4 Rates (Y12), Rates Tagged With: Band 5, smc-1104-25-Energy, smc-6932-20-Energy, smc-799-20-Electricity

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