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Statistics, STD2 S1 2018 HSC 1 MC

A set of scores has the following five-number summary.

lower extreme = 2
lower quartile = 5
median = 6
upper quartile = 8
upper extreme = 9

What is the range?

  1. 2
  2. 3
  3. 6
  4. 7
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`text(D)`

Show Worked Solution
`text(Range)` `=\ text(upper extreme − lower extreme)`
  `= 9 – 2`
  `= 7`

`=>\ text(D)`

Statistics, STD2 S1 2004 HSC 6-7 MC

Use the set of scores  1, 3, 3, 3, 4, 5, 7, 7, 12  to answer Questions 6 and 7.
 

Question 6

What is the range of the set of scores?

  1. 6
  2. 9
  3. 11
  4. 12

 

Question 7

What are the median and the mode of the set of scores?

  1. Median 3, mode 5
  2. Median 3, mode 3
  3. Median 4, mode 5
  4. Median 4, mode 3
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`text(Question 6:)\ C`

`text(Question 7:)\ D`

Show Worked Solution

`text(Question 6)`

`text(Range)` `= text(High) – text(Low)`
  `= 12 – 1`
  `= 11`

`=> C`

 

`text(Question 7)`

`text(9 scores)`

`:.\ text(Median)` `= (9 + 1) / 2`
  `=5 text(th score)`
  `= 4`

`text(Mode) = 3`

`=> D`

Statistics, STD2 S1 2007 HSC 21 MC

This set of data is arranged in order from smallest to largest.

 `5, \ 6, \ 11, \ x, \ 13, \ 18, \ 25`

The range is six less than twice the value of  `x`.

Which one of the following is true?

  1.    The median is 12 and the interquartile range is 7.
  2.    The median is 12 and the interquartile range is 12.
  3.    The median is 13 and the interquartile range is 7.
  4.    The median is 13 and the interquartile range is 12.
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`D`

Show Worked Solution

`5, 6, 11, x, 13, 18, 25`

`text(Range)` `= 2x – 6`
`25 – 5` `= 2x – 6`
`2x` `= 26`
`x` `= 13`
`:.\ text(Median)` `= 13`

 
`Q_1 = 6\ \ \ \ \ Q_3 = 18`

`:.\ text(IQR) = 12`

 
`=>  D`

Probability, STD2 S2 2008 HSC 26b

The retirement ages of two million people are displayed in a table.
 

 
 

  1. What is the relative frequency of the 51–55 year retirement age?  (1 mark)

  2. Describe the distribution.   (1 mark)

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  1. `7/400`
  2. `text(Distribution is negatively skewed because)`

     

    `text(as age increases, so does the number of)`

     

    `text(people in each age bracket.)`

Show Worked Solution

i.  `text(Relative frequency)\ (51-55)`

`= text{# People (51-55)}/text(Total People)`

`= (35\ 000)/(2\ 000\ 000)`

`= 7/400`

 

ii.  `text(Distribution is negatively skewed because)`

`text(as age increases, so does the number of)`

`text(people in each age bracket.)`

Statistics, STD2 S1 2013 HSC 26b

Write down a set of six data values that has a range of 12, a mode of 12 and a minimum value of 12.   (2 marks)

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 `12, 12, 12, 16, 18, 24`

Show Worked Solution

`12, 12, 12, 16, 18, 24`

`text(NB. There are many correct solutions.)`