SmarterEd

Aussie Maths & Science Teachers: Save your time with SmarterEd

  • Login
  • Get Help
  • About

v1 Measurement, STD2 M7 2018 HSC 27a

Alex used a cloud storage service for one month.

The plan has a base monthly cost of $25. The service also charges 45 cents per GB uploaded and 12 cents per GB downloaded.

During the month, Alex uploaded 180 GB and downloaded 350 GB.

What was the total bill for the month?   (2 marks)

--- 5 WORK AREA LINES (style=lined) ---

Show Answers Only

`$148.00`

Show Worked Solution

`text(Upload charge = 180 × 45c = $81.00)`

`text(Download charge = 350 × 12c = $42.00)`

`:.\ text(Total bill)` `= 25 + 81 + 42`
  `= $148.00`

Filed Under: Rates (Std2-X) Tagged With: Band 2, smc-1104-15-General rate problems, smc-805-60-Other rate problems

v1 Measurement, STD2 M7 2016 HSC 15 MC

Parking in a city car park is charged at the rate of $3.40 per 20 minutes, or part thereof.

What is the cost of parking for 1 hour and 8 minutes?

  1. $10.20
  2. $13.60
  3. $17.00
  4. $20.40
Show Answers Only

`=> B`

Show Worked Solution

`68 -: 20 = 3.4 \ \Rightarrow\ 4\ \text{blocks}`

♦ Mean mark 48%.
`:.\ \text(Cost)` `= 4 xx 3.40`
  `= $13.60`

`=> B`

Filed Under: Rates (Std2-X) Tagged With: Band 5, smc-1104-15-General rate problems, smc-805-60-Other rate problems

v1 Measurement, STD2 M7 SM-Bank 15 MC

A brand of cereal is sold in two different boxes.

What is the difference in the price per kilogram of these two boxes?

  1. $0.80
  2. $1.20
  3. $1.50
  4. $2.40
Show Answers Only

`B`

Show Worked Solution

`text(Convert to price per kg:)`

`text(Box 1)`

`400\ text(g) = $3.60`

`1\ text(kg) = 3.60\ xx\ 2.5 = $9.00`

 

`text(Box 2)`

`1.5\ text(kg) = $15.30`

`1\ text(kg) = 15.30\ -:\ 1.5 = $10.20`

 

`:.\ \text(Difference per kg)`

`= 10.20 – 9.00`

`= $1.20`
 

`=> B`

Filed Under: Rates (Std2-X) Tagged With: Band 4, smc-1104-50-Best Buys, smc-805-50-Best Buys

v1 Measurement, STD2 M7 2023 HSC 5 MC

Four mobile data packs are shown, each with the data included and its cost.

Which one represents the best value?

Show Answers Only

`C`

Show Worked Solution

`text{Calculate cost per GB of each option}`

`text{Option}\ A:\ $22.50 -: 10= $2.25\ text{per GB}`

`text{Option}\ B:\ $25.60 -: 12= $2.133\ldots\ \text{per GB}`

`text{Option}\ C:\ $27.30 -: 14= $1.95\ \text{per GB}`

`text{Option}\ D:\ $30.00 -: 15= $2.00\ \text{per GB}`

`=>C`

Filed Under: Rates (Std2-X) Tagged With: Band 4, smc-805-50-Best Buys

v1 Algebra, STD2 A2 2014 HSC 22 MC

Maya’s hybrid uses fuel at the rate of 7.4 L per 100 km for highway driving and 10.2 L per 100 km for urban driving.

She drove a total of 720 km, of which 120 km were urban driving.

Approximately how much fuel did Maya’s car use on the journey?

  1. 55 L
  2. 57 L
  3. 60 L
  4. 65 L
Show Answers Only

`B`

Show Worked Solution

`text(Fuel used in urban driving)`

`= 120/100 xx 10.2\ text(L) = 12.24\ text(L)`

`text(Fuel used on highway)`

`= 600/100 xx 7.4\ text(L) = 44.4\ text(L)`

`:.\ text(Total Fuel)` `= 12.24 + 44.4`
  `= 56.64\ text(L) ~~ \approx 57\ text(L)`

`=> B`

Filed Under: Rates (Std2-X) Tagged With: Band 4, smc-1104-20-Fuel, smc-1119-20-Fuel, smc-793-20-Fuel, smc-805-10-Fuel

v1 Measurement, STD2 M7 2016 HSC 11 MC

The concentration of an iron supplement is 250 mg / 5 mL. A patient is prescribed 1500 mg of the supplement.

How much medication should be given to the patient?

  1. 12.5 mL
  2. 20 mL
  3. 30 mL
  4. 300 mL
Show Answers Only

`C`

Show Worked Solution

`text(Volume required)`

`= 1500/250 xx 5`

`= 30\ text(mL)`

`=> C`

Filed Under: Rates (Std2-X) Tagged With: Band 3, smc-1104-30-Medication, smc-805-30-Medication

v1 Measurement, STD2 M7 2014 HSC 17 MC

A child who weighs 22 kg needs to be given 12 mg of medicine for every 2 kg of body weight. 

Every 10 mL of this medicine contains 150 mg. 

What is the correct dosage for the child? 

  1. 7.0 mL 
  2. 8.8 mL 
  3. 10.2 mL 
  4. 11.5 mL 
Show Answers Only

\(B\)

Show Worked Solution

\(\text{Dosage needed}\ = \dfrac{22}{2} \times 12 = 132\ \text{mg}\) 

\(\text{Since there is 150 mg in 10 mL:} \) 

\(\text{Volume (132 mg)}\ =\dfrac{132}{150} \times 10 = 8.8\ \text{mL}\) 

\(\Rightarrow B\)

Filed Under: Rates (Std2-X) Tagged With: Band 4, smc-1104-15-General rate problems, smc-805-60-Other rate problems

v1 Measurement, STD2 M7 2019 HSC 2 MC

Rice is sold in four different sized packets. Which is the best buy?

  1. 250 g for $1.10 
  2. 500 g for $2.00 
  3. 1 kg for $3.80 
  4. 2 kg for $7.40 
Show Answers Only

`D`

Show Worked Solution

\(\text{Price per kilogram}\)

\(\text{250 g:}\  1.10 \times 4 = $4.40 \)

\(\text{500 g:}\ 2.00 \times 2 = $4.00 \)

\(\text{1 kg:}\ $3.80 \)

\(\text{2 kg:}\ 7.40\ ÷\ 2 = $3.70 \)

\(\text{Best buy is 2 kg at \$3.70/kg.}\) 

\(\Rightarrow D\) 

Filed Under: Rates (Std2-X) Tagged With: Band 3, smc-805-50-Best Buys

v2 Measurement, STD2 M7 2016 HSC 9 MC

An old air conditioner uses 2.8 kW of electricity per hour. A new air conditioner uses 1.2 kW per hour. How much electricity is saved each year if the air conditioner runs for 5 hours per day for 200 days using the new model?

  1. 1200 kWh
  2. 1600 kWh
  3. 2400 kWh
  4. 2800 kWh
Show Answers Only

\(B\)

Show Worked Solution

\(\text{Electricity used by old air conditioner}\ = 2.8 \times 5 \times 200 = 2800\ \text{kWh}\)

\(\text{Electricity used by new air conditioner}\ = 1.2 \times 5 \times 200 = 1200\ \text{kWh}\)

\(\therefore\ \text{Electricity saved} = 2800-1200 = 1600\ \text{kWh}\)

\(\Rightarrow B\)

Filed Under: Rates (Std2-X) Tagged With: Band 3, smc-1104-15-General rate problems, smc-805-60-Other rate problems

v1 Measurement, STD2 M7 2016 HSC 9 MC

An old dishwasher uses 45 L of water per cycle. A new dishwasher uses 15 L per cycle. How much water is saved each year if three cycles are run each week using the new dishwasher?

  1. 2340 L
  2. 3640 L
  3. 4680 L
  4. 7020 L
Show Answers Only

\(C\)

Show Worked Solution

\(\text{Water used by old dishwasher}\ = 45 \times 3 \times 52 = 7020\ \text{L}\)

\(\text{Water used by new dishwasher}\ = 15 \times 3 \times 52 = 2340\ \text{L}\)

\(\text{Water saved}\ = 7020-2340 = 4680\ \text{L}\)

\(\Rightarrow C\)

Filed Under: Rates (Std2-X) Tagged With: Band 3, smc-1104-15-General rate problems, smc-805-60-Other rate problems

Copyright © 2014–2026 SmarterEd.com.au · Log in