Given the formula `C = (A(y + 1))/24`, calculate the value of `y` when `C = 120` and `A = 500`. (3 marks)
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Aussie Maths & Science Teachers: Save your time with SmarterEd
Given the formula `C = (A(y + 1))/24`, calculate the value of `y` when `C = 120` and `A = 500`. (3 marks)
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`4.76`
`text(Make)\ \ y\ \ text(the subject:)`
`C` | `= (A(y + 1))/24` |
`24C` | `= A(y + 1)` |
`y + 1` | `= (24C)/A` |
`y` | `= (24C)/A-1` |
`= (24 xx 120)/500-1` | |
`= 4.76` |
Mr Ralph has a History class that has completed two separate exams during the term.
The results of each exam are summarised in the histograms below.
Without using calculations, explain which test will have the highest standard deviation. (2 marks)
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\(\text{By inspection, Test B has a higher range than Test A.}\)
\(\text{Test A results look to have a tighter spread of data points}\)
\(\text{about its expected mean, when compared to Test B.}\)
\(\text{Test B will therefore have a higher standard deviation.}\)
\(\text{By inspection, Test B has a higher range than Test A.}\)
\(\text{Test A results look to have a tighter spread of data points}\)
\(\text{about its expected mean, when compared to Test B.}\)
\(\text{Test B will therefore have a higher standard deviation.}\)
Dataset 1 has mean \(\bar x_1\) and standard deviation \(\sigma_1\).
Dataset 2 has mean \(\bar x_2\) and standard deviation \(\sigma_2\).
Consider the following statement: If \(\bar x_1 < \bar x_2\), then \(\sigma_1 < \sigma_2\).
Is this statement correct? Explain your answer. (2 marks)
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\(\text{Standard deviation is a measure of how much members}\)
\(\text{of a data group differ from the mean value of the group.}\)
\(\text{It follows that the relative standard deviation between two}\)
\(\text{datasets is not affected if}\ \ \bar x_1 < \bar x_2\).
\(\text{Therefore, the statement is incorrect.}\)
\(\text{Standard deviation is a measure of how much members}\)
\(\text{of a data group differ from the mean value of the group.}\)
\(\text{It follows that the relative standard deviation between two}\)
\(\text{datasets is not affected if}\ \ \bar x_1 < \bar x_2\).
\(\text{Therefore, the statement is incorrect.}\)
Determine the standard deviation of the following dataset, giving your answer correct to one decimal place. (1 mark)
\(13, \ 14, \ 18, \ 18, \ 23, \ 27, \ 31\)
\(\text{Std Dev}\ = 6.2\)
\(\text{By calculator (using Statistics mode):} \)
\(\text{Std Dev}\ = 6.207… = 6.2\ \text{(1 d.p.)} \)
Rhonda and her friends were surveyed about the number of concerts they have been to in the last 12 months.
Their responses are as follows:
\(3, \ 4, \ 8, \ 10, \ 12, \ 13\)
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i. \(\text{Median}\ = 9\)
ii. \(\text{Std Dev}\ = 3.8\)
i. \(3, \ 4, \ 8, \ 10, \ 12, \ 13\)
\(\text{6 data points}\)
\(\text{Median}\ = \dfrac{\text{3rd + 4th}}{2} = \dfrac{8+10}{2} = 9 \)
ii. \(\text{By calculator (using Statistics mode):} \)
\(\text{Std Dev}\ = 3.771… = 3.8\ \text{(1 d.p.)} \)
Albert teaches Physics and sets his class a mid-term exam.
The results are summarised in the Stem and Leaf plot drawn below.
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i. \(\text{Median}\ = 83\)
ii. \(\text{Std Dev}\ = 12.14\)
i. \(\text{Dataset values:}\ 62, 65, 78, 79, 83, 89, 94, 96, 97 \)
\(\text{9 data points}\ \ \Rightarrow\ \ \text{Median = 5th value} \)
\(\text{Median}\ = 83\)
ii. \(\text{By calculator (using Statistics mode):} \)
\(\text{Std Dev}\ = 12.139… = 12.14\ \text{(2 d.p.)} \)
Seven 40-year old males are asked how many children they have in a survey.
The results are summarised in the histogram drawn below.
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i. \(\text{Mean}\ = 2.57\)
ii. \(\text{Std Dev}\ = 1.05\)
i. \(\text{Dataset values:}\ 1, 2, 2, 2, 3, 4, 4 \)
\(\text{Mean}\ = \dfrac{1+2+2+2+3+4+4}{7} = \dfrac{18}{7} = 2.571… = 2.57\ \text{(2 d.p.)} \)
ii. \(\text{By calculator (using Statistics mode):} \)
\(\text{Std Dev}\ = 1.049… = 1.05\ \text{(2 d.p.)} \)
A dataset is represented by the dot plot drawn below.
Determine the standard deviation of the dataset, giving your answer correct to two decimal places. (2 marks)
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\(\text{Std Dev}\ = 1.25\)
\(\text{Dataset values:}\ 0, 1, 1, 2, 2, 3, 4 \)
\(\text{By calculator (using Statistics mode):}\)
\(\text{Std Dev}\ = 1.245… = 1.25\ \text{(2 d.p.)} \)
Isa Guha recorded the number of sixes hit in the first nine games of the Women's Big Bash Cricket League over two seasons.
The results are recorded in the two dot plots below.
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i. \(\text{Std Dev}\ = 1.9\ \text{(1 d.p.)} \)
ii. \(\text{By inspection, season 1 has a slightly higher range}\)
\(\text{(5 vs 4) and its data points can be seen to be much}\)
\(\text{wider spread about the expected mean value.}\)
\(\text{Season 1 will therefore have a higher standard deviation.}\)
i. \(\text{Season 1 dataset:}\ 6, 6, 7, 8, 10, 10, 10, 11, 11\)
\(\text{By calculator (using Statistics mode):}\)
\(\text{Std Dev}\ = 1.930… = 1.9\ \text{(1 d.p.)} \)
ii. \(\text{By inspection, season 1 has a slightly higher range}\)
\(\text{(5 vs 4) and its data points can be seen to be much}\)
\(\text{wider spread about the expected mean value.}\)
\(\text{Season 1 will therefore have a higher standard deviation.}\)
In a cricket test match, a scorebook recorded the number of runs scored by England's top six batsman.
The scores are summarised in the Stem and Leaf plot below.
Determine the standard deviation of the scores, giving your answer correct to one decimal place. (2 marks)
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\(\text{Std Dev}\ = 6.6\)
\(\text{Runs scored dataset:}\ 8, 12, 15, 21, 23, 27 \)
\(\text{By calculator (using Statistics mode):}\)
\(\text{Std Dev}\ = 6.574… = 6.6\ \text{(1 d.p.)} \)
Ms Arnott has seven students in her Ethics class. The results of the most recent exam, completed by the whole class, is summarised in the Stem and Leaf plot below.
Determine the standard deviation of the exam results, giving your answer correct to one decimal place. (2 marks)
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\(\text{Std Dev}\ = 8.8\)
\(\text{Exam result dataset:}\ 56, 63, 69, 72, 77, 78, 84 \)
\(\text{By calculator (using Statistics mode):}\)
\(\text{Std Dev}\ = 8.84… = 8.8\ \text{(1 d.p.)} \)
Seven players in two basketball teams, the Swifties and the Chiefs, recorded how many 3-point baskets they had shot in the last season.
The results are recorded in the two Stem and Leaf plots below.
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i. \(\text{Std Dev}\ = 13.4 \)
ii. \(\text{The results of the Chiefs have a much smaller range (18 vs 38)}\)
\(\text{and are a much tighter fit around the expected mean.}\)
\(\text{The Chiefs’ results will therefore have a smaller standard deviation.}\)
i. \(\text{Swifties’ dataset:}\ 1, 2, 17, 22, 26, 33, 39 \)
\(\text{By calculator (using Statistics mode):}\)
\(\text{Std Dev}\ = 13.43… = 13.4\ \text{(1 d.p.)} \)
ii. \(\text{The results of the Chiefs have a much smaller range (18 vs 38)}\)
\(\text{and are a much tighter fit around the expected mean.}\)
\(\text{The Chiefs’ results will therefore have a smaller standard deviation.}\)
9 students completed two quizzes and the results were summarised in the dot plot diagrams below.
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i. \(\text{Median}\ = 7\)
ii. \(\text{Std Dev (Quiz A)}\ = 1.3 \)
\(\text{Std Dev (Quiz B)}\ = 0.8\)
i. \(\text{9 data points}\ \ \Rightarrow \ \ \text{Median = 5th data point}\)
\(\text{Median}\ = 7 \)
ii. \(\text{By calculator (using Statistics mode):}\)
\(\text{Quiz A dataset:}\ 5, 5, 6, 7, 7, 8, 8, 8, 9 \)
\(\text{Std Dev (Quiz A)}\ = 1.33… = 1.3\ \text{(1 d.p.)} \)
\(\text{Quiz B dataset:}\ 6, 6, 7, 7, 7, 8, 8, 8, 8 \)
\(\text{Std Dev (Quiz B)}\ = 0.78… = 0.8\ \text{(1 d.p.)} \)
Two data sets are represented in the dot plot diagrams below.
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i. \(\text{Std Dev}\ = 1.79… = 1.8\ \text{(1 d.p.)} \)
ii. \(\text{By inspection, Data Set A has a smaller range and a tighter}\)
\(\text{spread against its expected mean value.}\)
\(\text{Data Set B will therefore have a higher standard deviation.}\)
i. \(\text{Data points:}\ 4, 4, 5, 5, 6, 6, 7, 8, 9, 9\)
\(\text{By calculator (using Statistics mode):} \)
\(\text{Std Dev}\ = 1.79... = 1.8\ \text{(1 d.p.)} \)
ii. \(\text{By inspection, Data Set A has a smaller range and a tighter}\)
\(\text{spread against its expected mean value.}\)
\(\text{Data Set B will therefore have a higher standard deviation.}\)
In a small business, the seven employees earn the following wages per week:
\(\$300, \ \$490, \ \$520, \ \$590, \ \$660, \ \$680, \ \$970\)
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Explain the effect that this increase will this have on the standard deviation? (2 marks)
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i. \(191.0\)
ii. \(\text{All values increase by \$20, but so too does the mean.} \)
\(\text{Therefore the spread about the new mean will not change} \)
\(\text{and therefore the standard deviation will remain the same.} \)
i. \(\text{By calculator (in Statistics mode:}\)
\(\text{Std Dev}\ = 191.044... =191.0\ \text{(1 d.p.)} \)
ii. \(\text{All values increase by \$20, but so too does the mean.} \)
\(\text{Therefore the spread about the new mean will not change} \)
\(\text{and therefore the standard deviation will remain the same.} \)
Ali’s class sits a Geography test and the results are recorded below.
\(58,\ \ 74,\ \ 65,\ \ 66,\ \ 73,\ \ 71,\ \ 72,\ \ 74,\ \ 62,\ \ 70\)
The mean for the test was 68.5.
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i. \(5.2\ \ \text{(to 1 d.p.)} \)
ii. \(\text{Median}\ = \dfrac{70+71}{2} = 70.5 \)
\(\Rightarrow\ \text{Median > Mean (70.5 > 68.5)} \)
i. \(\text{By calculator (in Statistics mode):}\)
\(\text{Std Dev}\ = 5.220… = 5.2\ \text{(1 d.p.)} \)
ii. \(\text{Reorder test results in ascending order:}\)
\(58,\ \ 62,\ \ 65,\ \ 66,\ \ 70, \ \ 71,\ \ 72,\ \ 73,\ \ 74,\ \ 74\)
\(\text{Median}\ = \dfrac{70+71}{2} = 70.5 \)
\(\Rightarrow\ \text{Median > Mean (70.5 > 68.5)} \)
The ages of nine students were recorded in the table below.
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i. \(\text{By calculator (in Statistics mode):} \)
\(\text{Std Dev}\ = 1.5947… = 1.59\ \ \text{(to 2 d.p.)} \)
ii. \(\text{Standard deviation is a measure of how much members}\)
\(\text{of a data group differ from the mean value of the group.}\)
i. \(\text{By calculator (in Statistics mode):} \)
\(\text{Std Dev}\ = 1.5947… = 1.59\ \ \text{(to 2 d.p.)} \)
ii. \(\text{Standard deviation is a measure of how much members}\)
\(\text{of a data group differ from the mean value of the group.}\)
Ellyse recorded the number of wickets she took in the first seven games of the cricket season, which are as follows:
\(3, \ 5, \ 0, \ 8, \ 1, \ 2, \ 2 \)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} \rule[-1ex]{0pt}{0pt} & & & & \\
\hline
\end{array}
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i. \(\text{Ordering the data:}\ 0, \ 1, \ 2, \ 2, \ 3, \ 5, \ 8\)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 0 \rule[-1ex]{0pt}{0pt} & 1 & 2 & 5 & 8 \\
\hline
\end{array}
ii.
iii. \(\text{Positively skewed}\)
i. \(\text{Ordering the data:}\ 0, \ 1, \ 2, \ 2, \ 3, \ 5, \ 8\)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 0 \rule[-1ex]{0pt}{0pt} & 1 & 2 & 5 & 8 \\
\hline
\end{array}
ii.
iii. \(\text{Positively skewed}\)
Eli sat 22 Maths quizzes throughout year 8 and her results were recorded in the 5-number summary below.
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 30 \rule[-1ex]{0pt}{0pt} & 50 & 60 & 70 & 80 \\
\hline
\end{array}
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i.
ii. \(\text{Negatively skewed (slightly)}\)
i.
ii. \(\text{Negatively skewed (slightly)}\)
The test results in English and Mathematics for a class were recorded and displayed in the box plots.
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i. `text{IQR}_text{(English)}\ = 80-50=30`
ii. `text(Skewness)`
`text(Location and Spread)`
i. `text{IQR}_text{(English)}\ = 80-50=30`
ii. `text(Skewness)`
`text(Location and Spread)`
Terry and Kim each sat twenty class tests. Terry’s results on the tests are displayed in the box plot shown in part (i).
Draw a box plot to display Kim’s results below that of Terry’s results. (1 mark)
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i. |
ii. `text(50%)`
iii. `text{By inspection of box plot: Evenly skewed}`
This box plot represents a set of scores.
What is the interquartile range of this set of scores?
`C`
`text{Q}_1 = 8, \ text{Q}_3 = 11`
`text{IQR}` | `= text{Q}_3-text{Q}_1` |
`= 11-8` | |
`= 3` |
`=> C`
Using a 5-number summary of the data represented in this graph, or otherwise, determine
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i. \(\text{Range}\ = 7 \)
ii. \(\text{IQR}\ = \text{Q}_3-\text{Q}_1 = 6-1=5 \)
i. \(\text{Range}\ = 7-0=7 \)
ii.
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 0 \rule[-1ex]{0pt}{0pt} & 1 & 4 & 6 & 7 \\
\hline
\end{array}
\(\text{IQR}\ = \text{Q}_3-\text{Q}_1 = 6-1=5 \)
Using a 5-number summary of the data represented in this graph, or otherwise, determine
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i. \(\text{Median}\ = 2 \)
ii. \(\text{IQR}\ = \text{Q}_3-\text{Q}_1 = 5-1=4 \)
i. \(\text{15 data points}\ \Rightarrow \ \text{Median = 8th data point}\)
\(\text{Median}\ = 2 \)
ii.
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 0 \rule[-1ex]{0pt}{0pt} & 1 & 2 & 5 & 7 \\
\hline
\end{array}
\(\text{IQR}\ = \text{Q}_3-\text{Q}_1 = 5-1=4 \)
Yoyo was practicing his cello for an orchestra audition and the data set below records the number of hours he practiced each day over a 10-day period.
\(7.6, \ 12.2, \ 8.4, \ 7.8, \ 8.8, \ 9.3, \ 11.9, \ 7.0, \ 8.2, \ 10.4\)
Using a 5-number summary of this dataset, or otherwise, determine
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i. \(\text{Range}\ = 12.2-7.0 = 5.2 \)
ii. \(\text{IQR}\ = \text{Q}_3-\text{Q}_1 = 10.4-7.8=2.6 \)
i. \(\text{Placing data values in order:}\)
\(7.0, \ 7.6, \ 7.8, \ 8.2, \ 8.4, \ 8.8, \ 9.3, \ 10.4, \ 11.9, \ 12.2\)
\(\text{Range}\ = 12.2-7.0 = 5.2 \)
ii. \(\underbrace{7.0}_{\text{min}}, \ 7.7, \ \underbrace{7.8}_{Q1}, \ 8.2, \ \underbrace{8.4, \ 8.8}_{Q2}, \ 9.3, \ \underbrace{10.4}_{Q3}, \ 11.9, \ \underbrace{12.2}_{\text{max}}\)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 7.0 \rule[-1ex]{0pt}{0pt} & 7.8 & 8.6 & 10.4 & 12.2 \\
\hline
\end{array}
\(\text{IQR}\ = \text{Q}_3-\text{Q}_1 = 10.4-7.8=2.6 \)
Matt records the number of times he takes his dog Max for a walk each month. The data set below records the months January to August.
\(21, \ 24, \ 28, \ 22, \ 15, \ 12, \ 13, \ 17\)
Using a 5-number summary of this dataset, or otherwise, determine
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i. \(\text{Median}\ = \dfrac{17+21}{2} = 19 \)
ii. \(\text{IQR}\ = \text{Q}_3-\text{Q}_1 = 23-14=9 \)
i. \(\text{Placing data values in order:}\)
\(12, \ 13, \ 15, \ 17, \ 21, \ 22, \ 24, \ 28 \)
\(\text{Median}\ = \dfrac{17+21}{2} = 19 \)
ii. \(\underbrace{12}_{\text{min}}, \underbrace{13+15}_{Q1}, \ \underbrace{17+21}_{Q2}, \ \underbrace{22, \ 24}_{Q3}, \ \underbrace{28}_{\text{max}}\)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 12 \rule[-1ex]{0pt}{0pt} & 14 & 19 & 23 & 28 \\
\hline
\end{array}
\(\text{IQR}\ = \text{Q}_3-\text{Q}_1 = 23-14=9 \)
The data set below consists of 8 data points.
\(7.0, \ 7.4, \ 8.1, \ 9.3, \ 9.5, \ 10.7, \ 11.1, \ 12.9 \)
Complete the 5-number summary table of the data set below. (2 marks)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} & \ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} \rule[-1ex]{0pt}{0pt} & \\
\hline
\end{array}
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 7.0 \rule[-1ex]{0pt}{0pt} & 7.75 & 9.4 & 10.9 & 12.9 \\
\hline
\end{array}
\(\underbrace{7.0}_{\text{min}}, \underbrace{7.4,\ 8.1}_{Q1}, \ \underbrace{9.3, \ 9.5}_{Q2}, \ \underbrace{10.7, \ 11.1}_{Q3}, \ \underbrace{12.9}_{\text{max}}\)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 7.0 \rule[-1ex]{0pt}{0pt} & 7.75 & 9.4 & 10.9 & 12.9 \\
\hline
\end{array}
Rocket Reddy played 10 full seasons of first grade rugby league and recorded the number of tries he scored each season.
\(13, \ 5, \ 11, \ 2, \ 10, \ 13, \ 5, \ 7, \ 8, \ 3\)
Complete the 5-number summary table of Rocket Reddy's data below. (2 marks)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} & \ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} \rule[-1ex]{0pt}{0pt} & \\
\hline
\end{array}
\(\underbrace{2}_{\text{min}}, \ 3, \underbrace{5}_{Q1}, \ 5, \ \underbrace{7, \ 8}_{Q2}, \ 10, \ \underbrace{11}_{Q3}, \ 13, \ \underbrace{13}_{\text{max}}\)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 2 \rule[-1ex]{0pt}{0pt} & 5 & 7.5 & 11 & 13 \\
\hline
\end{array}
\(\text{Place data points in order:}\)
\(2, \ 3, \ 5, \ 5, \ 7, \ 8, \ 10, \ 11, \ 13, \ 13\)
\(\underbrace{2}_{\text{min}}, \ 3, \underbrace{5}_{Q1}, \ 5, \ \underbrace{7, \ 8}_{Q2}, \ 10, \ \underbrace{11}_{Q3}, \ 13, \ \underbrace{13}_{\text{max}}\)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 2 \rule[-1ex]{0pt}{0pt} & 5 & 7.5 & 11 & 13 \\
\hline
\end{array}
Le Bron plays basketball and records the number of free throws he shoots in the first nine games of the season.
\(12, \ 8, \ 4, \ 15, \ 13, \ 7, \ 8, \ 3, \ 10\)
Using a 5-number summary of this dataset, or otherwise, determine
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i. \(\text{Median}\ = 8\)
ii. \(\text{IQR}\ = \text{Q}_3-\text{Q}_1 = 5-2 =3\)
i. \(\text{Ordering the data values:}\)
\(3, \ 4, \ 7, \ 8, \ 8, \ 10, \ 12, \ 13, \ 15\)
\(\text{Median}\ = 8\)
ii. \(\underbrace{3}_{\text{min}}, \ \underbrace{4, \ 7}_{Q1}, \ 8, \ \underbrace{8}_{Q2}, \ 10, \ \underbrace{12, \ 13}_{Q3}, \ \underbrace{15}_{\text{max}}\)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 3 \rule[-1ex]{0pt}{0pt} & 5.5 & 8 & 12.5 & 15 \\
\hline
\end{array}
\(\text{IQR}\ = \text{Q}_3-\text{Q}_1 = 12.5-5.5 =7\)
Robert records the total goals scored in each of the first 11 matches of his favourite soccer team.
\(3, \ 5, \ 1, \ 2, \ 2, \ 7, \ 6, \ 4, \ 1, \ 5, \ 3\)
Using a 5-number summary of this dataset, or otherwise, determine
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i. \(\text{Range}\ = 7-1=6\)
ii. \(\text{IQR}\ = \text{Q}_3-\text{Q}_1 = 5-2 =3\)
i. \(\text{Ordering the data values:}\)
\(1, \ 1, \ 2, \ 2, \ 3, \ 3, \ 4, \ 5, \ 5, \ 6, \ 7\)
\(\text{Range}\ = 7-1=6\)
ii. \(\underbrace{1}_{\text{min}}, 1, \ \underbrace{2}_{Q1}, \ 2, \ 3, \ \underbrace{3}_{Q2}, \ 4, \ 5, \ \underbrace{5}_{Q3}, \ 6, \ \underbrace{7}_{\text{max}}\)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 1 \rule[-1ex]{0pt}{0pt} & 2 & 3 & 5 & 7 \\
\hline
\end{array}
\(\text{IQR}\ = \text{Q}_3-\text{Q}_1 = 5-2 =3\)
The numerical data set below is made up of 9 data points.
\(1.1, \ 1.3, \ 1.3, \ 1.3, \ 1.6, \ 1.7, \ 1.9, \ 2.1, \ 2.1\)
Complete 5-number summary table below. (2 marks)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} & \ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} \rule[-1ex]{0pt}{0pt} & \\
\hline
\end{array}
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 1.1 \rule[-1ex]{0pt}{0pt} & 1.3 & 1.6 & 2.0 & 2.1 \\
\hline
\end{array}
\(\underbrace{1.1}_{\text{min}}, \ \underbrace{1.3, \ 1.3}_{Q1}, \ 1.3, \ \underbrace{1.6}_{Q2}, \ 13, \ \underbrace{1.9, \ 2.1}_{Q3}, \ \underbrace{2.1}_{\text{max}}\)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 1.1 \rule[-1ex]{0pt}{0pt} & 1.3 & 1.6 & 2.0 & 2.1 \\
\hline
\end{array}
The numerical data set below is made up of 7 data points.
\(5, \ 7, \ 7, \ 10, \ 13, \ 15, \ 19\)
Complete 5-number summary table below. (2 marks)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} & \ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} \rule[-1ex]{0pt}{0pt} & \\
\hline
\end{array}
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 5 \rule[-1ex]{0pt}{0pt} & 7 & 10 & 15 & 19 \\
\hline
\end{array}
\(\underbrace{5}_{\text{min}}, \ \underbrace{7}_{Q1}, \ 7, \ \underbrace{10}_{Q2}, \ 13, \ \underbrace{15}_{Q3}, \ \underbrace{19}_{\text{max}}\)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 5 \rule[-1ex]{0pt}{0pt} & 7 & 10 & 15 & 19 \\
\hline
\end{array}
The numerical data set below is made up of 11 data points.
\(2, \ 3, \ 3, \ 5, \ 8, \ 10, \ 11, \ 11, \ 12, \ 14, \ 16\)
Complete 5-number summary table below. (2 marks)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} & \ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} \rule[-1ex]{0pt}{0pt} & \\
\hline
\end{array}
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 2 \rule[-1ex]{0pt}{0pt} & 3 & 10 & 12 & 16 \\
\hline
\end{array}
\(\underbrace{2}_{\text{min}}, \ 3, \ \underbrace{3}_{Q1}, \ 5, \ 8, \ \underbrace{10}_{Q2}, \ 11, \ 11, \ \underbrace{12}_{Q3}, \ 14, \ \underbrace{16}_{\text{max}}\)
\begin{array} {|c|c|c|c|c|}
\hline
\rule{0pt}{2.5ex} \ \text{Min} \ \rule[-1ex]{0pt}{0pt} &\ \ \text{Q}_1 \ \ \ &\ \ \text{Q}_2 \ \ \ &\ \ \text{Q}_3 \ \ \ & \ \text{Max} \ \\
\hline
\rule{0pt}{2.5ex} 2 \rule[-1ex]{0pt}{0pt} & 3 & 10 & 12 & 16 \\
\hline
\end{array}
Jevin has a bank account that pays him simple interest.
The bank statement below shows the transactions on Jevin’s account for the month of July.
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Interest for this account is calculated on the minimum monthly balance at a rate of 3.0% per annum.
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a. | `text(Deposit)` | `= 6870.67-6250.67` |
`= $620` |
b. `text(Minimum Balance) = $6120.86`
`I` | `=Prn` |
`= 6120.86 xx 3/100 xx 1/12` | |
`= 15.302…` | |
`= $15.30` |
The transaction details for a savings account for the month of August 2014 are shown in the table below.
The table is incomplete.
Simple interest is calculated and paid monthly on the minimum balance for that month.
Calculate the annual simple interest rate paid on this account, correct to two decimal places. (4 marks)
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`text{3.75%}`
`text(Minimum balance for month) = $4870.50`
`text{Interest paid}\ = 5885.72-5870.50= $15.22`
`I` | `=Prn` |
`15.22` | `= 4870.50 xx r xx 1/12` |
`:. r` | `=(15.22 xx 12)/4870.50` |
`= 0.03749…` | |
`= 3.75text{% (2 d.p.)}` |
The graph below shows the growth in value of a $1000 investment over a period of four years.
A different amount of money is invested under the same investment conditions for eight years.
In total, the amount of interest earned on this investment is $600.
Calculate the amount of money invested. (3 marks)
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`$1500`
`text(The linear graph shows a simple interest rate is applied.)`
`text{Simple interest rate} = 50/1000 xx 100=5text(% p.a.)`
`I = 600,\ \ r = 5/100,\ \ n=8`
`600` | `= P xx 5/100 xx 8` |
`:.P` | `= 600/0.4` |
`= $1500` |
Chardie invests a sum of money in an account paying simple interest at a rate of 5.25% per annum.
No withdrawals or deposits are made into the account and over 4 years and the total value of Chardie's investment grows to `$22\ 385`.
Calculate the sum of money Chardie originally invested. (3 marks)
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`$18\ 500`
`text{Interest earned}\ = 22\ 385-18\ 500=$3885`
`I = 3885, \ \ r = 5.25/100, \ \ n = 4`
`I` | `= Prn` |
`3885` | `= P xx 5.25/100 xx 4` |
`P` | `= 3885/0.21` |
`= $18\ 500` |
A sum of money is invested in an account paying simple interest at a rate of 5.0% per annum.
No withdrawals or deposits are made into the account and over 3 years, with the total interest earned on the investment being $120.
Calculate the sum of money originally invested. (2 marks)
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`$800`
`I = 120, \ \ r = 5/100, \ \ n = 3`
`I` | `= Prn` |
`120` | `= P xx 5/100 xx 3` |
`P` | `= 120/0.15` |
`= $800` |
Wilbur invests a sum of money into an account paying simple interest at a rate of 4.25% per annum.
The total interest earned on Wilbur's investment over 4 years is $6800.
Calculate the sum of money Wilbur originally invested. (2 marks)
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`$40\ 000`
`I = 6800, \ \ r = 4.25/100, \ \ n = 4`
`I` | `= Prn` |
`6800` | `= P xx 4.25/100 xx 4` |
`P` | `= 6800/0.17` |
`= $40\ 000` |
A sum of money is invested in an account paying simple interest at a rate of 8% per annum.
The total interest earned on this investment over 6 years is $27 000.
The sum of money invested is
`C`
`I = 27 \ 000, \ \ r = 8/100, \ \ n = 6`
`I` | `= Prn` |
`27 \ 000` | `= (P xx 8 xx 6)/100` |
`P` | `= (2\ 700\ 000)/48` |
`= $56\ 250` |
`=> C`
Kate and Amberley are Swifties and want to travel to Melbourne to go to a Tay-Tay concert.
It will cost them a total of $13 000 for tickets, accommodation and transport.
They currently have $12 500 and can invest this amount for 9 months.
What is the minimum simple interest rate, correct to 1 decimal place, at which they can invest their money to reach their goal of $13 000? (3 marks)
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`5.4\text{%}`
`n = \frac {9}{12} = 0.75`
`text{Interest required to reach goal} =13\ 000-12\ 500=$500`
`I` | `=Prn` |
`500` | `=12\ 500 xx r xx 0.75` |
`r` | `=500/9375` |
`=0.05333…` | |
`=5.333…\text{%}` |
`:.\ text{Minimum interest rate = 5.4%}`
Carissa borrowed $4000 to buy new surfboards.
She did not make any monthly repayments and repaid the loan in full 2 years later with a lump sum of $4400.
Determine the annual simple interest rate that Carissa was charged. (2 marks)
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`5.0\text{%}`
`text(Total interest paid)=4400-4000=$400`
`I` | `=Prn` |
`400` | `=4000 xx r xx 2` |
`r` | `=400/8000` |
`=0.05` | |
`=5.0\text{%}` |
Steffi borrowed $8600 to buy a new car.
She did not make any monthly repayments but instead repaid the loan in full 2 years later with a lump sum of $10 062.
Determine the annual simple interest rate that Steffi was charged. (2 marks)
--- 5 WORK AREA LINES (style=lined) ---
`8.50\text{%}`
`text(Total interest paid)=10\ 062-8600=$1462`
`I` | `=Prn` |
`1462` | `=8600 xx r xx 2` |
`r` | `=1462/(17\ 200)` |
`=0.0850` | |
`=8.50\text{%}` |
$2800 is invested in an account that earns simple interest at the rate of 4.0% per annum.
Calculate the total interest earned in the first six months. (2 marks)
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`$56`
`P = 2800,\ \ r = 4.0text(%),\ \ n = \frac{6}{12}=0.5`
`I` | `= Prn` |
`= 2800 xx 4.0/100 xx 0.5` | |
`= $56` |
$5000 is invested in an account that earns simple interest at the rate of 3.0% per annum.
Calculate the total interest earned in the first two years. (2 marks)
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`$300`
`P = 5000,\ \ r = 3.0text(%),\ \ n = 2`
`I` | `= Prn` |
`= 5000 xx 3.0/100 xx 2` | |
`= $300` |
Find an expression for the total value of an investment, in dollars, if $24 000 is invested for `x` months at a simple interest rate of 4.75% per annum? (2 marks)
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`$(24\ 000 + 95x)`
`text(Interest)` | `= 24\ 000 xx x/12 xx 4.75/100` |
`= 95x` |
`:.\ \text{Investment value}\ =$(24\ 000 + 95x)`
What is the interest earned, in dollars, if $4800 is invested for `x` months at a simple interest rate of 2.25% per annum?
`A`
`text(Interest)` | `= 4800 xx x/12 xx 2.25/100` |
`= 9x` |
`=> A`
Albert borrowed $2000 off his brother Sid so he could attend the rugby league Magic Round in Brisbane.
He did not make any monthly repayments but instead repaid the loan in full 12 months later with a lump sum of $2350.
What was the annual simple interest rate Sid charged Albert?
`B`
`text(Total interest paid)=2350-2000=$350`
`I` | `=Prn` |
`350` | `=2000 xx r xx 1` |
`r` | `=350/2000` |
`=0.1750` | |
`=17.50\text{%}` |
`=> B`
Sandy borrowed $7 000 for an overseas trip.
She did not make any monthly repayments but instead repaid the loan in full at the end of three years with a lump sum of $8800.
Calculate the annual simple interest rate was she charged? (2 marks)
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`8.57\text{%}`
`text(Total interest paid)=8800-7000=$1800`
`I` | `=Prn` |
`1800` | `=7000 xx r xx 3` |
`r` | `=1800/(21\ 000)` |
`=0.08571…` | |
`=8.57\text{%}` |
Jackie invests $4350 for 3 years. The simple interest is calculated at a rate of 4.5% per annum.
What is the total value of the investment at the end of this period, to the nearest dollar?
`D`
`text(Interest)` | `=Prn` |
`=4350 xx \frac{4.5}{100} xx 3` | |
`=$587.25` |
`:.\ text(Value of Investment)=4350 + 587 =$4937`
`=> D`
Gutho invests $10 000 for 1 year and 8 months. The simple interest is calculated at a rate of 4.25% per annum.
What is the total value of the investment at the end of this period, to the nearest dollar?
`C`
`text{1 year 8 months = 12 + 8 = 20 months}`
`text(Interest)` | `=Prn` |
`=10\ 000 xx \frac{4.25}{100} xx \frac{20}{12}` | |
`=$708` |
`:.\ text(Value of Investment)=10\ 000+708=$10\ 708`
`=> C`
Johnno lives overseas and needs $6000 for his planned trip to Parramatta Stadium to watch Junior Paolo play.
If he invests $5600 for 15 months at a simple interest rate of 6.5% per annum, determine if will get to see the big fella play. Show your working. (2 marks)
--- 4 WORK AREA LINES (style=lined) ---
`text(Interest)` | `=Prn` |
`=5600 xx \frac{6.5}{100} xx \frac{15}{12}` | |
`=$455` |
`text(Value of Investment)` | `=5600+455` |
`=$6055>$6000` |
`:.\ \text{Johnno will get to see Junior play}.`
`text(Interest)` | `=Prn` |
`=5600 xx \frac{6.5}{100} xx \frac{15}{12}` | |
`=$455` |
`text(Value of Investment)` | `=5600+455` |
`=$6055` |
`:.\ \text{Johnno will get to see Junior play}.`
Clancy estimates that he will need $7800 for his planned trip to visit the The Stockman's Hall of Fame in Longreach.
If he invests $7000 for 18 months at a simple interest rate of 6% per annum, will he reach his goal of $7800? Show your working. (2 marks)
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`A`
`text(Interest)` | `=Prn` |
`=7000 xx \frac{6}{100} xx \frac{18}{12}` | |
`=$630` |
`text(Value of Investment)` | `=7000+630` |
`=$7630` |
`:.\ \text{Clancy won’t reach his goal of $7800}.`
Min Woo invests $8000 for 3 years. The simple interest is calculated at a rate of 4% per annum.
Calculate the total value of the investment at the end of this period. (2 marks)
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`$8960`
`text(Interest)` | `=Prn` |
`=8000 xx \frac{4}{100} xx 3` | |
`=$960` |
`:.\ text(Value of Investment)` | `=8000+960` |
`=$8960` |
$2500 is invested in an account that earns simple interest at the rate of 3.0% per annum.
The total interest earned in the first two years is
`C`
`P = 2500,\ \ r = 3.0text(%),\ \ n = 2`
`I` | `= Prn` |
`= 2500 xx 3.0/100 xx 2` | |
`= $150` |
`=> C`
$14 000 is invested in an account that earns simple interest at the rate of 2.5% per annum.
Calculate the total interest earned in the first three years. (2 marks)
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`$1050`
`P = 14\ 000,\ \ r = 2.5text(%),\ \ n = 3`
`I` | `= Prn` |
`= 14\ 000 xx 2.5/100 xx 3` | |
`= $1050` |
The cash price of a large refrigerator is $2000.
A customer buys the refrigerator under a hire-purchase agreement.
She does not pay a deposit and will pay $55 per month for four years.
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i. `text{Total amount paid} = 55 xx 4 xx 12 = $2640`
ii. `text{Total interest} = 2640-2000= $640`
Shaun decides to buy a new sound system on a hire-purchase plan.
The sound system is priced at $3500.
Shaun pays a 15% deposit and monthly repayments for five years.
If Shaun's total purchase price after paying the last instalment is $4425, calculate his monthly repayment. (3 marks)
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`$65`
`text{Deposit} = \frac{15}{100} xx 3500 = $525`
`text{Balance due after deposit} = 4425-525= $3900`
`text{Number of repayments} = 5 xx 12 = 60`
`text{Monthly repayment} = \frac{3900}{60} = $65`
Brad investigated the cost of buying a $720 washing machine under a hire purchase agreement.
A 25% deposit is required and the balance will be paid in 24 equal monthly repayments of $27.90.
Calculate the amount of interest Brad pays on this purchase. (3 marks)
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`$129.60`
`text{Deposit} = \dfrac{25}{100} xx 720 = $180`
`text{Total instalments} = 24 xx 27.90 = $669.60`
`text{Total purchase price} = 180+669.60 = $849.60`
`text{Interest paid} = 849.60-720= $129.60`
A $2000 lounge suite was sold under a hire-purchase agreement.
A deposit of $200 was paid.
The balance was to be paid in 36 equal monthly instalments of $68.
Calculate the total interest paid in the purchase. (3 marks)
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`$648`
`text{Deposit} = $200`
`text(Total instalments) = 36 xx 68 = $2448`
`text{Total price paid} = 200 + 2448 = $2648`
`text{Interest paid} = 2648-2000 = $648`