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Algebra, STD2 A2 EQ-Bank 10 MC

Leo drew a straight line through the points `(0, 5)` and `(3, -2)` as shown in the diagram below.
 

 
What is the gradient of the line that Leo drew?

  1. `7/3`
  2. `3/7`
  3. `-3/7`
  4. `-7/3`
Show Answers Only

`D`

Show Worked Solution

`text(Line passes through)\ (0, 5)\  \text(and)\ (3,-2):`

`text(Gradient)= \text{rise}/\text{run} = (5-(-2))/(0-3)= -7/3`

 `=>D`

Filed Under: Linear Equations and Basic Graphs (Std 1), Linear Equations and Basic Graphs (Std 2), Linear Modelling and Basic Graphs, Linear Modelling and Basic Graphs Tagged With: Band 4, smc-1118-10-Gradient, smc-6255-10-Find Gradient/Intercept, smc-6512-10-Find Gradient/Intercept, smc-792-10-Gradient

Algebra, STD2 A2 EQ-Bank 2 MC

What is the gradient of the line  `2x + 3y + 4 = 0`?

  1. `-2/3`
  2. `2/3`
  3. `-3/2`
  4. `3/2`
Show Answers Only

`A`

Show Worked Solution
`2x + 3y + 4` `= 0`
`3y` `= -2x-4`
`y` `= -2/3 x-4/3`

 
`=>  A`

Filed Under: Linear Equations and Basic Graphs (Std 1), Linear Equations and Basic Graphs (Std 2), Linear Modelling and Basic Graphs, Linear Modelling and Basic Graphs Tagged With: Band 3, smc-1118-10-Gradient, smc-6255-10-Find Gradient/Intercept, smc-6512-10-Find Gradient/Intercept, smc-792-10-Gradient

Algebra, STD2 A2 EQ-Bank 1 MC

What is the slope of the line with equation  `5x+2y-8 = 0`?

  1. `-5/2`
  2. `-2/5`
  3.  `2/5`
  4. `5/2`
Show Answers Only

`A`

Show Worked Solution
`5x+2y-8` `= 0`
`2y` `= -5x+8`
`y` `= -5/2 x+4`

 
`:.\ text(Slope)\ = -5/2`

`=>A`

Filed Under: Linear Equations and Basic Graphs (Std 1), Linear Equations and Basic Graphs (Std 2), Linear Modelling and Basic Graphs, Linear Modelling and Basic Graphs Tagged With: Band 3, smc-1118-10-Gradient, smc-6255-10-Find Gradient/Intercept, smc-6512-10-Find Gradient/Intercept, smc-792-10-Gradient

Algebra, STD2 A2 2004 HSC 2 MC

Susan drew a graph of the height of a plant.
  

What is the gradient of the line?

  1. `1`
  2. `5`
  3. `7.5`
  4. `10`
Show Answers Only

`B`

Show Worked Solution

`text(2 points on graph)\ \ (0, 10),\ (1, 15)`

`text(Gradient)` `= (y_2-y_1) / (x_2-x_1)`
  `= (15-10) / (1-0)`
  `= 5`

`=> B`

Filed Under: AM2 - Linear Relationships (Prelim), Cartesian Plane, Linear Equations and Basic Graphs (Std 1), Linear Equations and Basic Graphs (Std 2), Linear Modelling and Basic Graphs, Linear Modelling and Basic Graphs Tagged With: Band 3, num-title-ct-pathc, num-title-qs-hsc, smc-1118-10-Gradient, smc-4422-20-Gradient, smc-6255-10-Find Gradient/Intercept, smc-6512-10-Find Gradient/Intercept, smc-792-10-Gradient

Algebra, STD2 A2 2012 HSC 5 MC

The line  `l`  has intercepts  `p`  and  `q`,  where  `p`  and  `q`  are positive integers. 
  

What is the gradient of line  `l ` ? 

  1. `-p/q`  
  2. `-q/p`  
  3. `p/q`  
  4. `q/p`  
Show Answers Only

`A`

Show Worked Solution
 
♦ Mean mark 45%
`text(Gradient)` `= text(rise)/text(run)`
  `= -p/q`

`=>  A`

Filed Under: AM2 - Linear Relationships (Prelim), Cartesian Plane, Linear Equations and Basic Graphs (Std 1), Linear Equations and Basic Graphs (Std 2), Linear Modelling and Basic Graphs, Linear Modelling and Basic Graphs Tagged With: Band 5, num-title-ct-pathc, num-title-qs-hsc, smc-1118-10-Gradient, smc-4422-20-Gradient, smc-6255-10-Find Gradient/Intercept, smc-6512-10-Find Gradient/Intercept, smc-792-10-Gradient

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