SmarterEd

Aussie Maths & Science Teachers: Save your time with SmarterEd

  • Login
  • Get Help
  • About

Algebra, STD2 A2 EQ-Bank 10 MC

Leo drew a straight line through the points `(0, 5)` and `(3, -2)` as shown in the diagram below.
 

 
What is the gradient of the line that Leo drew?

  1. `7/3`
  2. `3/7`
  3. `-3/7`
  4. `-7/3`
Show Answers Only

`D`

Show Worked Solution

`text(Line passes through)\ (0, 5)\  \text(and)\ (3,-2):`

`text(Gradient)= \text{rise}/\text{run} = (5-(-2))/(0-3)= -7/3`

 `=>D`

Filed Under: Linear Equations and Basic Graphs, Linear Equations and Basic Graphs, Linear Modelling and Basic Graphs, Linear Modelling and Basic Graphs Tagged With: Band 4, smc-1118-10-Gradient, smc-6255-10-Find Gradient/Intercept, smc-6512-10-Find Gradient/Intercept, smc-792-10-Gradient

Algebra, STD2 A2 EQ-Bank 2 MC

What is the gradient of the line  `2x + 3y + 4 = 0`?

  1. `-2/3`
  2. `2/3`
  3. `-3/2`
  4. `3/2`
Show Answers Only

`A`

Show Worked Solution
`2x + 3y + 4` `= 0`
`3y` `= -2x-4`
`y` `= -2/3 x-4/3`

 
`=>  A`

Filed Under: Linear Equations and Basic Graphs, Linear Equations and Basic Graphs, Linear Modelling and Basic Graphs, Linear Modelling and Basic Graphs Tagged With: Band 3, smc-1118-10-Gradient, smc-6255-10-Find Gradient/Intercept, smc-6512-10-Find Gradient/Intercept, smc-792-10-Gradient

Algebra, STD2 A2 EQ-Bank 1 MC

What is the slope of the line with equation  `5x+2y-8 = 0`?

  1. `-5/2`
  2. `-2/5`
  3.  `2/5`
  4. `5/2`
Show Answers Only

`A`

Show Worked Solution
`5x+2y-8` `= 0`
`2y` `= -5x+8`
`y` `= -5/2 x+4`

 
`:.\ text(Slope)\ = -5/2`

`=>A`

Filed Under: Linear Equations and Basic Graphs, Linear Equations and Basic Graphs, Linear Modelling and Basic Graphs, Linear Modelling and Basic Graphs Tagged With: Band 3, smc-1118-10-Gradient, smc-6255-10-Find Gradient/Intercept, smc-6512-10-Find Gradient/Intercept, smc-792-10-Gradient

Algebra, STD2 A2 2004 HSC 2 MC

Susan drew a graph of the height of a plant.
  

What is the gradient of the line?

  1. `1`
  2. `5`
  3. `7.5`
  4. `10`
Show Answers Only

`B`

Show Worked Solution

`text(2 points on graph)\ \ (0, 10),\ (1, 15)`

`text(Gradient)` `= (y_2-y_1) / (x_2-x_1)`
  `= (15-10) / (1-0)`
  `= 5`

`=> B`

Filed Under: AM2 - Linear Relationships (Prelim), Cartesian Plane, Linear Equations and Basic Graphs, Linear Equations and Basic Graphs, Linear Modelling and Basic Graphs, Linear Modelling and Basic Graphs Tagged With: Band 3, num-title-ct-pathc, num-title-qs-hsc, smc-1118-10-Gradient, smc-4422-20-Gradient, smc-6255-10-Find Gradient/Intercept, smc-6512-10-Find Gradient/Intercept, smc-792-10-Gradient

Algebra, STD2 A2 2012 HSC 5 MC

The line  `l`  has intercepts  `p`  and  `q`,  where  `p`  and  `q`  are positive integers. 
  

What is the gradient of line  `l ` ? 

  1. `-p/q`  
  2. `-q/p`  
  3. `p/q`  
  4. `q/p`  
Show Answers Only

`A`

Show Worked Solution
 
♦ Mean mark 45%
`text(Gradient)` `= text(rise)/text(run)`
  `= -p/q`

`=>  A`

Filed Under: AM2 - Linear Relationships (Prelim), Cartesian Plane, Linear Equations and Basic Graphs, Linear Equations and Basic Graphs, Linear Modelling and Basic Graphs, Linear Modelling and Basic Graphs Tagged With: Band 5, num-title-ct-pathc, num-title-qs-hsc, smc-1118-10-Gradient, smc-4422-20-Gradient, smc-6255-10-Find Gradient/Intercept, smc-6512-10-Find Gradient/Intercept, smc-792-10-Gradient

Copyright © 2014–2026 SmarterEd.com.au · Log in